Re: How to retrieve the filename of a module

[Jim O'D]

mku wrote:
 Hi,
 
 there´s a function inside a module. How can these function retrieve
 the path+name   of his module ? (The path is most important).
 That should also work if the module is part of a package.
 
 Thanks in advance
 
 Martin
 

Try the following in the function:

import traceback
f = traceback.extract_stack(limit=2)

If you output f to the interpreter, you'll see the filename but I don't 
know what position in the output list it is guaranteed to be.

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

Re: array subset could be improved? -repost ;)

[Jim O'D]

 With the new numeric, you'll be able to do:
 
 negatives = a[a0]
 
 Cheers,
 
 f
 

Ooh, that's nice.

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

my array subset method could be improved?

[Jim O'D]

Hi all

I have an array a=array([2,3,1]).

I want to extract an array with all the elements of a that are less than 0.

Method 1.
new = array([i for i in a if i  0])

Method 2.
new = a[nonzero(a0)]

I'm using Numeric arrays but can't seem to find a function that does this.

Am I missing a more obvious way to do it quickly?

Thanks

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

array subset could be improved? -repost ;)

[Jim O'D]

Hi all

I have an array a=array([2,3,-1]).

I want to extract an array with all the elements of a that are less than 0.

Method 1.
new = array([i for i in a if i  0])

Method 2.
new = a[nonzero(a0)]

I'm using Numeric arrays but can't seem to find a function that does this.

Am I missing a more obvious way to do it quickly?

Thanks

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

Re: my array subset method could be improved?

[Jim O'D]

 
 new = Numeric.compress(Numeric.less(a,0),a)

Ah, thank you!

Sorry about subject mangle, I gave a silly example first time round.

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

assignment, references and list comprehension

[Jim O'D]

Hi everyone

Was just posting a question as I got confused with a big messy sheaf of 
code when I thought I should make a simple example myself. Since I did I 
thought I'd post it for the good of mankind.

I was confused as to whether the assignment of a result of a list 
comprehension created references to the orginal objects... and it does 
(at least for my self-defined object).

e.g.
initArrrgs = [pick me,not me]

class MyObject:
def __init__(arg):
self.argument = arg;

myObjects = [MyObject(initarg) for initarg in initArrrgs]
myObjects2 = [ob for ob in myObjects if ob.argument == pick me]

Then the following interrogation

  myObjects2[0].argument
'pick me'
  myObjects2[0].argument='juicy'
  myObjects2[0].argument
'juicy'
  myObjects[0].argument
'juicy'


Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

Re: assignment, references and list comprehension

[Jim O'D]

 trust me, it works the same way for all objects.
 
 

Yes, it was lack of trust that led me on a 2 hour re-write to avoid 
creating subsets of object lists as I thought they were being copied. In 
fact it was another error... huh.

I now know better.

Jim
-- 
http://mail.python.org/mailman/listinfo/python-list

Re: assignment, references and list comprehension

[Jim O'D]

 reading this may help:
 
 http://effbot.org/zone/python-objects.htm
 
 /F 
 
 
 

site bookmarked ;)
-- 
http://mail.python.org/mailman/listinfo/python-list