Re: [Proto-Scripty] Re: Effect.multiple and toggle
On 20 July 2010 23:37, Febo ilpuccio.f...@gmail.com wrote:
Thanks Richard and Ralph,
I'm studing the code but my feeling is that Effect.toggle can't handle
the Object which is always passed by Effect.multiple as last parameter
or let's say effect.
I don't know very much JavaScript, so I came up with this solution.
I added a funciton to public/javascripts/prototype.js
Toggle: function(element, options) {
element = $(element);
effect = ($(options)['effect'] || 'appear').toLowerCase();
Effect.toggle(element, effect, options);
}
calling the multiple function:
Effect.multiple(['id_1','id_2',...,'id_n'], Effect.Toggle,
{'effect':'appear'})
I tested the curry but without success, perhaps I'm not so good in JS
so I didn't catch the concept of curry.
If you have a better solution, let me know.
The problem with the class solution is that I have a table and I want
to hide some rows of this table, I set the class of each row to odd/
even for zebra colouring.
On 20 Lug, 19:08, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 17:59, Ralph Brickley i...@topsoftweb.com wrote:
This is a revelation to me. I didn't know Effect had a multiple. Also,
what is curry?
My solution has been to tag those elements with a class, ie div
class=effects
Then use $$('effects') to get each item and all effects... On each
Sent from my iPhone
On Jul 20, 2010, at 9:08 AM, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 15:55, Febo ilpuccio.f...@gmail.com wrote:
Hello,
I'd like to use the toggle effect on multiple object at the same time
I tried with
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle)
but it doesn't work, also I don't know where/how to pass the 'appear'
parameter
I'm used to call toggle in this way:
Effect.toggle('my_id_of_interest','appear')
At a guess, you need to curry() [1] the parameter.
So, can you try ...
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle.curry('appear'));
Regards,
Richard.
[1]http://api.prototypejs.org/language/function/prototype/curry/
Curries (burns in) arguments to a function, returning a new function
that when called with call the original passing in the curried
arguments (along with any new ones)
The linkhttp://api.prototypejs.org/language/function/prototype/curry/
is the documentation for curry.
So, Effect.toggle.curry('appear') returns a new function which, when
called, will call the Effect.toggle function with 'appear' as the
first parameter, along with any other parameters supplied by the
Effect.multiple() function.
Is it the same as $$('effects').invoke('toggle', 'appear');
Hmm. On the surface, probably yes. But I'm not an expert here.
One difference is that Effect.multiple allows you to supply any ids.
I suppose ...
Effect.multiple($$('effects'), Effect.toggle.curry('appear'));
could also be a similar approach.
Ah. Yes. toggle requires the element first. Using curry() puts the
parameters the wrong way round.
Sorry about that.
So...
Effect.multiple
(
['id1', 'id2'],
function(el) { Effect.toggle(el, 'appear');}
);
maybe.
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Re: [Proto-Scripty] Re: Effect.multiple and toggle
On 21 July 2010 13:10, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 23:37, Febo ilpuccio.f...@gmail.com wrote:
Thanks Richard and Ralph,
I'm studing the code but my feeling is that Effect.toggle can't handle
the Object which is always passed by Effect.multiple as last parameter
or let's say effect.
I don't know very much JavaScript, so I came up with this solution.
I added a funciton to public/javascripts/prototype.js
Toggle: function(element, options) {
element = $(element);
effect = ($(options)['effect'] || 'appear').toLowerCase();
Effect.toggle(element, effect, options);
}
calling the multiple function:
Effect.multiple(['id_1','id_2',...,'id_n'], Effect.Toggle,
{'effect':'appear'})
I tested the curry but without success, perhaps I'm not so good in JS
so I didn't catch the concept of curry.
If you have a better solution, let me know.
The problem with the class solution is that I have a table and I want
to hide some rows of this table, I set the class of each row to odd/
even for zebra colouring.
On 20 Lug, 19:08, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 17:59, Ralph Brickley i...@topsoftweb.com wrote:
This is a revelation to me. I didn't know Effect had a multiple. Also,
what is curry?
