Re: Rappresenting infinite
On Jun 27, 6:41 am, andrea [EMAIL PROTECTED] wrote: I would like to have a useful rappresentation of infinite, is there already something?? from numpy import inf -- http://mail.python.org/mailman/listinfo/python-list
Re: What was that web interaction library called again?
On Jun 22, 11:19 am, Harald Korneliussen [EMAIL PROTECTED] wrote: Hi, I remember I came across a python library that made it radically simple to interact with web sites, connecting to gmail and logging in with four or five lines, for example. I thought, that's interesting, I must look into it sometime. Now there's this child I know who asked me about programming, especially programs that could do things like this, how difficult it was, and so on. I mentioned how I though Python was a good intro to programming, and there was a library which was perfect for what he wanted. httplib2? -- http://mail.python.org/mailman/listinfo/python-list
Re: WSGI with mod_python (was: Python, WSGI, legacy web application)
Ben Finney wrote: I was under the impression that WSGI in mod_python was a rather kludgy way to do WSGI, but I don't know what the alternatives are. CGI? Python http server (e.g. CherryPy)? Something else? You can use FastCGI or SCGI too, with Apache, lighttpd or Cherokee. I have a short description of different ways to run a WSGI app here: http://pydap.org/docs/server.html Though it's focused on a specific WSGI app I wrote it uses Paste Deploy, so you can generalize it easily. --Rob -- http://mail.python.org/mailman/listinfo/python-list
Re: Dictionaries
Lad wrote:
Let's suppose I have
a={'c':1,'d':2}
b={'c':2}
but
a.update(b)
will make
{'c': 2, 'd': 2}
and I would need
{'c': 3, 'd': 2}
(because `c` is 1 in `a` dictionary and `c` is 2 in `b` dictionary, so
1+2=3)
How can be done that?
dict([(k, a.get(k, 0) + b.get(k,0)) for k in set(a.keys() + b.keys())])
--
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Re: What value should be passed to make a function use the default argument value?
LaundroMat wrote: Suppose I have this function: def f(var=1): return var*2 What value do I have to pass to f() if I want it to evaluate var to 1? I know that f() will return 2, but what if I absolutely want to pass a value to f()? None doesn't seem to work.. If you *absolutely* want to pass a value and you don't know the default value (otherwise you could just pass it): import inspect v = inspect.getargspec(f)[3][0] # first default value f(v) 2 -- http://mail.python.org/mailman/listinfo/python-list
Compile AST to bytecode?
Hi, I would like to compile an AST to bytecode, so I can eval it later. I tried using parse.compileast, but it fails: import compiler, parser ast = compiler.parse(42) parser.compileast(ast) Traceback (most recent call last): File stdin, line 1, in ? TypeError: compilest() argument 1 must be parser.st, not instance Any hints? TIA, --Rob -- http://mail.python.org/mailman/listinfo/python-list
Re: Compile AST to bytecode?
Duncan Booth wrote: I would like to compile an AST to bytecode, so I can eval it later. I'm not sure there are any properly documented functions for converting an AST to a code object, so your best bet may be to examine what a pycodegen class like Expression or Module actually does. Thanks, Duncan. It worked perfectly. :-) For arbitrary nodes I just had to wrap them inside an Expression node: ast = compiler.ast.Expression(node) ast.filename = 'dummy' c = compiler.pycodegen.ExpressionCodeGenerator(ast) obj = eval(c.getCode(), scope) --Rob -- http://mail.python.org/mailman/listinfo/python-list
Re: ancestor class' __init__ doesn't call other methods
Luis P. Mendes wrote: Method a() is not called. Why is this? What is the best option to solve this? Have Cotacoes returning values and not to be an ancestor class of CruzaEmas? It works for me, after rearranging your code a little bit: class Ema: pass class Sistema: def __init__(self, par): cruza_ema = CruzaEmas(par) class Cotacoes: def __init__(self, par): print par: , par self.a() def a(self): print ff class CruzaEmas(Ema, Cotacoes): def __init__(self, par): Cotacoes.__init__(self, par) s = Sistema(par) --Rob -- http://mail.python.org/mailman/listinfo/python-list
Re: Where to find fpconst?
Anybody know where I can find fpconst? I uploaded the lastest copy I could find to the Cheese Shop (http://www.python.org/pypi/fpconst/). I'm not affiliated in any way with fpconst, btw. Rob -- http://mail.python.org/mailman/listinfo/python-list
