Re: Probably simple syntax error
**weights_array(randomizing_counter) = small_randomized_int The starred line is the one getting the error message: SyntaxError: can't assign to function call Now, I do understand what this means. I'm trying to assign to a function instead of the value that the function should create. But since when is weights_array or small_randomizing_int a function? Both are being declared in the code on their first usage. This one has got me stumped, maybe you guys can help me out with it? Using parens () indicates a function call. I suspect things will work much better using square brackets []. Square brackets indicate the index into a sequence (like a list) -- http://mail.python.org/mailman/listinfo/python-list
Re: Error message if there is a space in the source directory
When using a source like this on line 5: source = [r'C:\test\test 2\\'] which has a space in the title, the program will not work. Try wrapping that argument in double quotes when you build the command -- http://mail.python.org/mailman/listinfo/python-list
Re: regex question
is there any way i would be successful then, in using raw string inside my makeRE() function? Why do you think you even need a raw string? Just build and return the string 'a|b|c' (NOTE: DON'T add the quotes to the string) -- http://mail.python.org/mailman/listinfo/python-list
Re: regex question
yes, i suppose you are right. i can't think of a reason i would NEED a raw string in this situation. It looks from your code that you are trying to remove all occurances of one string from the other. a simple regex way would be to use re.sub() import re a = abc b = debcabbde re.sub([ + a + ],,b) 'dede' -- http://mail.python.org/mailman/listinfo/python-list
Re: TypeError: cannot concatenate 'str' and 'NoneType' objects
# Begin going through the loop Townshp = Townshps.next() while Townshps !=: #Set the output name to be the same as input outName = outputPath + / + Townshp + land + .img Output_table = outputPath + / + Townshp + table + .dbf #For each extract by Mask gp.ExtractbyMask_sa (raster, Townshp, outName) #For each tabluate area gp.TabulateArea_sa (Townshp, RITOWN5K_, outName, VALUE, Output_table, 98.425) Townshp = Townshps.next() Warning: I know nothing about the Python ArcGIS stuff. The first thing that jumps out at me is your while condition. You are testing Townshps when it seems from the code that you should be testing Townshp. However, the typical Python way to iterate through a list for be to use a for loop. Perhaps replace the while statement with: for Townshp in Townshps: and remove the Townshp = Townshps.next() lines If that doesn't do it, please post the entire traceback message that you are seeing (copy and paste it) and it should tell us a lot more about your error. -- http://mail.python.org/mailman/listinfo/python-list
Re: 6 Pick Bet Grouping
The totalizator system allows us to merge or group these four bets as
follows:
5 + 7 / 3 / 11 / 7 + 14 / 1 / 9 - $50 ($200 total)
I'm still trying to get my head around what you're trying to do, but
here's some code:
---snip-
data = [5 / 3 / 11 / 7 / 1 / 9 - $50,
7 / 3 / 11 / 7 / 1 / 9 - $50,
5 / 3 / 11 / 14 / 1 / 9 - $50,
7 / 3 / 11 / 14 / 1 / 9 - $50]
pick6 = [{},{},{},{},{},{}]
for line in data:
amount = int(line.split(-)[1].strip().lstrip($))
runners = [int(s) for s in line.split(-)[0].split(/)]
for x,r in enumerate(runners):
qty,amt = pick6[x].get(r,(0,0))
qty += 1
amt += amount
pick6[x][r] = (qty,amt)
for place in range(6):
print For position ,place
for runner in sorted(pick6[place].keys()):
bets = pick6[place][runner][0]
betamt = pick6[place][runner][1]
print Runner,runner,has,bets,bets for $,betamt
---snip-
Output:
For position 0
Runner 5 has 2 bets for $ 100
Runner 7 has 2 bets for $ 100
For position 1
Runner 3 has 4 bets for $ 200
For position 2
Runner 11 has 4 bets for $ 200
For position 3
Runner 7 has 2 bets for $ 100
Runner 14 has 2 bets for $ 100
For position 4
Runner 1 has 4 bets for $ 200
For position 5
Runner 9 has 4 bets for $ 200
Is that anywhere close?
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Re: basic python questions
[EMAIL PROTECTED] wrote:
dict = {}
As a general rule you should avoid variable names which shadow built in
types (list, dict, etc.). This can cause unexpected behavior later on.
