Re: [PHP] variable functions: empty/isset/unset invalid?
> Thanks for the additional code, now I see what you are after. Sorry, I don't
> know the answer, other than using curly braces will fix the problem for
> empty(). Also, a User Contributed Note at
> http://www.php.net/manual/en/functions.php#functions.user-defined has this
> to say:
>
>
> there are tons of good uses for this sort of functionality. But it should be
> noted that this will not work with
> include()
> include_once()
> require()
> require_once()
>
> it's safe to assume that this is for safty.
>
These funtions are directives rather than normal php functions as the manual says.
I'm just guessing, maybe empty(), isset() and other variable-testing functions are
also directives with a function-syntax wrapper and this is the reason why PHP doesn't
find them as functions (not in the target-list :).
>
> Kirk
>
> > -Original Message-
> > From: Philip Olson [mailto:[EMAIL PROTECTED]]
> > Sent: Monday, May 07, 2001 11:45 AM
> > To: [EMAIL PROTECTED]
> > Subject: RE: [PHP] variable functions: empty/isset/unset invalid?
> >
> >
> >
> > I wish it were that easy. Also, I'm looking for words on WHY this
> > behavior exists.
> >
> > http://www.php.net/manual/en/functions.variable-functions.php
> >
> > >
> > // works
> > if (empty($var)) print '$var is empty';
> >
> > // works
> > $foo = 'is_string';
> > $var = 'abcdef';
> > if ($foo($var)) print '$var is a string';
> >
> > // works
> > $foo = 'strlen';
> > $var = 'abcdef';
> > if ($foo($var) > 5) print '$var is over 5 chars';
> >
> > // doesn't work : Fatal Error : Call to undefined function: empty()
> > // same with isset() and unset()
> > $foo = 'empty';
> > if ($foo($var)) print '$var is empty';
> >
> > ?>
> >
> > In otherwords, only these few functions aren't working as "variable
> > functions" but result in a "Fatal Error" instead. Why?
> >
> >
> > Regards,
> > Philip
> >
> > On Mon, 7 May 2001, Johnson, Kirk wrote:
> >
> > > Change the parens around $var to curly braces:
> > >
> > > if ($foo{$var}) print 'worked.';
> > >
> > > Kirk
>
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Re: [PHP] variable functions: empty/isset/unset invalid?
On Monday 07 May 2001 20:11, Johnson, Kirk wrote: > problem for empty(). Also, a User Contributed Note at > http://www.php.net/manual/en/functions.php#functions.user-defined has > this to say: > > > there are tons of good uses for this sort of functionality. But it > should be noted that this will not work with > include() > include_once() > require() > require_once() > > it's safe to assume that this is for safty. > But I see no reason why it shouldn't work with empty() and isset() (unset() might be justified perhaps). You should report it as bug, Philip. > > // doesn't work : Fatal Error : Call to undefined function: empty() > > // same with isset() and unset() > > $foo = 'empty'; > > if ($foo($var)) print '$var is empty'; > > > > ?> > > > > In otherwords, only these few functions aren't working as "variable > > functions" but result in a "Fatal Error" instead. Why? -- Christian Reiniger LGDC Webmaster (http://sunsite.dk/lgdc/) Error 032: Recursion error - see error 032 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] variable functions: empty/isset/unset invalid?
Though I didn't know about 'variable functions' when answered, this is exactly what I said.. Interesting :) >>$foo is a string not a PHP function which makes 'empty' a string and not a >>function/command. >> >>Am I missing something? >> >>oktay -Original Message- From: Philip Olson [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 2:43 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] variable functions: empty/isset/unset invalid? Solved. empty, isset and unset are not functions, they are language contructs, which results in the error. This makes sense, a workaround is creating functions like isEmpty (or something similar) and using them. I'll be submitting a future request soon ;) Thanks everyone, especially OpenSrc in #php regards, Philip > > > > > // works > > if (empty($var)) print '$var is empty'; > > > > // works > > $foo = 'is_string'; > > $var = 'abcdef'; > > if ($foo($var)) print '$var is a string'; > > > > // works > > $foo = 'strlen'; > > $var = 'abcdef'; > > if ($foo($var) > 5) print '$var is over 5 chars'; > > > > // doesn't work : Fatal Error : Call to undefined function: empty() > > // same with isset() and unset() > > $foo = 'empty'; > > if ($foo($var)) print '$var is empty'; > > > > ?> > > > > In otherwords, only these few functions aren't working as "variable > > functions" but result in a "Fatal Error" instead. Why? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] variable functions: empty/isset/unset invalid?
Solved. empty, isset and unset are not functions, they are language contructs, which results in the error. This makes sense, a workaround is creating functions like isEmpty (or something similar) and using them. I'll be submitting a future request soon ;) Thanks everyone, especially OpenSrc in #php regards, Philip > > > > > // works > > if (empty($var)) print '$var is empty'; > > > > // works > > $foo = 'is_string'; > > $var = 'abcdef'; > > if ($foo($var)) print '$var is a string'; > > > > // works > > $foo = 'strlen'; > > $var = 'abcdef'; > > if ($foo($var) > 5) print '$var is over 5 chars'; > > > > // doesn't work : Fatal Error : Call to undefined function: empty() > > // same with isset() and unset() > > $foo = 'empty'; > > if ($foo($var)) print '$var is empty'; > > > > ?> > > > > In otherwords, only these few functions aren't working as "variable > > functions" but result in a "Fatal Error" instead. Why? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] variable functions: empty/isset/unset invalid?
