Re: list problem...
On Wed, 29 Sep 2010 05:52:32 -0700, bruno.desthuilli...@gmail.com wrote: On 29 sep, 14:17, Steven D'Aprano st...@remove-this- cybersource.com.au wrote: On Tue, 28 Sep 2010 20:11:51 +0100, Rog wrote: On Tue, 28 Sep 2010 11:59:08 -0700, geremy condra wrote: On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote: Hi all, Have been grappling with a list problem for hours... a = [2, 3, 4, 5,.] b = [4, 8, 2, 6,.] Basicly I am trying to place a[0], b[0] in a seperate list IF a[2] and b[2] is present. I have tried sets, zip etc with no success. I am tackling Euler projects with Python 3.1, with minimal knowledge, and having to tackle the language as I progress. Enjoyable frustration :) I'm not clear on what your actual problem is, could you restate it? It sounds like you want to copy the ith element out of a and b into some other list- call it c- when the (i+2)th element meets some condition. What's the condition? Geremy Condra The condition is that the i-th element is inverted, but not equal. eg 4,2 - 2,4 , 34,5 - 5,34 etc. Hope that is clearer. Clear as mud. Perhaps you should given an example. Given input a = [2, 3, 4, 5, 6, 7] b = [4, 8, 2, 6, 10, 42] what output are you expecting, AFAICT, the OP expects [2, 4] in this case, but it's not clear what he'd expect for let's say: a = [2, 3, 21, 4, 5, 6, 7] b = [4, 8, 22, 2, 6, 10, 42] (the 'reversed' pair is at i+3, not i+2) or a = [0, 2, 3, 4, 5, 6, 7] b = [3, 4, 8, 2, 6, 10, 42] (the first pair is at pos 1, not 0) or a = [2, 3, 4, 8, 6, 7] b = [4, 8, 2, 3, 10, 42] (there's a second 'non-reversed/reversed' match at positions resp. 1 3) It is true that I would have needed any 'non-reversed/reversed' pairs, these would have been the amicable pairs I was looking for. The method to recognise them eluded me. Eyes are not good enough :) I have now joined Python-List and will follow the correct route. I have used a method suggested that has made the problem redundant, though it will bug me from now on. g = [] def divsum(n): return sum(i for i in range(1, n) if not n % i) for x in range(1, 2, -1): c = divsum(x) v = divsum(c) if v == x and v != c: g.append(divsum(x)) else: continue print(sum(g)) -- Rog http://www.rog.pynguins.com -- http://mail.python.org/mailman/listinfo/python-list
list problem...
Hi all, Have been grappling with a list problem for hours... a = [2, 3, 4, 5,.] b = [4, 8, 2, 6,.] Basicly I am trying to place a[0], b[0] in a seperate list IF a[2] and b[2] is present. I have tried sets, zip etc with no success. I am tackling Euler projects with Python 3.1, with minimal knowledge, and having to tackle the language as I progress. Enjoyable frustration :) -- Rog http://www.rog.pynguins.com -- http://mail.python.org/mailman/listinfo/python-list
Re: list problem...
On Tue, 28 Sep 2010 11:59:08 -0700, geremy condra wrote: On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote: Hi all, Have been grappling with a list problem for hours... a = [2, 3, 4, 5,.] b = [4, 8, 2, 6,.] Basicly I am trying to place a[0], b[0] in a seperate list IF a[2] and b[2] is present. I have tried sets, zip etc with no success. I am tackling Euler projects with Python 3.1, with minimal knowledge, and having to tackle the language as I progress. Enjoyable frustration :) I'm not clear on what your actual problem is, could you restate it? It sounds like you want to copy the ith element out of a and b into some other list- call it c- when the (i+2)th element meets some condition. What's the condition? Geremy Condra The condition is that the i-th element is inverted, but not equal. eg 4,2 - 2,4 , 34,5 - 5,34 etc. Hope that is clearer. Thanks for the response. -- Rog http://www.rog.pynguins.com -- http://mail.python.org/mailman/listinfo/python-list
http access produces 503
I am porting a simple code from Perl, the website asks for usr/pwd and
the server's side Perl script makes atemp ftp dir for file upload.
The original Perl script connects okay, does its job. The same URL
stuffed into FF3 performs the same way.
My Python script I am sweating out for past four days (noob!) gets
consistently 503, even with user agen set to: Mozilla/5.0 (Windows;
U; Windows NT 5.1; it; rv:1.8.1.11) Gecko/20071127 Firefox/2.0.0.11.
Snippets of relevant code below.
Please, help me understand how this same code lets me log in into my
router usr/pwd running .asp, but this !...@#$% perl script returns to me
w/503 c*ap?
Thank you.
Do I need to set any proxy? The server is on intranet and the FF3 is
set to proxy. The original Perl script did not use any proxy setting.
pre
url = http://example.com/ftpsetup.pl?username=boofanodeid=42
#
# create a password manager
password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm()
# Add the username and password.
# If we knew the realm, we could use it instead of ``None``.
password_mgr.add_password(None, url, uid, pcode)
handler = urllib2.HTTPBasicAuthHandler(password_mgr)
class Mopener(URLopener): version = Mozilla/5.0 (Windows; U;
Windows NT 5.1; it; rv:1.8.1.11) Gecko/20071127 Firefox/2.0.0.11
opener = Mopener()
# create opener (OpenerDirector instance)
opener = urllib2.build_opener(handler)
opener.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U;
Windows NT 5.1; it; rv:1.8.1.11) Gecko/20071127 Firefox/2.0.0.11')]
opener.version = Mozilla/5.0 (Windows; U; Windows NT 5.1; it; rv:
1.8.1.11) Gecko/20071127 Firefox/2.0.0.11
print opener.version
# timeout in seconds
timeout = 10
socket.setdefaulttimeout(timeout)
# Install the opener all calls to urllib2.urlopen use our opener.
urllib2.install_opener(opener)
try:
response = opener.open(url)
# http://www.useragent.org/; tested okay!!!
printok = 1
except:
print error 1
#
output from the above:
Mozilla/5.0 (Windows; U; Windows NT 5.1; it; rv:1.8.1.11) Gecko/
20071127 Firefox/2.0.0.11
error 1
Error code: 503
('Service Unavailable', 'The server cannot process the request due to
a high load')
/pre
--
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