Re: [pygtk] GTK_IS_WIDGET on subclass of a widget fails
Kelvin Ho wrote: > Have a look at this: > > http://fuhm.net/super-harmful/ > > ;) > Interesting...so what can _I_ do then? This seems like a problem above me... ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/
Re: [pygtk] GTK_IS_WIDGET on subclass of a widget fails
Christian Becke wrote: > > I think you have to call the constructor of the parent object here: > def __init__(self): > HBox.__init__(self) > and you have to make your new widget known: > import gobject > gobject.type_register (FooBox) > Thanks Christian, and Jeffrey, that helped. Jeffrey ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/
[pygtk] GTK_IS_WIDGET on subclass of a widget fails
I'm new to Gtk. I tried to create a subclass of an HBox and add it to a window, but I get a GtkWarning telling me that the assertion `GTK_IS_WIDGET()' fails on the instance of my subclass. For example: ===code=== from gtk import Window, HBox, WINDOW_TOPLEVEL, main class FooBox(HBox): def __init__(self): pass window = Window(WINDOW_TOPLEVEL) window.add(FooBox()) window.show_all() main() ===/code=== yields a warning at "window.add()", namely "GtkWarning: gtk_container_add: assertion `GTK_IS_WIDGET (widget)' failed". This causes the widget to not be displayed in the window. I don't really understand why this is; am I missing a method call? Thanks. Jeffrey ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/