Re: [PHP] how to write IF statement for login script

2005-03-23 Thread M. Sokolewicz 
Nick wrote:
Hi,
I have a login script which has worked fine in the past, however i need 
to change the IF statement.  Basically all i want it to do is verify 
that $squadnum variable is inbetween 1-98 or is 99.  I'm not even 
entirely sure if i need to use the ereg function and i dont think the 
1-98 bit is formatted correctly, any help would be much appreciated.

Heres the code i have so far:
if (ereg(1-98, $squadnum)) {  // users with id 1-98 should get sent to 
squad page
   header(Location: squad.php);
   }  else if(ereg(99, $squadnum)) {  // 99 is the id number of the 
site administrator
   header(Location: admin.php);
   }  else {
   header(Location: login.php);
   }

Thanks, Nick
how about a non regular-expression solution?
if($squadnum  0  $squadnum  99) {
header('Location: squad.php');
} elseif($squadnum == 99) {
header('Location: admin.php');
} else {
header('Location: login.php');
}
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Re: [PHP] how to write IF statement for login script

2005-03-23 Thread Nick 
Thanks, that seems to have worked.
M. Sokolewicz wrote:
Nick wrote:
Hi,
I have a login script which has worked fine in the past, however i 
need to change the IF statement.  Basically all i want it to do is 
verify that $squadnum variable is inbetween 1-98 or is 99.  I'm not 
even entirely sure if i need to use the ereg function and i dont 
think the 1-98 bit is formatted correctly, any help would be much 
appreciated.

Heres the code i have so far:
if (ereg(1-98, $squadnum)) {  // users with id 1-98 should get sent 
to squad page
   header(Location: squad.php);
   }  else if(ereg(99, $squadnum)) {  // 99 is the id number of the 
site administrator
   header(Location: admin.php);
   }  else {
   header(Location: login.php);
   }

Thanks, Nick
how about a non regular-expression solution?
if($squadnum  0  $squadnum  99) {
header('Location: squad.php');
} elseif($squadnum == 99) {
header('Location: admin.php');
} else {
header('Location: login.php');
}
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