On 12 Feb 2012, at 18:51, Tim Streater wrote:
I have a function defined thus:
function my_func ($arg1, $arg2, $arg3, $arg4, $arg5, $arg6)
{
// code here
}
I call this with variously the first three arguments only, or all six, taking
care that if I call it with fewer arguments then I don't try to acces $arg4,
$arg5, or $arg6 (which is passed by reference, as is $arg1).
On my first attempt to execute this, I'm getting:
Missing argument 4 for my_func(), called in /path/to/source/file1.php at
line 556 and defined
in /path/to/source/file2.php at line 3
Is this because $arg6 is passed by reference? There is some reference to this
in the docs and the user notes but it's a little unclear. Or is there another
reason?
Optional arguments must be given a default value...
function my_func($arg1, $arg2, $arg3, $arg4 = null, $arg5 = null, $arg6 =
null)
Note that passing a default value by reference was not supported prior to PHP5.
All the relevant details are here: http://php.net/functions.arguments
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
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