Font issues Tkinter/Python 3.5

[KP]

import tkinter as tk
from tkinter import ttk
from tkinter import font
...
def __init__(self):
self.root = tk.Tk()
self.root.title('Main Window')
self.root.geometry('1000x800+200+200')
self.root.minsize(width=1000, height=800)

default_font = tkFont.nametofont("TkDefaultFont")
default_font.configure(size=12)
self.root.option_add("*Font", default_font)
... 
self.root.mainloop()
...

tells me that 'tkFont' is not defined. What am I missing?

As always, thanks for any pointers!
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Tkinter spacing

[KP]

If I want to have some space between, say, btn_last & btn_new, will I have to 
use a dummy label in between these two or is there a better way?

Thanks for any help, as always!




from tkinter import *
from tkinter import ttk

root = Tk()
root.geometry("822x600+100+100")
nav_bar = ttk.Frame(root, borderwidth=2, relief='ridge', padding=(10, 3, 10, 3))

btn_first  = ttk.Button(nav_bar, text='|<', width=4)  # for buttons showing 
text only, this will be text units (= average characters?)
btn_prev   = ttk.Button(nav_bar, text='<',  width=4)  # for image buttons, it 
will be in pixels 
btn_next   = ttk.Button(nav_bar, text='>',  width=4)
btn_last   = ttk.Button(nav_bar, text='>|', width=4)
btn_new= ttk.Button(nav_bar, text='New')
btn_edit   = ttk.Button(nav_bar, text='Edit')
btn_delete = ttk.Button(nav_bar, text='Delete')
btn_cancel = ttk.Button(nav_bar, text='Cancel')
btn_print  = ttk.Button(nav_bar, text='Print')
btn_help   = ttk.Button(nav_bar, text='Help')
btn_save   = ttk.Button(nav_bar, text='Save')
lbl_Recs   = ttk.Label(nav_bar,  text='Records')
lbl_RCount = ttk.Label(nav_bar,  text='0 ', width=10, borderwidth=2, 
relief='sunken', anchor='e')  # fake entry look

nav_bar.grid(column=0, row=0, columnspan=13)

btn_first.grid(column=0, row=0)
btn_prev.grid(column=1,  row=0)
btn_next.grid(column=2,  row=0)
btn_last.grid(column=3,  row=0)

btn_new.grid(column=4,row=0)
btn_edit.grid(column=5,   row=0)
btn_delete.grid(column=6, row=0)
btn_cancel.grid(column=7, row=0)

lbl_Recs.grid(column=8,   row=0, padx=5)
lbl_RCount.grid(column=9, row=0, padx=5)
btn_print.grid(column=10, row=0)
btn_help.grid(column=11,  row=0)
btn_save.grid(column=12,  row=0)

root.mainloop()
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Re: tkinter newbie question

[KP]

On Sunday, 24 January 2016 20:20:07 UTC-8, KP  wrote:
> See my code below (which works). I'd like to have the 2nd window as a class 
> in a separate unit. How do I code that unit and how do I call it from my 
> first unit?
> 
> As always, thanks for all help!
> 
> 
> 
> 
> #!/usr/bin/env python
> """
> """ 
> from tkinter import *
> from settings import *
> 
> class window1():
> 
> def open_window2(self):
> t = Toplevel(self.root)
> t.title('New window')
> t.geometry('262x65+200+250')
> t.transient(self.root)
> 
> def setup_menu(self):
> self.menubar = Menu(self.root)
> self.menu1 = Menu(self.menubar, tearoff=0 ) 
> self.menu1.add_command(label="Settings",   accelerator='Ctrl+S', 
> command=self.open_window2)
> self.menubar.add_cascade(label="Menu 1", menu=self.menu1)  
> self.root.config(menu=self.menubar)
> 
> def __init__(self):
> self.root = Tk()
> self.root.title('Window #1')
> self.setup_menu()
> self.root.geometry('800x600+200+200')
> #
> self.root.mainloop()
> 
> if __name__ == '__main__':
> 
> w1 = window1()

Thank you - much appreciated!
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Re: tkinter newbie question

[KP]

