[Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
2009/7/26 Alex McAuley webmas...@thecarmarketplace.com:
php's json_encode/decode functions... you may need to install them.
Good luck
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: geoffcox75 g...@freeuk.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 6:23 PM
Subject: [Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
On Jul 26, 5:26 pm, Alex McAuley webmas...@thecarmarketplace.com
wrote:
because its being sent as an array.. php cannot directly read javascript
arrays and as such you have to json encode/decode it
Thanks Alex - I have not so far used json - can you suggest a good
site for help on this? Simple, sample code would be very helpful to
help me get started.
Cheers,
Geoff
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: geoffcox g...@freeuk.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 5:22 PM
Subject: [Proto-Scripty] what causes this? prototype/javascript/php ?!
Hello,
I am not clear where the problem is with this situation.
The html/javascript used Ajax.Updater to send data to a php file which
inserts the data into mysql.
Oddly, to me ay any rate, print_r($_POST) and echo give different
results with chrome/safari and firefox.
With firefox I get the extra empty element and would like to know why.
Cheers,
Geoff
1. with chrome/safari I get
(a) print_r($_POST) gives
Array ( [firstnum] = 1 [lastnum] = 3 [groupname] = test [usercode]
= A1 [mysql_p11] = 10 [mysql_p12] = 20 [mysql_p13] = 30 [_] = )
(b) echo gives
'test',
'test','A1',
'test','A1','10',
'test','A1','10','20',
'test','A1','10','20','30',
'test','A1','10','20','30','',
2. with Firefox/IE the [_] = and the '', are not present.
3. The Javascript code
script type=text/javascript
var startValue = 1;
var endValue = 3;
var p1 = [];
var group = test;
var code_given = A1;
var params = {};
params[firstnum] = startValue;
params[lastnum] = endValue;
params[groupname] = group;
params[usercode] = code_given;
p1[1] = 10;
p1[2] = 20;
p1[3] = 30;
for (i=startValue;i(endValue+1);i++) {
params[mysql_p1 + i] = p1[i];
}
new Ajax.Updater(
'updateDiv',
'fv-p1-arrays4-mysql-test.php',
{
asynchronous:true,
method:'post',
parameters: params
}
);
/script
JSON Is now built into PHP as standard as of V5.3.0. Prior to that you
would have to either include the pre-built library (Windows) or
rebuild PHP (non-windows).
The '_' comes from Prototype and is a requirement for some reason. Not
exactly sure why, but you can ignore it in PHP.
What are you echo-ing to get the list you see?
If you want mysql_p1 as an array in PHP, try changing ...
params[mysql_p1 + i] = p1[i];
to
params['mysql_p1[' + i + ']'] = p1[i];
Regards,
Richard.
--
-
Richard Quadling
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731
Standing on the shoulders of some very clever giants!
ZOPA : http://uk.zopa.com/member/RQuadling
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[Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
because its being sent as an array.. php cannot directly read javascript
arrays and as such you have to json encode/decode it
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: geoffcox g...@freeuk.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 5:22 PM
Subject: [Proto-Scripty] what causes this? prototype/javascript/php ?!
Hello,
I am not clear where the problem is with this situation.
The html/javascript used Ajax.Updater to send data to a php file which
inserts the data into mysql.
Oddly, to me ay any rate, print_r($_POST) and echo give different
results with chrome/safari and firefox.
With firefox I get the extra empty element and would like to know why.
Cheers,
Geoff
1. with chrome/safari I get
(a) print_r($_POST) gives
Array ( [firstnum] = 1 [lastnum] = 3 [groupname] = test [usercode]
= A1 [mysql_p11] = 10 [mysql_p12] = 20 [mysql_p13] = 30 [_] = )
(b) echo gives
'test',
'test','A1',
'test','A1','10',
'test','A1','10','20',
'test','A1','10','20','30',
'test','A1','10','20','30','',
2. with Firefox/IE the [_] = and the '', are not present.
