Python for Windows
Hi! I've tried to install Python a couple of times on my computer. Although it works fine when first downloaded, every time I turn off my computer and then back on Python says it has a problem that needs fixing. After "fixing" it, I still encounter some issues and have the need to uninstall it and install it again. Do you know what the problem is? Thank you. Ana -- *POLÍTICA DE PRIVACIDAD: Las instituciones pertenecientes al Sistema UP-IPADE utilizarán cualquier dato personal expuesto en el presente correo electrónico, única y exclusivamente para cuestiones académicas, administrativas, de comunicación, o bien para las finalidades expresadas en cada asunto en concreto, esto en cumplimiento con la Ley Federal de Protección de Datos Personales en Posesión de los Particulares. Para mayor información acerca del tratamiento y de los derechos que puede hacer valer, usted puede acceder al aviso de privacidad integral a través de nuestras páginas de Internet: www.up.edu.mx <http://www.up.edu.mx> / prepaup.up.edu.mx <http://prepaup.up.edu.mx> / www.ipade.mx <http://www.ipade.mx> / www.ipadealumni.com.mx <http://www.ipadealumni.com.mx> La información contenida en este correo es privada y confidencial, dirigida exclusivamente a su destinatario. Si usted no es el destinatario del mismo debe destruirlo y notificar al remitente absteniéndose de obtener copias, ni difundirlo por ningún sistema, ya que está prohibido y goza de la protección legal de las comunicaciones.* -- https://mail.python.org/mailman/listinfo/python-list
Python and GIL
Hi, Can somebody explain to me how would you proceed in releasing the GIL and whether you think it will have consequences? Thanks Ana -- http://mail.python.org/mailman/listinfo/python-list
Pulp problem _dummy
Hello! I'm using pulp for linear optimization but when I run my code I get the following output: Central Optimization: MAXIMIZE 0*__dummy + 0 SUBJECT TO _C1: 2 T0 >= 0 _C2: 2 T0 <= 0 _C3: 0.0686928673545 Frigorifico0 >= 0 _C4: 0.0686928673545 Frigorifico0 <= 0 _C5: 2 Termo0 >= 0 _C6: 2 Termo0 <= 0 _C7: 0.0686928673545 F0 >= 0 _C8: 0.0686928673545 F0 <= 0 _C9: 2 T1 >= 0 _C10: 2 T1 <= 0 _C11: 0.0686928673545 Frigorifico1 >= 0 _C12: 0.0686928673545 Frigorifico1 <= 0 _C13: 2 Termo0 >= 0 _C14: 2 Termo0 <= 0 _C15: 0.0686928673545 F0 >= 0 _C16: 0.0686928673545 F0 <= 0 _C17: - AC0 - VE0 - 2 T0 - 0.0686928673545 F0 - AC1 - VE1 - 2 T1 - 0.0686928673545 F1 >= -15 VARIABLES AC0 <= 2.75 Continuous VE0 = 0 Continuous 0 <= T0 <= 1 Integer 0 <= F0 <= 1 Integer AC1 <= 2.75 Continuous VE1 = 0 Continuous 0 <= T1 <= 1 Integer 0 <= F1 <= 1 Integer __dummy = 0 Continuous I don't know if this is enough information for you but if you couold help me I would be very very grateful Thank you! -- http://mail.python.org/mailman/listinfo/python-list
Sum operation in numpy arrays
Hello! I have several numpy arrays in my script and i want to add them. For example: a=[1,2,3,4,5] b=[1,1,1,1,1] c=[1,0,1,0,1] for i in range(5): d[i]=a[i]+b[i]+c[i] print d [3,3,5,5,7] I did it like that but I get an error: "TypeError: unsupported operand type(s) for +: 'float' and 'numpy.string_'" How can I sum my arrays? -- http://mail.python.org/mailman/listinfo/python-list
Scan CSV file and saving it into an array
Hello!
I have this script that scans a csv file and if the value in the first column
== 200 it saves that row into an array.
The problem is, I need to save that row and the next 10 rows in that same
array. What can I add to the script so it does that? I tried to do for row in
len(10): but I get an error.