On Monday, 25 January 2016 08:22:12 UTC-8, KP  wrote:
> On Monday, 25 January 2016 00:51:34 UTC-8, Peter Otten  wrote:
> > KP wrote:
> > 
> > > See my code below (which works). 
> > 
> > >From the import of lowercase "tkinter" I conclude you are using Python 3.
> > 
> > > I'd like to have the 2nd window as a
> > > class in a separate unit. How do I code that unit and how do I call it
> > > from my first unit?
> > > 
> > > As always, thanks for all help!
> > 
> > Move the code from open_window2() into a class in settings.py, e. g.
> > 
> > 
> > import tkinter as tk # avoid star-import
> > 
> > class SettingsWindow(tk.Toplevel): # Class names start with uppercase letter
> ># Prefer self-explaining names
> > def __init__(self, root):
> > super().__init__(root)
> > self.title('New window')
> > self.geometry('262x65+200+250')
> > self.transient(root)
> > 
> > Then use it in your main script:
> > 
> > 
> > > #!/usr/bin/env python
> > > """
> > > """
> > > from tkinter import *
> > import settings
> > 
> > > class window1():
> > > 
> > > def open_window2(self):
> >   settings.SettingsWindow(self.root)
> > 
> > > def setup_menu(self):
> > > self.menubar = Menu(self.root)
> > > self.menu1 = Menu(self.menubar, tearoff=0 )
> > > self.menu1.add_command(label="Settings",   accelerator='Ctrl+S',
> > > command=self.open_window2) self.menubar.add_cascade(label="Menu
> > > 1", menu=self.menu1) self.root.config(menu=self.menubar)
> > > 
> > > def __init__(self):
> > > self.root = Tk()
> > > self.root.title('Window #1')
> > > self.setup_menu()
> > > self.root.geometry('800x600+200+200')
> > > #
> > > self.root.mainloop()
> > > 
> > > if __name__ == '__main__':
> > > 
> > > w1 = window1()
> 
> Dang - almost there. Using your code, I get the new window with the specified 
> geometry and its type is transient, as expected.
> 
> Its caption, however, is NOT the caption specified, but the caption of the 
> first window, leaving me with 2 windows with identical caption.
> 
> Any idea why?

Forget that post - mea culpa - figured it out - sorry!
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Re: tkinter newbie question

[KP]

On Monday, 25 January 2016 00:51:34 UTC-8, Peter Otten  wrote:
> KP wrote:
> 
> > See my code below (which works). 
> 
> >From the import of lowercase "tkinter" I conclude you are using Python 3.
> 
> > I'd like to have the 2nd window as a
> > class in a separate unit. How do I code that unit and how do I call it
> > from my first unit?
> > 
> > As always, thanks for all help!
> 
> Move the code from open_window2() into a class in settings.py, e. g.
> 
> 
> import tkinter as tk # avoid star-import
> 
> class SettingsWindow(tk.Toplevel): # Class names start with uppercase letter
># Prefer self-explaining names
> def __init__(self, root):
> super().__init__(root)
> self.title('New window')
> self.geometry('262x65+200+250')
> self.transient(root)
> 
> Then use it in your main script:
> 
> 
> > #!/usr/bin/env python
> > """
> > """
> > from tkinter import *
> import settings
> 
> > class window1():
> > 
> > def open_window2(self):
>   settings.SettingsWindow(self.root)
> 
> > def setup_menu(self):
> > self.menubar = Menu(self.root)
> > self.menu1 = Menu(self.menubar, tearoff=0 )
> > self.menu1.add_command(label="Settings",   accelerator='Ctrl+S',
> > command=self.open_window2) self.menubar.add_cascade(label="Menu
> > 1", menu=self.menu1) self.root.config(menu=self.menubar)
> > 
> > def __init__(self):
> > self.root = Tk()
> > self.root.title('Window #1')
> > self.setup_menu()
> > self.root.geometry('800x600+200+200')
> > #
> > self.root.mainloop()
> > 
> > if __name__ == '__main__':
> > 
> > w1 = window1()

Dang - almost there. Using your code, I get the new window with the specified 
geometry and its type is transient, as expected.

Its caption, however, is NOT the caption specified, but the caption of the 
first window, leaving me with 2 windows with identical caption.

Any idea why?
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tkinter newbie question

[KP]

See my code below (which works). I'd like to have the 2nd window as a class in 
a separate unit. How do I code that unit and how do I call it from my first 
unit?

As always, thanks for all help!




#!/usr/bin/env python
"""
""" 
from tkinter import *
from settings import *

class window1():

def open_window2(self):
t = Toplevel(self.root)
t.title('New window')
t.geometry('262x65+200+250')
t.transient(self.root)

def setup_menu(self):
self.menubar = Menu(self.root)
self.menu1 = Menu(self.menubar, tearoff=0 ) 
self.menu1.add_command(label="Settings",   accelerator='Ctrl+S', 
command=self.open_window2)
self.menubar.add_cascade(label="Menu 1", menu=self.menu1)  
self.root.config(menu=self.menubar)

def __init__(self):
self.root = Tk()
self.root.title('Window #1')
self.setup_menu()
self.root.geometry('800x600+200+200')
#
self.root.mainloop()

if __name__ == '__main__':

w1 = window1()
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Re: Fast pythonic way to process a huge integer list

[KP]

On Wednesday, 6 January 2016 18:37:22 UTC-8, high5s...@gmail.com  wrote:
> I have a list of 163.840 integers. What is a fast & pythonic way to process 
> this list in 1,280 chunks of 128 integers?

