Re: [PHP] adding a variable to a variable name
You are on the right track with the reasoning:
$unsetA = "level" . $i . "Name";
unset($$unsetA);
HTH
Bogdan
Tom Beidler wrote:
>I'm wondering if this can be done, and if so, what's the proper way to do
>it.
>
>For the current issue I'm trying to unset some variables with common names
>and I would like to step through them with a loop. Here's where I'm at to
>give you an idea but the code doesn't work.
>
>for ($i = 2; $i <= 4; $i++) {
>unset($level$iName);
>unset($level$iUrl);
>}
>
>so the code unsets
>
>unset($level2Name);
>unset($level2Url);
>unset($level3Name);
>unset($level3Url);
>unset($level4Name);
>unset($level4Url);
>
>I guess I could create a variable before the unset like so
>
>$unsetA = "level" . $i . "Name";
>
>but that seems cloogey.
>
>Thanks,
>Tom
>
>
>
>
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RE: [PHP] adding a variable to a variable name
> -Original Message-
> From: Tom Beidler [mailto:[EMAIL PROTECTED]]
> Sent: 03 July 2002 21:41
>
> For the current issue I'm trying to unset some variables with
> common names
> and I would like to step through them with a loop. Here's
> where I'm at to
> give you an idea but the code doesn't work.
>
> for ($i = 2; $i <= 4; $i++) {
> unset($level$iName);
> unset($level$iUrl);
> }
[...]
> I guess I could create a variable before the unset like so
>
> $unsetA = "level" . $i . "Name";
This does the trick:
unset(${"level${i}Name"});
> but that seems cloogey.
cloogey --> kludgy???
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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