Re: Flubbed it in the second interation through the string: range error... HOW?
On 29May2024 01:14, Thomas Passin wrote:
Also, it's 2024 ... time to start using f-strings (because they are
more readable than str.format())
By which Thomas means stuff like this:
print(f'if block {name[index]} and index {index}')
Notice the leading "f'". Personally I wouldn't even go that far, just:
print('if block', name[index], 'and index', index)
But there are plenty of places where f-strings are very useful.
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Re: Flubbed it in the second interation through the string: range error... HOW?
Your code is unreadable. The lines have all run together. And after
that, kindly explain what you want your code sample to do. "Process"
doesn't say much.
From what I can make out about what you are trying to do, you would do
better to index through your string with
for i, chr in enumerate(name):
# do something with the character
Also, it's 2024 ... time to start using f-strings (because they are more
readable than str.format())
On 5/29/2024 12:33 AM, Kevin M. Wilson via Python-list wrote:
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index)) name =
name[index].upper() print('if block {} and index {}'.format(name[index],
index)) elif (index % 2 > 0): print(index) print('Start:
elseif block, index is {}, letter is {}'.format(index, name)) # print('letter
to lower = {}'.format(name[index])) # print('Already lowercase do noting:
name = {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexErrorTraceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass through the
rivers, they will not sweep over you. When you walk through the fire, you will not be
burned: the flames will not set you ablaze."
Isaiah 43:2
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Fw: Flubbed it in the second interation through the string: range error... HOW?
The format in this email is not of my making, should someone know, how to do
this so that it's a readable script do tell!
KMW
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
- Forwarded Message - From: Kevin M. Wilson via Python-list
To: python-list@python.org
Sent: Tuesday, May 28, 2024 at 10:35:23 PM MDTSubject:
Flubbed it in the second interation through the string: range error... HOW?
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index))
name = name[index].upper() print('if block {} and index
{}'.format(name[index], index)) elif (index % 2 > 0):
print(index) print('Start: elseif block, index is {}, letter is
{}'.format(index, name)) # print('letter to lower =
{}'.format(name[index])) # print('Already lowercase do noting: name
= {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexError Traceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
--
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--
https://mail.python.org/mailman/listinfo/python-list
Flubbed it in the second interation through the string: range error... HOW?
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index))
name = name[index].upper() print('if block {} and index
{}'.format(name[index], index)) elif (index % 2 > 0):
print(index) print('Start: elseif block, index is {}, letter is
{}'.format(index, name)) # print('letter to lower =
{}'.format(name[index])) # print('Already lowercase do noting: name
= {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexErrorTraceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
--
https://mail.python.org/mailman/listinfo/python-list
Re: Serializing pydantic enums
Most Python objects aren't serializable into JSON. Pydantic isn't special in this sense. What can you do about this? -- Well, if this is a one-of situation, then, maybe just do it by hand? If this is a recurring problem: json.dumps() takes a cls argument that will be used to do the serialization. Extend json.JSONEncoder and implement the encode() method for the encoder class you are passing. I believe that the official docs have some information about this too. On Tue, May 28, 2024 at 2:50 PM Larry Martell via Python-list wrote: > > Just getting started with pydantic. I have this example code: > > class FinishReason(Enum): > stop = 'stop' > > class Choice(BaseModel): > finish_reason: FinishReason = Field(...) > > > But I cannot serialize this: > > json.dumps(Choice(finish_reason=FinishReason.stop).dict()) > *** TypeError: Object of type FinishReason is not JSON serializable > > > I get the object not the value: > > (Pdb) Choice(finish_reason=FinishReason.stop) > Choice(finish_reason=) > > > Also tried it with .value, same result. > > What am I missing here? > -- > https://mail.python.org/mailman/listinfo/python-list -- https://mail.python.org/mailman/listinfo/python-list
Serializing pydantic enums
Just getting started with pydantic. I have this example code: class FinishReason(Enum): stop = 'stop' class Choice(BaseModel): finish_reason: FinishReason = Field(...) But I cannot serialize this: json.dumps(Choice(finish_reason=FinishReason.stop).dict()) *** TypeError: Object of type FinishReason is not JSON serializable I get the object not the value: (Pdb) Choice(finish_reason=FinishReason.stop) Choice(finish_reason=) Also tried it with .value, same result. What am I missing here? -- https://mail.python.org/mailman/listinfo/python-list