p = csv.reader(open('file.csv'), delimiter=';')
a=[0]*2881
a = numpy.array(a, dtype=dict)
for row in p:
if row[0]=="200":
a=row
break
print a
--
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Re: Reading a CSV file
The condition I want to meet is in the first column, so is there a way to read only the first column and if the condition is true, print the rest? -- http://mail.python.org/mailman/listinfo/python-list
Re: Reading a CSV file
Thank you, but can you explain it a little better? I am just starting in python and I don't think I understood how to apply your awnser -- http://mail.python.org/mailman/listinfo/python-list
Reading a CSV file
Hello! I need to read a CSV file that has "n" rows and "m" columns and if a certain condition is met, for exameple n==200, it prints all the columns in that row. How can I do this? I tried to save all the data in a multi-dimensional array but I get this error: "ValueError: array is too big." Thank you! -- http://mail.python.org/mailman/listinfo/python-list
Lists and arrays
Hello! I need your help! I have an array and I need pick some data from that array and put it in a list, for example: array= [a,b,c,1,2,3] list=array[0]+ array[3]+ array[4] list: [a,1,2] When I do it like this: list=array[0]+ array[3]+ array[4] I get an error: "TypeError: unsupported operand type(s) for +: 'numpy.ndarray' and 'numpy.ndarray'" Can you help me? -- http://mail.python.org/mailman/listinfo/python-list
Re: CSV to matrix array
It's still not working. I still have one column with all the data inside, like this: 2999;T3;3;1;1;Off;ON;OFF;ON;ON;ON;ON;Night;; How can I split this data in a way that if I want to print "T3" I would just do "print array[0][1]"? -- http://mail.python.org/mailman/listinfo/python-list
Re: CSV to matrix array
That only puts the data in one column, I wanted to separate it. For example: data in csv file: 1 2 3 4 5 7 8 9 10 11 a b c d e I wanted an array where I could pick an element in each position. In the case above if I did print array[0][3] it would pick 4 -- http://mail.python.org/mailman/listinfo/python-list
Re: CSV to matrix array
Hi, thanks for yor answer! ;) Anyone has more suggestions? -- http://mail.python.org/mailman/listinfo/python-list
CSV to matrix array
Hello!
I have a CSV file with 20 rows and 12 columns and I need to store it as a
matrix. I already created an array with zeros, but I don't know how to fill it
with the data from the csv file. I have this script:
import numpy
from numpy import array
from array import *
import csv
input = open('Cenarios.csv','r')
cenario = csv.reader(input)
array=numpy.zeros([20, 12])
I know I have to use for loops but I don't know how to use it to put the data
the way I want. Can you help me?
Thanks!
--
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Re: How to do this?
Nice! Thank you! And if I need something like this? [0 0 0 0 0.17 0.17 0.17 0.17 0 0 0 0.17 0.17 0.17 0 0 0 0 0 0 0] How can I do this? -- http://mail.python.org/mailman/listinfo/python-list
How to do this?
So I have this script: " from numpy import array vt=[0]*20 vt = array(vt, dtype=dict) for t in range(20): if t == 4: vt[t]=1 else: vt[t]=0 " And have this output: [0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] What I need is when t == 4 I need to put 1 in that position and in the next 3, for example the following output: [0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0] Do you have any suggestions? I'm sorry if I can't explain this in a better way, English is not my first language Thank you -- http://mail.python.org/mailman/listinfo/python-list
Export data from python to a txt file
Hello!!!
I have this lists a=[1,3,5,6,10], b=[a,t,q,r,s] and I need to export it to a
txt file and I can't use csv.
And I want the next format:
a 1 3 5 6 10
b a t q r s
I already have this code:
"f = open("test.txt", 'w')
f.write("a")
f.write("\n")
f.write("b")
f.write("\n")
for i in xrange(len(a)):
LDFile.write("\t")
LDFile.write(str(a[i]))
LDFile.write("\t")
LDFile.write(str(b[i]))
f.close()"
But it doesn't have the format I want. Can you help?
Thanks!
--
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Test a list
t= [3,5,6,7,10,14,17,21] Basically I want to print Test 1 when i is equal to an element of the list "t" and print Test 2 when i is not equal: while i<=25: if i==t[]: print "Test1" else: print "Test2" What is missing here for this script work? Thank you all -- http://mail.python.org/mailman/listinfo/python-list
Lists and Decimal numbers
So, I have this script that puts in a list every minute in 24 hours hour=[] i=0 t=-(1.0/60.0) while i<24*60: i = i+1 t = t+(1.0/60.0) hour.append([t]) When it is doing the cicle it can have all the decimal numbers, but I need to print the result with only 4 decimal numbers How can I define the number of decimal numbers I want to print in this case? For example with 4 decimal numbers, it would print: 0. 0.0167 0.0333 ... Can you help? -- http://mail.python.org/mailman/listinfo/python-list
Re: Excel column 256 limit
But I still get the error and I use Excel 2010. I'm trying to export data in a list to Excel -- http://mail.python.org/mailman/listinfo/python-list
Excel column 256 limit
Is there some way to go around this limit? I need to import data from python to excel and I need 1440 columns for that. -- http://mail.python.org/mailman/listinfo/python-list
Re: TypeError: 'float' object is not iterable
But isn't t_amb a list? I thought that the first piece of script would create a list. I'm trying to create a list named t_amb with some values that are in a Excel sheet. And then I need to export that list to another Excel sheet -- http://mail.python.org/mailman/listinfo/python-list
TypeError: 'float' object is not iterable
Hi!! I keep having this error and I don't know why: TypeError: 'float' object is not iterable. I have this piece of code, that imports to python some data from Excel and saves it in a list: " t_amb = [] for i in range(sh2.nrows): t_amb.append(sh2.cell(i,2).value) print t_amb " Here is everything ok. But then, I need to pass the data again to exel, so I wrote this: " a=8 for b in range (len(t_amb)): a=8 for d in t_amb[b]: a=a+1 sheet.write(a,b+1,d) " The error appear in "for d in t_amb[b]:" and I don't understand why. Can you help me? -- http://mail.python.org/mailman/listinfo/python-list
Re: Recursive function
Yes, I simplified it a lot. I need to run it 24 times. What I don't really understand is how to put the final temperature (result) in it = 0 in temp_-1 in it =1 -- http://mail.python.org/mailman/listinfo/python-list
Recursive function
Hello! I have to make a script that calculates temperature, but one of the parameters is the temperature in the iteration before, for example: temp = (temp_-1)+1 it = 0 temp = 3 it = 1 temp = 3+1 it = 2 temp = 4+1 How can I do this in a simple way? Thanks a lot! -- http://mail.python.org/mailman/listinfo/python-list
Re: Data Tree urgent help!!!!!!
