Re: GLE-like python package
On Oct 14, 12:54 pm, Wildemar Wildenburger <[EMAIL PROTECTED]> wrote: > Hello there, > > I'm exploring possibilities of using python as an alternative to Matlab. > The obvious way to go seems to be matplotlib for plotting, but I do like > GLE http://glx.sourceforge.net/> a lot. One reason is that with GLE > you can also do diagrams, that is, descriptive pictures (like > http://glx.sourceforge.net/examples/diagrams/index.html>) > > Is there anything similar for python? > > /W I think this is what you're looking for: http://pyx.sourceforge.net/ Cesar -- http://mail.python.org/mailman/listinfo/python-list
Re: Basic question
On May 12, 8:13 pm, [EMAIL PROTECTED] (Alex Martelli) wrote:
> Cesar G. Miguel <[EMAIL PROTECTED]> wrote:
>
> > On May 12, 3:40 pm, Dmitry Dzhus <[EMAIL PROTECTED]> wrote:
> > > > Actually I'm trying to convert a string to a list of float numbers:
> > > > str = '53,20,4,2' to L = [53.0, 20.0, 4.0, 2.0]
>
> > > str="53,20,4,2"
> > > map(lambda s: float(s), str.split(','))
>
> > > Last expression returns: [53.0, 20.0, 4.0, 2.0]
> > > --
> > > Happy Hacking.
>
> > > Dmitry "Sphinx" Dzhushttp://sphinx.net.ru
>
> > Nice!
>
> As somebody else alredy pointed out, the lambda is supererogatory (to
> say the least).
>
> > The following also works using split and list comprehension (as
> > suggested in a brazilian python forum):
>
> > ---
> > L = []
> > file = ['5,1378,1,9', '2,1,4,5']
> > str=''
> > for item in file:
> > L.append([float(n) for n in item.split(',')])
>
> The assignment to str is useless (in fact potentially damaging because
> you're hiding a built-in name).
>
> L = [float(n) for item in file for n in item.split(',')]
>
> is what I'd call Pythonic, personally (yes, the two for clauses need to
> be in this order, that of their nesting).
>
> Alex
Yes, 'str' is unnecessary. I just forgot to remove it from the code.
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Re: Basic question
On May 12, 3:40 pm, Dmitry Dzhus <[EMAIL PROTECTED]> wrote:
> > Actually I'm trying to convert a string to a list of float numbers:
> > str = '53,20,4,2' to L = [53.0, 20.0, 4.0, 2.0]
>
> str="53,20,4,2"
> map(lambda s: float(s), str.split(','))
>
> Last expression returns: [53.0, 20.0, 4.0, 2.0]
> --
> Happy Hacking.
>
> Dmitry "Sphinx" Dzhushttp://sphinx.net.ru
Nice!
The following also works using split and list comprehension (as
suggested in a brazilian python forum):
---
L = []
file = ['5,1378,1,9', '2,1,4,5']
str=''
for item in file:
L.append([float(n) for n in item.split(',')])
---
Thank you for all suggestions!
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Re: Basic question
On May 12, 3:09 pm, Karlo Lozovina <[EMAIL PROTECTED]> wrote:
> Cesar G. Miguel wrote:
> > -
> > L = []
> > file = ['5,1378,1,9', '2,1,4,5']
> > str=''
> > for item in file:
> >j=0
> >while(j > while(item[j] != ','):
> > str+=item[j]
> > j=j+1
> > if(j>= len(item)): break
>
> > if(str != ''):
> > L.append(float(str))
> > str = ''
>
> > j=j+1
>
> > print L
> > But I'm not sure this is an elegant pythonic way of coding :-)
>
> Example:
>
> In [21]: '5,1378,1,9'.split(',')
> Out[21]: ['5', '1378', '1', '9']
>
> So, instead of doing that while-based traversal and parsing of `item`,
> just split it like above, and use a for loop on it. It's much more
> elegant and pythonic.
>
> HTH,
> Karlo.
Great! Now it looks better :-)
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Re: Basic question
On May 12, 2:45 pm, Basilisk96 <[EMAIL PROTECTED]> wrote:
> On May 12, 12:18 pm, "Cesar G. Miguel" <[EMAIL PROTECTED]> wrote:
>
>
>
> > I've been studying python for 2 weeks now and got stucked in the
> > following problem:
>
> > for j in range(10):
> > print j
> > if(True):
> >j=j+2
> >print 'interno',j
>
> > What happens is that "j=j+2" inside IF does not change the loop
> > counter ("j") as it would in C or Java, for example.
>
> > Am I missing something?
>
> > []'s
> > Cesar
>
> What is your real intent here? This is how I understand it after
> reading your post: you want to create a loop that steps by an
> increment of 2. If that's the case, then:
>
> >>> for j in range(0,10,2):
>
> ... print j
> ...
> 0
> 2
> 4
> 6
> 8
>
> would be a simple result.
>
> Cheers,
> -Basilisk96
Actually I'm trying to convert a string to a list of float numbers:
str = '53,20,4,2' to L = [53.0, 20.0, 4.0, 2.0]
As some of you suggested, using while it works:
-
L = []
file = ['5,1378,1,9', '2,1,4,5']
str=''
for item in file:
j=0
while(j= len(item)): break
if(str != ''):
L.append(float(str))
str = ''
j=j+1
print L
-
But I'm not sure this is an elegant pythonic way of coding :-)
Thanks for all suggestions!
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Basic question
I've been studying python for 2 weeks now and got stucked in the
following problem:
for j in range(10):
print j
if(True):
j=j+2
print 'interno',j
What happens is that "j=j+2" inside IF does not change the loop
counter ("j") as it would in C or Java, for example.
Am I missing something?
[]'s
Cesar
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