3. The Javascript code
script type=text/javascript
var startValue = 1;
var endValue = 3;
var p1 = [];
var group = test;
var code_given = A1;
var params = {};
params[firstnum] = startValue;
params[lastnum] = endValue;
params[groupname] = group;
params[usercode] = code_given;
p1[1] = 10;
p1[2] = 20;
p1[3] = 30;
for (i=startValue;i(endValue+1);i++) {
params[mysql_p1 + i] = p1[i];
}
new Ajax.Updater(
'updateDiv',
'fv-p1-arrays4-mysql-test.php',
{
asynchronous:true,
method:'post',
parameters: params
}
);
/script
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[Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
On Jul 26, 5:26 pm, Alex McAuley webmas...@thecarmarketplace.com
wrote:
because its being sent as an array.. php cannot directly read javascript
arrays and as such you have to json encode/decode it
Thanks Alex - I have not so far used json - can you suggest a good
site for help on this? Simple, sample code would be very helpful to
help me get started.
Cheers,
Geoff
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: geoffcox g...@freeuk.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 5:22 PM
Subject: [Proto-Scripty] what causes this? prototype/javascript/php ?!
Hello,
I am not clear where the problem is with this situation.
The html/javascript used Ajax.Updater to send data to a php file which
inserts the data into mysql.
Oddly, to me ay any rate, print_r($_POST) and echo give different
results with chrome/safari and firefox.
With firefox I get the extra empty element and would like to know why.
Cheers,
Geoff
1. with chrome/safari I get
(a) print_r($_POST) gives
Array ( [firstnum] = 1 [lastnum] = 3 [groupname] = test [usercode]
= A1 [mysql_p11] = 10 [mysql_p12] = 20 [mysql_p13] = 30 [_] = )
(b) echo gives
'test',
'test','A1',
'test','A1','10',
'test','A1','10','20',
'test','A1','10','20','30',
'test','A1','10','20','30','',
2. with Firefox/IE the [_] = and the '', are not present.
3. The Javascript code
script type=text/javascript
var startValue = 1;
var endValue = 3;
var p1 = [];
var group = test;
var code_given = A1;
var params = {};
params[firstnum] = startValue;
params[lastnum] = endValue;
params[groupname] = group;
params[usercode] = code_given;
p1[1] = 10;
p1[2] = 20;
p1[3] = 30;
for (i=startValue;i(endValue+1);i++) {
params[mysql_p1 + i] = p1[i];
}
new Ajax.Updater(
'updateDiv',
'fv-p1-arrays4-mysql-test.php',
{
asynchronous:true,
method:'post',
parameters: params
}
);
/script
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[Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
php's json_encode/decode functions... you may need to install them.
Good luck
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: geoffcox75 g...@freeuk.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 6:23 PM
Subject: [Proto-Scripty] Re: what causes this? prototype/javascript/php ?!
On Jul 26, 5:26 pm, Alex McAuley webmas...@thecarmarketplace.com
wrote:
because its being sent as an array.. php cannot directly read javascript
arrays and as such you have to json encode/decode it
Thanks Alex - I have not so far used json - can you suggest a good
site for help on this? Simple, sample code would be very helpful to
help me get started.
Cheers,
Geoff
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: geoffcox g...@freeuk.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Sunday, July 26, 2009 5:22 PM
Subject: [Proto-Scripty] what causes this? prototype/javascript/php ?!
Hello,
I am not clear where the problem is with this situation.
The html/javascript used Ajax.Updater to send data to a php file which
inserts the data into mysql.
Oddly, to me ay any rate, print_r($_POST) and echo give different
results with chrome/safari and firefox.
With firefox I get the extra empty element and would like to know why.
Cheers,
Geoff
1. with chrome/safari I get
(a) print_r($_POST) gives
Array ( [firstnum] = 1 [lastnum] = 3 [groupname] = test [usercode]
= A1 [mysql_p11] = 10 [mysql_p12] = 20 [mysql_p13] = 30 [_] = )
(b) echo gives
'test',
'test','A1',
'test','A1','10',
'test','A1','10','20',
'test','A1','10','20','30',
'test','A1','10','20','30','',
2. with Firefox/IE the [_] = and the '', are not present.
3. The Javascript code
script type=text/javascript
var startValue = 1;
var endValue = 3;
var p1 = [];
var group = test;
var code_given = A1;
var params = {};
params[firstnum] = startValue;
params[lastnum] = endValue;
params[groupname] = group;
params[usercode] = code_given;
p1[1] = 10;
p1[2] = 20;
p1[3] = 30;
for (i=startValue;i(endValue+1);i++) {
params[mysql_p1 + i] = p1[i];
}
new Ajax.Updater(
'updateDiv',
'fv-p1-arrays4-mysql-test.php',
{
asynchronous:true,
method:'post',
parameters: params
}
);
/script
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