[Puppet Users] Re: replacing mkdir -p

2013-04-09 Thread Klavs Klavsen
pls. post if you upload it to the forge or somewhere else.. would 
definetely be interested in getting rid of mkdir -p :)

Den tirsdag den 9. april 2013 18.56.33 UTC+2 skrev Mike Power:
>
> I'll see if I can open source the component I wrote and upload it to 
> puppet forge.  In this way the open source community can continue the 
> debate about what is the best way to do this, while at the same time those 
> who want can use some solution other than mkdir -p
>

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[Puppet Users] Re: replacing mkdir -p

2013-04-09 Thread Mike Power
I'll see if I can open source the component I wrote and upload it to puppet 
forge.  In this way the open source community can continue the debate about 
what is the best way to do this, while at the same time those who want can 
use some solution other than mkdir -p

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Re: [Puppet Users] Re: replacing mkdir -p

2013-04-08 Thread Tony C
I have the same issue, I basically create an array, that way it cuts it 
down to one FILE, and not the same thing over and over again.


file { ["/blah", "/blah/blah", "/blah/blah/blah", "/blah/blah/blah/blah", 
"/blah/blah/blah/blah/blah"]:
ensure => directory,
owner => "blah",
group => "blah",
mode => 0700,
}

On Monday, April 8, 2013 1:27:11 PM UTC-7, Luca Gioppo wrote:
>
> Can you post a complete example please?
> Thanks
> Luca
>
>
> 2013/4/4 Mike Power >
>
>> Actually I found if I created a resource between path and file called 
>> element, I could give it a unique name.  Then inside the body I could check 
>> to see if the File is declared, if not I could declare it.  
>>
>> On Thursday, April 4, 2013 9:23:54 AM UTC-7, Mike Power wrote:
>>>
>>> Puppet right now requires every element of a path to have an individual 
>>> file definition.  This makes it had to take an arbitrary path as a 
>>> parameter.  You are forced to require your client to make the entire path 
>>> structure for you or instead you use an exec resource and call mkdir -p.  
>>> Using an exec resource does not generate an File resources so autorequire 
>>> does not work.
>>>
>>> I didn't like this, I wanted to be able to once specify a path and have 
>>> puppet do that autorequire as needed.
>>>
>>> Something like:
>>> path {"/blah/blah/blah/and/blah":
>>> }
>>>
>>>
>>> In order to make this happen I would have to manually define each file:
>>> file {"/blah/":
>>> ensure  => directory,
>>> }
>>>
>>> file {"/blah/blah/":
>>> ensure  => directory,
>>> }
>>>
>>> file {"/blah/blah/blah/":
>>> ensure  => directory,
>>> }
>>>
>>> file {"/blah/blah/blah/and/":
>>> ensure  => directory,
>>> }
>>>
>>> file {"/blah/blah/blah/and/blah/":
>>> ensure  => directory,
>>> }
>>>
>>> Of course there is a short hand for this:
>>> file {["/blah/", "/blah/blah/", "/blah/blah/blah/", 
>>> "/blah/blah/blah/and/","/blah/**blah/blah/and/blah/"]:
>>> ensure  => directory,
>>> }
>>>
>>> Then it occurred to me I could parse the path and produce the array of 
>>> elements needed.  Something like:
>>> $path = "/blah/blah/blah/and/blah"
>>> $file_list = split($path, $file_separator)
>>> $paths = inline_template('<% parent = nil %><%=@file_list.collect{ 
>>> |file| parent.nil? ? parent = "#{@file_separator}":parent = 
>>> "#{parent}#{file}#{@file_**separator}"}.join(@path_**separator) %>')
>>> $path_list = split($paths, $path_separator)
>>> file{$path_list:
>>> ensure  => directory,
>>> }
>>>
>>> This works great once.  Then you get errors like:
>>> Error: Duplicate declaration: File[/]
>>>
>>> If there anyway to trim down the produced array by removing the 
>>> resources that already exist?
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>  -- 
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>>  
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>
>

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Re: [Puppet Users] Re: replacing mkdir -p

2013-04-08 Thread Luca Gioppo
Can you post a complete example please?
Thanks
Luca