My solution has been to tag those elements with a class, ie div
class=effects
Then use $$('effects') to get each item and all effects... On each
Sent from my iPhone
On Jul 20, 2010, at 9:08 AM, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 15:55, Febo ilpuccio.f...@gmail.com wrote:
Hello,
I'd like to use the toggle effect on multiple object at the same time
I tried with
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle)
but it doesn't work, also I don't know where/how to pass the 'appear'
parameter
I'm used to call toggle in this way:
Effect.toggle('my_id_of_interest','appear')
At a guess, you need to curry() [1] the parameter.
So, can you try ...
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle.curry('appear'));
Regards,
Richard.
[1]http://api.prototypejs.org/language/function/prototype/curry/
Curries (burns in) arguments to a function, returning a new function
that when called with call the original passing in the curried
arguments (along with any new ones)
The linkhttp://api.prototypejs.org/language/function/prototype/curry/
is the documentation for curry.
So, Effect.toggle.curry('appear') returns a new function which, when
called, will call the Effect.toggle function with 'appear' as the
first parameter, along with any other parameters supplied by the
Effect.multiple() function.
Is it the same as $$('effects').invoke('toggle', 'appear');
Hmm. On the surface, probably yes. But I'm not an expert here.
One difference is that Effect.multiple allows you to supply any ids.
I suppose ...
Effect.multiple($$('effects'), Effect.toggle.curry('appear'));
could also be a similar approach.
Ah. Yes. toggle requires the element first. Using curry() puts the
parameters the wrong way round.
Sorry about that.
So...
Effect.multiple
(
['id1', 'id2'],
function(el) { Effect.toggle(el, 'appear');}
);
maybe.
On http://script.aculo.us/, opening the console command line (using
Google Chrome).
Entered
Effect.multiple(['header','ninja'],function(el){Effect.toggle(el, 'appear');})
and the 2 elements fade out.
Repeat the all and they fade back in.
So this looks like a winner.
In essence the curry() call was doing ...
Effect.multiple(['header','ninja'],function(el){Effect.toggle('appear',el);})
which is why it wasn't working for you. Sorry again.
Regards,
Richard.
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[Proto-Scripty] Re: Effect.multiple and toggle
Dear Richard,
amazing :-)
thanks a lot.
They should update the wiki with this tip.
On 21 Lug, 14:23, Richard Quadling rquadl...@gmail.com wrote:
On 21 July 2010 13:10, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 23:37, Febo ilpuccio.f...@gmail.com wrote:
Thanks Richard and Ralph,
I'm studing the code but my feeling is that Effect.toggle can't handle
the Object which is always passed by Effect.multiple as last parameter
or let's say effect.
I don't know very much JavaScript, so I came up with this solution.
I added a funciton to public/javascripts/prototype.js
Toggle: function(element, options) {
element = $(element);
effect = ($(options)['effect'] || 'appear').toLowerCase();
Effect.toggle(element, effect, options);
}
calling the multiple function:
Effect.multiple(['id_1','id_2',...,'id_n'], Effect.Toggle,
{'effect':'appear'})
I tested the curry but without success, perhaps I'm not so good in JS
so I didn't catch the concept of curry.
If you have a better solution, let me know.
The problem with the class solution is that I have a table and I want
to hide some rows of this table, I set the class of each row to odd/
even for zebra colouring.
On 20 Lug, 19:08, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 17:59, Ralph Brickley i...@topsoftweb.com wrote:
This is a revelation to me. I didn't know Effect had a multiple. Also,
what is curry?
My solution has been to tag those elements with a class, ie div
class=effects
Then use $$('effects') to get each item and all effects... On each
Sent from my iPhone
On Jul 20, 2010, at 9:08 AM, Richard Quadling rquadl...@gmail.com
wrote:
On 20 July 2010 15:55, Febo ilpuccio.f...@gmail.com wrote:
Hello,
I'd like to use the toggle effect on multiple object at the same time
I tried with
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle)
but it doesn't work, also I don't know where/how to pass the 'appear'
parameter
I'm used to call toggle in this way:
Effect.toggle('my_id_of_interest','appear')
At a guess, you need to curry() [1] the parameter.
So, can you try ...
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle.curry('appear'));
Regards,
Richard.