Thanks for the additional code, now I see what you are after. Sorry, I don't
know the answer, other than using curly braces will fix the problem for
empty(). Also, a User Contributed Note at
http://www.php.net/manual/en/functions.php#functions.user-defined has this
to say:
there are tons of good uses for this sort of functionality. But it should be
noted that this will not work with
include()
include_once()
require()
require_once()
it's safe to assume that this is for safty.
Kirk
> -Original Message-
> From: Philip Olson [mailto:[EMAIL PROTECTED]]
> Sent: Monday, May 07, 2001 11:45 AM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP] variable functions: empty/isset/unset invalid?
>
>
>
> I wish it were that easy. Also, I'm looking for words on WHY this
> behavior exists.
>
> http://www.php.net/manual/en/functions.variable-functions.php
>
>
> // works
> if (empty($var)) print '$var is empty';
>
> // works
> $foo = 'is_string';
> $var = 'abcdef';
> if ($foo($var)) print '$var is a string';
>
> // works
> $foo = 'strlen';
> $var = 'abcdef';
> if ($foo($var) > 5) print '$var is over 5 chars';
>
> // doesn't work : Fatal Error : Call to undefined function: empty()
> // same with isset() and unset()
> $foo = 'empty';
> if ($foo($var)) print '$var is empty';
>
> ?>
>
> In otherwords, only these few functions aren't working as "variable
> functions" but result in a "Fatal Error" instead. Why?
>
>
> Regards,
> Philip
>
> On Mon, 7 May 2001, Johnson, Kirk wrote:
>
> > Change the parens around $var to curly braces:
> >
> > if ($foo{$var}) print 'worked.';
> >
> > Kirk
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RE: [PHP] variable functions: empty/isset/unset invalid?
I wish it were that easy. Also, I'm looking for words on WHY this
behavior exists.
http://www.php.net/manual/en/functions.variable-functions.php
';
// works
$foo = 'is_string';
$var = 'abcdef';
if ($foo($var)) print '$var is a string';
// works
$foo = 'strlen';
$var = 'abcdef';
if ($foo($var) > 5) print '$var is over 5 chars';
// doesn't work : Fatal Error : Call to undefined function: empty()
// same with isset() and unset()
$foo = 'empty';
if ($foo($var)) print '$var is empty';
?>
In otherwords, only these few functions aren't working as "variable
functions" but result in a "Fatal Error" instead. Why?
Regards,
Philip
On Mon, 7 May 2001, Johnson, Kirk wrote:
> Change the parens around $var to curly braces:
>
> if ($foo{$var}) print 'worked.';
>
> Kirk
>
> > -Original Message-
> > From: Philip Olson [mailto:[EMAIL PROTECTED]]
> > Subject: [PHP] variable functions: empty/isset/unset invalid?
> >
> > This does not work as expected (as I expect it at least) and gives the
> > following error. This seems to result with use of empty(),
> > isset(), and
> > unset(), perhaps others :
> >
> > Call to undefined function: empty()
> >
> > When using :
> >
> > $foo = 'empty';
> > if ($foo($var)) print 'worked.';
>
>
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> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
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RE: [PHP] variable functions: empty/isset/unset invalid?
Change the parens around $var to curly braces:
if ($foo{$var}) print 'worked.';
Kirk
> -Original Message-
> From: Philip Olson [mailto:[EMAIL PROTECTED]]
> Subject: [PHP] variable functions: empty/isset/unset invalid?
>
> This does not work as expected (as I expect it at least) and gives the
> following error. This seems to result with use of empty(),
> isset(), and
> unset(), perhaps others :
>
> Call to undefined function: empty()
>
> When using :
>
> $foo = 'empty';
> if ($foo($var)) print 'worked.';
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To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] variable functions: empty/isset/unset invalid?
$foo is a string not a PHP function which makes 'empty' a string and not a function/command. Am I missing something? oktay -Original Message- From: Philip Olson [mailto:[EMAIL PROTECTED]] Sent: Monday, May 07, 2001 1:04 PM To: [EMAIL PROTECTED] Subject: [PHP] variable functions: empty/isset/unset invalid? This does not work as expected (as I expect it at least) and gives the following error. This seems to result with use of empty(), isset(), and unset(), perhaps others : Call to undefined function: empty() When using : $foo = 'empty'; if ($foo($var)) print 'worked.'; Of course the following works as expected. if (empty($var)) print 'worked.'; And with other functions : $foo = 'somefunction'; if ($foo($var)) print 'worked.'; Why won't variable functions work with empty/isset/unset this way? And why the 'undefined function' fatal error? regards, philip -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