Also, variable names should be more descriptive of their contents.
Try word_dict or some such variant
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Re: Unicode/ascii encoding nightmare
The string below is the encoding of the norwegian word fødselsdag.
s = 'f\xc3\x83\xc2\xb8dselsdag'
I'm not sure which encoding method you used to get the string above.
Here's the result of my playing with the string in IDLE:
u1 = u'fødselsdag'
u1
u'f\xf8dselsdag'
s1 = u1.encode('utf-8')
s1
'f\xc3\xb8dselsdag'
u2 = s1.decode('utf-8')
u2
u'f\xf8dselsdag'
print u2
fødselsdag
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Re: python html rendering
Hi, Im looking for a way to display some python code in html: with correct indentation, possibly syntax hiliting, dealing correctly with multi-line comment, and... generating valid html code if the python code itself deals with html (hence manipulates tag litterals. Thanks for your help! I haven't used it, but these seem promising: http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/252170 http://silvercity.sourceforge.net/ Hope it helps. -- http://mail.python.org/mailman/listinfo/python-list
Re: Spliting a string on non alpha characters
I'm relatively new to python but I already noticed that many lines of python code can be simplified to a oneliner by some clever coder. As the topics says, I'm trying to split lines like this : 'foo bar- blah/hm.lala' - [foo, bar, blah, hm, lala] 'foobbbar.. xyz' - [foo, bbbar, xyz] obviously a for loop catching just chars could do the trick, but I'm looking for a more elegant way. Anyone can help? A simple regular expression would work: import re s = 'foo bar- blah/hm.lala' re.findall(r\w+,s) ['foo', 'bar', 'blah', 'hm', 'lala'] -- http://mail.python.org/mailman/listinfo/python-list
Re: Simple regex with whitespaces
Which of course does not work. I cannot express the fact: sentence
have 0 or 1 whitespace, separation of group have two or more
whitespaces.
Any suggestion ? Thanks a bunch !
How about this:
import re
s = 'hello world how are you'
re.split(r\s{2,},s)
['', 'hello world', 'how are you']
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Re: (easy question) Find and replace multiple items
ds4ff1z wrote: Hello, i'm looking to find and replace multiple characters in a text file (test1). I have a bunch of random numbers and i want to replace each number with a letter (such as replace a 7 with an f and 6 with a d). I would like a suggestion on an a way to do this. Thanks how about: import string text1 = foo bar 12 spam joe876 table = string.maketrans(0123456789,uydnwkdfpx) text1.translate(table) 'foo bar yd spam joepfd' Mark Peters -- http://mail.python.org/mailman/listinfo/python-list
Re: Built-in Exceptions - How to Find Out Possible Errno's
I did find this but it doesn't have numbers and I can't tell if it's even what I'm looking for: http://docs.python.org/lib/module-errno.html Error number picked at random: import errno print errno.errorcode.keys() [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 27, 28, 29, 30, 31, 32, 33, 34, 36, 38, 39, 40, 41, 42, 1, 10004, 10009, 10013, 10014, 10022, 10024, 10035, 10036, 10037, 10038, 10039, 10040, 10041, 10042, 10043, 10044, 10045, 10046, 10047, 10048, 10049, 10050, 10051, 10052, 10053, 10054, 10055, 10056, 10057, 10058, 10059, 10060, 10061, 10062, 10063, 10064, 10065, 10066, 10067, 10068, 10069, 10070, 10071, 10091, 10092, 10093, 10101] print errno.errorcode[10] ECHILD or import os print os.strerror(10) No child processes Hope this helps, Mark Peters -- http://mail.python.org/mailman/listinfo/python-list
Re: Built-in Exceptions - How to Find Out Possible Errno's
Gregory Piñero wrote: Thanks Mark, that does help, but what is this errno module? I mean, does it apply to OSError or to IOError or both? My guess is that the IOError will return the underlying operating system error, but that's just a guess (and no time to dig for the answer right now) Mark -- http://mail.python.org/mailman/listinfo/python-list
Re: Built-in Exceptions - How to Find Out Possible Errno's
A quick test: try: f = open(foo,r) except IOError, error: print errno.errorcode[error.errno] ENOENT It looks to me like your if statement should be as simple as: if error.errno == errno.ENOENT: print os.strerror(error.errno) Mark -- http://mail.python.org/mailman/listinfo/python-list