[1]http://api.prototypejs.org/language/function/prototype/curry/
Curries (burns in) arguments to a function, returning a new function
that when called with call the original passing in the curried
arguments (along with any new ones)
The linkhttp://api.prototypejs.org/language/function/prototype/curry/
is the documentation for curry.
So, Effect.toggle.curry('appear') returns a new function which, when
called, will call the Effect.toggle function with 'appear' as the
first parameter, along with any other parameters supplied by the
Effect.multiple() function.
Is it the same as $$('effects').invoke('toggle', 'appear');
Hmm. On the surface, probably yes. But I'm not an expert here.
One difference is that Effect.multiple allows you to supply any ids.
I suppose ...
Effect.multiple($$('effects'), Effect.toggle.curry('appear'));
could also be a similar approach.
Ah. Yes. toggle requires the element first. Using curry() puts the
parameters the wrong way round.
Sorry about that.
So...
Effect.multiple
(
['id1', 'id2'],
function(el) { Effect.toggle(el, 'appear');}
);
maybe.
Onhttp://script.aculo.us/, opening the console command line (using
Google Chrome).
Entered
Effect.multiple(['header','ninja'],function(el){Effect.toggle(el, 'appear');})
and the 2 elements fade out.
Repeat the all and they fade back in.
So this looks like a winner.
In essence the curry() call was doing ...
Effect.multiple(['header','ninja'],function(el){Effect.toggle('appear',el);})
which is why it wasn't working for you. Sorry again.
Regards,
Richard.
--
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[Proto-Scripty] Re: Effect.multiple and toggle
Thanks Richard and Ralph,
I'm studing the code but my feeling is that Effect.toggle can't handle
the Object which is always passed by Effect.multiple as last parameter
or let's say effect.
I don't know very much JavaScript, so I came up with this solution.
I added a funciton to public/javascripts/prototype.js
Toggle: function(element, options) {
element = $(element);
effect = ($(options)['effect'] || 'appear').toLowerCase();
Effect.toggle(element, effect, options);
}
calling the multiple function:
Effect.multiple(['id_1','id_2',...,'id_n'], Effect.Toggle,
{'effect':'appear'})
I tested the curry but without success, perhaps I'm not so good in JS
so I didn't catch the concept of curry.
If you have a better solution, let me know.
The problem with the class solution is that I have a table and I want
to hide some rows of this table, I set the class of each row to odd/
even for zebra colouring.
On 20 Lug, 19:08, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 17:59, Ralph Brickley i...@topsoftweb.com wrote:
This is a revelation to me. I didn't know Effect had a multiple. Also, what
is curry?
My solution has been to tag those elements with a class, ie div
class=effects
Then use $$('effects') to get each item and all effects... On each
Sent from my iPhone
On Jul 20, 2010, at 9:08 AM, Richard Quadling rquadl...@gmail.com wrote:
On 20 July 2010 15:55, Febo ilpuccio.f...@gmail.com wrote:
Hello,
I'd like to use the toggle effect on multiple object at the same time
I tried with
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle)
but it doesn't work, also I don't know where/how to pass the 'appear'
parameter
I'm used to call toggle in this way:
Effect.toggle('my_id_of_interest','appear')
At a guess, you need to curry() [1] the parameter.
So, can you try ...
Effect.multiple(['id_1','id_2','id_n'], Effect.toggle.curry('appear'));
Regards,
Richard.
[1]http://api.prototypejs.org/language/function/prototype/curry/
Curries (burns in) arguments to a function, returning a new function
that when called with call the original passing in the curried
arguments (along with any new ones)
The linkhttp://api.prototypejs.org/language/function/prototype/curry/
is the documentation for curry.
So, Effect.toggle.curry('appear') returns a new function which, when
called, will call the Effect.toggle function with 'appear' as the
first parameter, along with any other parameters supplied by the
Effect.multiple() function.
Is it the same as $$('effects').invoke('toggle', 'appear');
Hmm. On the surface, probably yes. But I'm not an expert here.
One difference is that Effect.multiple allows you to supply any ids.
I suppose ...
Effect.multiple($$('effects'), Effect.toggle.curry('appear'));
could also be a similar approach.
--
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