Thanks all for your valuable input - much appreciated!
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Is there an idiom for this?

[KP]

Given: 

cfg =  {'c': ('3840', '1024'), 
   'p1': {'gpio': '1', 'id': '4', 'coord': ('0', '0', '1280', '1024')}, 
   'p2': {'gpio': '2', 'id': '5', 'coord': ('1280', '0', '2560', '1024')}, 
   'p3': {'gpio': '3', 'id': '6', 'coord': ('2560', '0', '3840', '1024')}} 

for config in cfg: 
if config != 'c': 
print config 

Is there an idiom that combines the 'for...' & the 'if..' lines into one? 
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Idiom for this case?

[KP]

Given:

cfg =  {'c': ('3840', '1024'),
   'p1': {'gpio': '1', 'id': '4', 'coord': ('0', '0', '1280', '1024')}, 
   'p2': {'gpio': '2', 'id': '5', 'coord': ('1280', '0', '2560', '1024')},
   'p3': {'gpio': '3', 'id': '6', 'coord': ('2560', '0', '3840', '1024')}}

for config in cfg:
if config != 'canvas':
print config

Is there an idiom that combines the 'for...' & the 'if..' lines into one?

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Re: Is there an idiom for this?

[KP]

Thanks Paul, you just pointed out one of my blonder moments: 

I actually want all nested dicts one by one, but not the one with the 'c' key...



On Thursday, 24 December 2015 14:15:45 UTC-8, Paul Rubin  wrote:
> KP writes:
> > for config in cfg: 
> > if config != 'c': 
> > print config 
> >
> > Is there an idiom that combines the 'for...' & the 'if..' lines into one? 
> 
> Maybe you actually want
> 
>   print [config for config in cfg if config != 'c']
> 
> That prints all the relevant keys as a list, rather than one per line.

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Re: Newbie: String to Tuple

[KP]

On Tuesday, 22 December 2015 12:59:59 UTC-8, Mark Lawrence  wrote:
> On 22/12/2015 20:53, KP wrote:
> > How do I convert
> >
> > '1280,1024'
> >
> > to
> >
> > (1280,1024) ?
> >
> > Thanks for all help!
> >
> 
> Start with this https://docs.python.org/3/library/stdtypes.html#str.split
> 
> -- 
> My fellow Pythonistas, ask not what our language can do for you, ask
> what you can do for our language.
> 
> Mark Lawrence

Thanks - just what I was missing!
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Re: Newbie XML problem

[KP]

Thank you both - your help is much appreciated!
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Newbie: Convert strings in nested dict to tuples

[KP]

I now know how to convert a string cont. coordinates to a tuple, but hwo can I 
do this?

Given

cfg = {'canvas': ('3840', '1024'),
  'panel1': {'gpio': '1', 'id': '4', 'co': '0,0,1280,1024'}, 
  'panel2': {'gpio': '2', 'id': '5', 'co': '1280,0,2560,1024'},
  'panel3': {'gpio': '3', 'id': '6', 'co': '2560,0,3840,1024'}}

how can I transform cfg to 

cfg = {'canvas': ('3840', '1024'),
  'panel1': {'gpio': '1', 'id': '4', 'co': ('0','0','1280','1024')}, 
  'panel2': {'gpio': '2', 'id': '5', 'co': ('1280','0','2560','1024')},
  'panel3': {'gpio': '3', 'id': '6', 'co': ('2560','0','3840','1024')}}

Again, thanks for all help!
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Re: Newbie: Convert strings in nested dict to tuples

[KP]

Beautiful - thanks!

On Tuesday, 22 December 2015 15:23:25 UTC-8, Peter Otten  wrote:
> KP wrote:
> 
> > I now know how to convert a string cont. coordinates to a tuple, but hwo
> > can I do this?
> > 
> > Given
> > 
> > cfg = {'canvas': ('3840', '1024'),
> >   'panel1': {'gpio': '1', 'id': '4', 'co': '0,0,1280,1024'},
> >   'panel2': {'gpio': '2', 'id': '5', 'co': '1280,0,2560,1024'},
> >   'panel3': {'gpio': '3', 'id': '6', 'co': '2560,0,3840,1024'}}
> > 
> > how can I transform cfg to
> > 
> > cfg = {'canvas': ('3840', '1024'),
> >   'panel1': {'gpio': '1', 'id': '4', 'co': ('0','0','1280','1024')},
> >   'panel2': {'gpio': '2', 'id': '5', 'co':
> >   ('1280','0','2560','1024')}, 'panel3': {'gpio': '3', 'id': '6',
> >   'co': ('2560','0','3840','1024')}}
> > 
> > Again, thanks for all help!
> 
> >>> cfg = {'canvas': ('3840', '1024'),
> ...   'panel1': {'gpio': '1', 'id': '4', 'co': '0,0,1280,1024'}, 
> ...   'panel2': {'gpio': '2', 'id': '5', 'co': '1280,0,2560,1024'},
> ...   'panel3': {'gpio': '3', 'id': '6', 'co': '2560,0,3840,1024'}}
> >>> 
> >>> for value in cfg.values():
> ... if isinstance(value, dict):
> ... value["co"] = tuple(value["co"].split(","))
> ... 
> >>> import pprint
> >>> pprint.pprint(cfg)
> {'canvas': ('3840', '1024'),
>  'panel1': {'co': ('0', '0', '1280', '1024'), 'gpio': '1', 'id': '4'},
>  'panel2': {'co': ('1280', '0', '2560', '1024'), 'gpio': '2', 'id': '5'},
>  'panel3': {'co': ('2560', '0', '3840', '1024'), 'gpio': '3', 'id': '6'}}

