Hi Yharonkh,
Thanks a lot.
It really did the trick :)
Regards,
Mrio Gamito
[EMAIL PROTECTED] wrote:
Hi
Try using instead of '
Meaning you should write:
Print (a href =\http://www.dte.ua.pt/cv/email=?.$recordSet-fields[0]. \ br
/);
-Original Message-
From: Mrio Gamito [mailto:[EMAIL PROTECTED]
Sent: Monday, March 21, 2005 12:50 PM
To: php-general@lists.php.net
Subject: [PHP] Damn escaping... Grunf...
Hi,
I want this code to display peoples' names within an hyperlink.
I'm tired of trying different ways, read all about it in PHP's manual,
but i can't get it there.
You can visit http://www.dte.ua.pt/cv
In the rightmost column it is suposed to apear two name below Links,
but... it doen't, becuase i can't straight the escaping :(
Any help would be apreciated.
The code follows my signature.
Warm Regards,
Mrio Gamito
--
// select names to display in the right column
$recordSet = $conn-Execute('SELECT name FROM users');
while (!$recordSet-EOF) {
print ('a href=\'http://www.dte.ua.pt/cv/email=?' .
$recordSet-fields[0] . '\'' . 'br /');
$recordSet-MoveNext();
}
--
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