Re: [pygtk] UI will be blocked if creating a message dialog by emitting a signal
Thanks a lot, it works now! So far I'm using a really stupid method:
using gobject.timeout_add() to check a global flag variable every 0.1
seconds, if the flag is set, the message dialog will be shown.. But now
they can be fixed:)
On 2013/7/25 23:15, Niklas Koep wrote:
Emitting signals from a thread will run the handler in the same
thread. You shouldn't call gtk functions from a thread other than the
main one. If you insist on doing so you have to make sure to acquire
the GDK lock first by wrapping your code in gtk.gdk.threads_enter()
... gtk.gdk.threads_leave() calls. In this case you also have to call
gtk.gdk.thread_init() as otherwise the main loop will never release
the GDK lock. The easier solution is to push the signal emission to
the main thread by replacing self.emit('ASignal') with
gobject.idle_add(self.emit, 'ASignal') which guarantees the handler
will also run in the main thread (which already has the GDK lock).
Regards.
On Thu, Jul 25, 2013 at 4:56 PM, Todong Ma <mailto:gbstac...@gmail.com>> wrote:
Hi, everyone
I met a problem that UI will be blocked forever if I emit a signal
from a thread to create a message dialog.
Following code will reproduce the issue, please let me give a
short explanation: AThread thread defines a custom signal named
"ASignal", and the signal handler is aSignal() function of
MainWindow class. The aSignal() function is used to display a
message dialog. Emitting "ASignal" signal will display the message
dialog successfully but the UI is blocked forever.
import gtk
import gobject
import threading
class AThread(threading.Thread, gobject.GObject):
__gsignals__ = {
'ASignal': (gobject.SIGNAL_RUN_LAST,
gobject.TYPE_NONE, ())
}
def __init__(self):
threading.Thread.__init__(self)
gobject.GObject.__init__(self)
def run(self):
self.emit('ASignal')
class MainWindow(gtk.Window):
def aSignal(self, obj):
dialog = gtk.MessageDialog(self,
gtk.DIALOG_DESTROY_WITH_PARENT, gtk.MESSAGE_INFO,
gtk.BUTTONS_CLOSE, 'asdfasf')
dialog.run()
dialog.destroy()
gobject.threads_init()
w = MainWindow()
t = AThread()
t.connect('ASignal', w.aSignal)
t.start()
gtk.main()
Any suggestion is appreciated.
Thanks,
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[pygtk] UI will be blocked if creating a message dialog by emitting a signal
Hi, everyone
I met a problem that UI will be blocked forever if I emit a signal from
a thread to create a message dialog.
Following code will reproduce the issue, please let me give a short
explanation: AThread thread defines a custom signal named "ASignal", and
the signal handler is aSignal() function of MainWindow class. The
aSignal() function is used to display a message dialog. Emitting
"ASignal" signal will display the message dialog successfully but the UI
is blocked forever.
import gtk
import gobject
import threading
class AThread(threading.Thread, gobject.GObject):
__gsignals__ = {
'ASignal': (gobject.SIGNAL_RUN_LAST, gobject.TYPE_NONE, ())
}
def __init__(self):
threading.Thread.__init__(self)
gobject.GObject.__init__(self)
def run(self):
self.emit('ASignal')
class MainWindow(gtk.Window):
def aSignal(self, obj):
dialog = gtk.MessageDialog(self,
gtk.DIALOG_DESTROY_WITH_PARENT, gtk.MESSAGE_INFO, gtk.BUTTONS_CLOSE,
'asdfasf')
dialog.run()
dialog.destroy()
gobject.threads_init()
w = MainWindow()
t = AThread()
t.connect('ASignal', w.aSignal)
t.start()
gtk.main()
Any suggestion is appreciated.
Thanks,
___
pygtk mailing list pygtk@daa.com.au
http://www.daa.com.au/mailman/listinfo/pygtk
Read the PyGTK FAQ: http://faq.pygtk.org/
[pygtk] How to get hwnd of StatusIcon
Hi everyone, I want to display a balloon notification near system tray icon, I found calling Shell_NotifyIcon with .szInfo and .szInfoTitle will show a balloon message. Widget.get_window() can be used to get a Widget's hwnd, but how could I get hwnd of StatusIcon since it's direct child class of GObject? Thanks, ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/
Re: [pygtk] gobject.timeout_add() won't work after calling gtk.threads_init() on windows xp
On 2013/6/26 18:56, Todong Ma wrote: Hi, everyone Following simple code will hang forever on windows XP, and the "check dialog" text is never outputted to console. The window created in the code showed but is blocked (when I move mouse into the window area, the mouse pointer is always a "loading" icon) */|import gtk import gobject def checkDialog(): print 'check dialog' return True gobject.timeout_add(500, checkDialog) gtk.threads_init() w= gtk.Window() w.show() gtk.main()|/* While same code works well on Windows 7 Runtime details: Windows XP SP3, python 2.7.5, pytgtk-2.24-allinone Just now Juhaz on the IRC channel told me I should try gtk.gdk.threads_init() or gobject.threads_init() instead of gtk.threads_init(). Then I tried them and found it works by using gobject.threads_init()! Thank you all! ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/
[pygtk] gobject.timeout_add() won't work after calling gtk.threads_init() on windows xp
Hi, everyone Following simple code will hang forever on windows XP, and the "check dialog" text is never outputted to console. The window created in the code showed but is blocked (when I move mouse into the window area, the mouse pointer is always a "loading" icon) */|import gtk import gobject def checkDialog(): print 'check dialog' return True gobject.timeout_add(500, checkDialog) gtk.threads_init() w= gtk.Window() w.show() gtk.main()|/* While same code works well on Windows 7 Runtime details: Windows XP SP3, python 2.7.5, pytgtk-2.24-allinone ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://faq.pygtk.org/