2013/4/4 Mike Power 

> Actually I found if I created a resource between path and file called
> element, I could give it a unique name.  Then inside the body I could check
> to see if the File is declared, if not I could declare it.
>
> On Thursday, April 4, 2013 9:23:54 AM UTC-7, Mike Power wrote:
>>
>> Puppet right now requires every element of a path to have an individual
>> file definition.  This makes it had to take an arbitrary path as a
>> parameter.  You are forced to require your client to make the entire path
>> structure for you or instead you use an exec resource and call mkdir -p.
>> Using an exec resource does not generate an File resources so autorequire
>> does not work.
>>
>> I didn't like this, I wanted to be able to once specify a path and have
>> puppet do that autorequire as needed.
>>
>> Something like:
>> path {"/blah/blah/blah/and/blah":
>> }
>>
>>
>> In order to make this happen I would have to manually define each file:
>> file {"/blah/":
>> ensure  => directory,
>> }
>>
>> file {"/blah/blah/":
>> ensure  => directory,
>> }
>>
>> file {"/blah/blah/blah/":
>> ensure  => directory,
>> }
>>
>> file {"/blah/blah/blah/and/":
>> ensure  => directory,
>> }
>>
>> file {"/blah/blah/blah/and/blah/":
>> ensure  => directory,
>> }
>>
>> Of course there is a short hand for this:
>> file {["/blah/", "/blah/blah/", "/blah/blah/blah/",
>> "/blah/blah/blah/and/","/blah/**blah/blah/and/blah/"]:
>> ensure  => directory,
>> }
>>
>> Then it occurred to me I could parse the path and produce the array of
>> elements needed.  Something like:
>> $path = "/blah/blah/blah/and/blah"
>> $file_list = split($path, $file_separator)
>> $paths = inline_template('<% parent = nil %><%=@file_list.collect{
>> |file| parent.nil? ? parent = "#{@file_separator}":parent =
>> "#{parent}#{file}#{@file_**separator}"}.join(@path_**separator) %>')
>> $path_list = split($paths, $path_separator)
>> file{$path_list:
>> ensure  => directory,
>> }
>>
>> This works great once.  Then you get errors like:
>> Error: Duplicate declaration: File[/]
>>
>> If there anyway to trim down the produced array by removing the resources
>> that already exist?
>>
>>
>>
>>
>>
>>
>>
>>  --
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[Puppet Users] Re: replacing mkdir -p

2013-04-04 Thread Mike Power
Actually I found if I created a resource between path and file called 
element, I could give it a unique name.  Then inside the body I could check 
to see if the File is declared, if not I could declare it.  

On Thursday, April 4, 2013 9:23:54 AM UTC-7, Mike Power wrote:
>
> Puppet right now requires every element of a path to have an individual 
> file definition.  This makes it had to take an arbitrary path as a 
> parameter.  You are forced to require your client to make the entire path 
> structure for you or instead you use an exec resource and call mkdir -p.  
> Using an exec resource does not generate an File resources so autorequire 
> does not work.
>
> I didn't like this, I wanted to be able to once specify a path and have 
> puppet do that autorequire as needed.
>
> Something like:
> path {"/blah/blah/blah/and/blah":
> }
>
>
> In order to make this happen I would have to manually define each file:
> file {"/blah/":
> ensure  => directory,
> }
>
> file {"/blah/blah/":
> ensure  => directory,
> }
>
> file {"/blah/blah/blah/":
> ensure  => directory,
> }
>
> file {"/blah/blah/blah/and/":
> ensure  => directory,
> }
>
> file {"/blah/blah/blah/and/blah/":
> ensure  => directory,
> }
>
> Of course there is a short hand for this:
> file {["/blah/", "/blah/blah/", "/blah/blah/blah/", 
> "/blah/blah/blah/and/","/blah/blah/blah/and/blah/"]:
> ensure  => directory,
> }
>
> Then it occurred to me I could parse the path and produce the array of 
> elements needed.  Something like:
> $path = "/blah/blah/blah/and/blah"
> $file_list = split($path, $file_separator)
> $paths = inline_template('<% parent = nil %><%=@file_list.collect{ 
> |file| parent.nil? ? parent = "#{@file_separator}":parent = 
> "#{parent}#{file}#{@file_separator}"}.join(@path_separator) %>')
> $path_list = split($paths, $path_separator)
> file{$path_list:
> ensure  => directory,
> }
>
> This works great once.  Then you get errors like:
> Error: Duplicate declaration: File[/]
>
> If there anyway to trim down the produced array by removing the resources 
> that already exist?
>
>
>
>
>
>
>
>

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