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Newbie: String to Tuple

[KP]

How do I convert

'1280,1024'

to

(1280,1024) ? 

Thanks for all help!
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Newbie XML problem

[KP]

>From my first foray into XML with Python:

I would like to retrieve this list from the XML upon searching for the 'config' 
with id attribute = 'B'


config = {id: 1, canvas: (3840, 1024), comment: "a comment",
 {id: 4, gate: 3, (0,0, 1280, 1024)},   
 {id: 5, gate: 2, (1280, 0, 2560, 1024)},
 {id: 6, gate: 1, (2560, 0, 3840, 1024)}}

I have started to use this code - but this is beginning to feel very 
non-elegant; not the cool Python code I usually see...

import xml.etree.ElementTree as ET

tree   = ET.parse('master.xml')
master = tree.getroot()

for config in master:
if config.attrib['id'] == 'B':
...  

Thanks for any help!






3840,1024
"bla"

1
6
0,0,1280,1024


2
5
1280,0,2560,1024


3
4
2560,0,3840,1024



3840,1024
"a comment"

4
3
0,0,1280,1024


5
2
1280,0,2560,1024


6
1
2560,0,3840,1024



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Re: List of integers

[KP]

On Sunday, 13 December 2015 16:33:20 UTC-8, Chris Angelico  wrote:
> On Mon, Dec 14, 2015 at 11:24 AM, KP <> wrote:
> > data = list(f.read(4))
> > print data
> >
> > from a binary file might give
> >
> > ['\x10', '\x20', '\x12', '\x01']
> >
> >
> > How can I receive this instead?
> >
> > [0x10, 0x20, 0x12, 0x01]
> >
> > Thanks for all help!
> 
> Try this:
> 
> data = [ord(x) for x in f.read(4)]
> 
> Note that it won't print out in hexadecimal.
> 
> >>> [0x10, 0x20, 0x12, 0x01]
> [16, 32, 18, 1]
> 
> If you insist on that, try a subclass of int:
> 
> class ord(int):
> ord = ord
> def __new__(cls, x):
> return super().__new__(cls, cls.ord(x))
> def __repr__(self): return hex(self)
> 
> Then they'll come out in hex.
> 
> ChrisA

Thanks much!

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Re: Weird list conversion

[KP]

On Sunday, 13 December 2015 11:57:57 UTC-8, Laura Creighton  wrote:
> In a message of Sun, 13 Dec 2015 11:45:19 -0800, KP writes:
> >Hi all,
> >
> >  f = open("stairs.bin", "rb") 
> >  data = list(f.read(16))
> >  print data
> >
> >returns
> >
> >['=', '\x04', '\x00', '\x05', '\x00', '\x01', '\x00', '\x00', '\x00', 
> >'\x00', '\x00', '\x00', '\x00', '\x00', '\x00', '\x00']
> >
> >The first byte of the file is 0x3D according to my hex editor, so why does 
> >Python return '=' and not '\x3D'?
> >
> >As always, thanks for any help!
> 
> 0x3d is the ascii code for '='

I am aware of that - so is the rule that non-printables are returned in hex 
notation whereas printables come in their ASCII representation?
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List of integers

[KP]

data = list(f.read(4))
print data

from a binary file might give

['\x10', '\x20', '\x12', '\x01']


How can I receive this instead?

[0x10, 0x20, 0x12, 0x01]

Thanks for all help!

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How to install PIL or PILLOW on OS X Yosemite?

[KP]

Hi,

just upgraded my Mac Mini to Yosemite and have never dabbled in Python on this 
OS.

I see it has Python 2.7.6 installed.

When I do something like

from PIL import ImageFont, ImageDraw

it tells me that it cannot find PIL

How do I install this on Yosemite?

Any pointers much appreciated

KP
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