Thank you so much!!! It works perfectly!!! ;) -- http://mail.python.org/mailman/listinfo/python-list
Re: why generator assigned to slice?
In Peter Otten <__pete...@web.de> writes: >ana sanchez wrote: >> i found this when i read the source of a program in python: >> >> self.__chunks[start:end] = (chunk for i in xrange(start, end)) >> what utility has to assign a generator to a slice??? ?the *final >> result* isn't the same as this?: >> >> self.__chunks[start:end] = [chunk for i in xrange(start, end)] >Whoever used the first variant probably was hoping that it was either faster >or used less peak memory. I think the latter is wrong, and the former can >easily be checked: >$ python -m timeit -s'chunk = "yadda"; chunks = range(100); start = 20; end >= 50' 'chunks[start:end] = (chunk for i in xrange(start, end))' >10 loops, best of 3: 9.02 usec per loop >$ python -m timeit -s'chunk = "yadda"; chunks = range(100); start = 20; end >= 50' 'chunks[start:end] = [chunk for i in xrange(start, end)]' >10 loops, best of 3: 4.16 usec per loop >$ python -m timeit -s'chunk = "yadda"; chunks = range(100); start = 20; end >= 50' 'chunks[start:end] = [chunk]*(end-start)' >100 loops, best of 3: 1.02 usec per loop peter thank you very much!!! (i like very much the timing "miniscripts") ana -- http://mail.python.org/mailman/listinfo/python-list
why generator assigned to slice?
hi!!! i found this when i read the source of a program in python: self.__chunks[start:end] = (chunk for i in xrange(start, end)) and also this: self.__lines[line:line] = (None for i in xrange(count)) what utility has to assign a generator to a slice??? ?the *final result* isn't the same as this?: self.__chunks[start:end] = [chunk for i in xrange(start, end)] self.__chunks[line:line] = [None for i in xrange(count)] thanks!!! ana p.d. excuse my english -- http://mail.python.org/mailman/listinfo/python-list
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Re: urgent - Matplolib with IDLE!
Hi, in site-packages/matplotlib/backends/backend_tkagg.py I commented out in the show function the line Tk.mainloop() In addition to the changes I mentioned in my first email, this has solved my problem! On 3/19/07, Rob Clewley <[EMAIL PROTECTED]> wrote: I have the same problem with a similar setup (except Python 2.4.3) and have tried the same solutions (BTW those steps really did used to work on my machine using Python 2.3.5). In the short term you could either try IPython (a proper solution to this problem, which returns me to the prompt just fine after closing the figure) or try the following "quick and dirty fix" with IDLE: 1) If your script does stuff other than define classes and functions, put in a command that prevents it getting to the calculations (e.g. insert a "1/0" line) or, for instance, turn all your calculations into function calls that you can easily comment out (temporarily). Run your script using F5 so that you just get the prompt. 3) Create an empty figure using pylab.figure() or whatever. 2) Close the figure and the IDLE console (command prompt window) that opened when you ran the script (you have to say Yes when it asks about killing a python process). 3) This leaves an orphaned python process which you have to clean up later using your Task Manager, but ... 4) you can now continue to interact with any new IDLE console created in the current session when you bring up new figures. i.e. uncomment the parts of your script that actually do stuff and run it again. At least that's a quick fix that's working for me while I await a better answer too... Perhaps this hack will outrage someone's sensibilities sufficiently that we'll hear of a better IDLE solution. HTH, Rob -- http://mail.python.org/mailman/listinfo/python-list
urgent - Matplolib with IDLE!
Dear all, I've just started using Matplotlib and I'm trying to make it work in IDLE. Other people have reported the same problem as I'll refer, but I've tried some solutions that I found in the web and I haven't succeded. Every time I produce a figure, I can't get the IDLE prompt active again after closing that figure. I've tried the following: - in site-pachages/matplotlib/backends/backend_tkagg.py I've uncommented the line #os.environ['PYTHONINSPECT'] = '1' - I've changed to the interactive mode, i.e I've set interactive=True in share/matplotlib/.matplotlibrc - I've started IDLE with the -n flag I would sincerely appreciate your help, because I must finish some work very very soon and I'm going crazy with this issue... By the way, I'm using - windows XP - matplotlib-0.90.0.win32-py2.5 - numpy-1.0.1.win32-py2.5 - python 2.5 Te -- http://mail.python.org/mailman/listinfo/python-list
