[issue42473] re.sub ignores flag re.M

[Matthew Barnett]

Matthew Barnett  added the comment:

Not a bug.

Argument 4 of re.sub is the count:

sub(pattern, repl, string, count=0, flags=0)

not the flags.

--
nosy: +mrabarnett
resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

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[issue42473] re.sub ignores flag re.M

[Jérôme Laurens]

New submission from Jérôme Laurens :

Test code:
```
import re
test='''012345678
 
012345678
'''
pattern = r'^\s+?$'
m = re.search(pattern, test, re.M)
if m:
print(f'TEST FOUND "{m.span()}"')

def replace(m):
print(f'TEST REMOVE {m.span()}')
return ''

test = re.sub(pattern, replace, test, re.M)
m = re.search(pattern, test, re.M)
if m:
print(f'TEST STILL THERE "{m.span()}"')

print('COMPILE PATTERN FIRST')
pattern_re = re.compile(pattern, re.M)
m = re.search(pattern_re, test)
if m:
print(f'TEST FOUND "{m.span()}"')

def replace(m):
print(f'TEST REMOVE {m.span()}')
return ''

test = re.sub(pattern_re, replace, test)
m = re.search(pattern_re, test)
if m:
print(f'TEST STILL THERE "{m.span()}"')
```

Actual output:

TEST FOUND "(10, 19)"
TEST STILL THERE "(10, 19)"
COMPILE PATTERN FIRST
TEST FOUND "(10, 19)"
TEST REMOVE (10, 19)

This is an inconsistency between re.search and re.sub. Either this is a bug in 
the code or in the documentation.

--
components: IO
messages: 381901
nosy: jlaurens
priority: normal
severity: normal
status: open
title: re.sub ignores flag re.M
type: behavior
versions: Python 3.8

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