Re: email questions
Yes, I was doing something wrong: I was connecting to the localhost
after instantiation. All better now.
Thanks for the tips!
Scott
On Feb 8, 2006, at 11:04 AM, Carsten Haese wrote:
>
> Then you're doing something wrong. The line
>
> s = smtplib.SMTP("mail.ispname.net") instantiates an SMTP instance and
> connects it. Are you doing s.connect() afterwards? If yes, don't do
> that, it'll try to connect to the local host, which is not an smtp
> server.
>
> If you want to separate instantiation and connection, do this:
>
> s = smtplib.SMTP()
> s.connect("mail.ispname.net")
>
> -Carsten
>
>
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Re: email questions
Seems I'm still having issues with syntax.
From what I can tell from my mail client, my outgoing mail server
name is either
mail..net
or
mail..net:@.com
The former yields the same socket error on connect() that I reported
earlier. The latter yields a "nonnumeric port" error upon
instantiation. Instantiating with the port number,
s = smtplib.SMTP("mail..net:@.com",
portNum)
yields the following error:
socket.gaierror: (7, 'No address associated with nodename')
Suggestions?
Thanks again
Scott
On Feb 8, 2006, at 9:47 AM, Carsten Haese wrote:
> On Wed, 2006-02-08 at 12:34, Scott Frankel wrote:
>> I'm looking for a way to send a simple, plain text email message
>> using Python. My initial attempts are failing with the following
>> error:
>>
>> socket.error: (61, 'Connection refused')
>>
>> Does this imply that I do not have the machine's smtp server
>> running?
>
> Yes.
>
>> (I don't; and I'd like to avoid setting it up.)
>
> You don't have to set up an smtp server to use smtplib. You should be
> able to use your ISP's outgoing mail server, as in
>
> s = smtplib.SMTP("")
>
> HTH,
>
> Carsten.
>
>
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email questions
I'm looking for a way to send a simple, plain text email message using Python. My initial attempts are failing with the following error: socket.error: (61, 'Connection refused') Does this imply that I do not have the machine's smtp server running? (I don't; and I'd like to avoid setting it up.) I'm following example code in the lib ref docs: >>> s = smtplib.SMTP() >>> s.connect() Traceback (most recent call last): File "", line 1, in ? File "/Library/Frameworks/Python.framework/Versions/2.4/lib/ python2.4/smtplib.py", line 303, in connect raise socket.error, msg socket.error: (61, 'Connection refused') Python 2.4.1 MacOSX 10.4.3 Is there a better/easier way to send a plain text message? Thanks in advance! Scott -- http://mail.python.org/mailman/listinfo/python-list
Re: wxPython vs. pyQt
I have just started using wxPython. I selected it over pyQT for licensing reasons. I'm no gui app expert. But that said, I've found the toolkit approachable and the user community very helpful. Scott On Mar 16, 2005, at 9:11 PM, [EMAIL PROTECTED] wrote: I've narrowed down my toolkit selection for my project to wxPython and pyQt, and now i'd like to hear any opinions, war stories, peeves, etc, about them, particularly from anyone who's used _both_toolkits_. I'm only mildly interested in the IDEs and UI designers for each, as i want to do as much as i can in just Xemacs and xterm. Feel free to rant, rave, pontificate, whatever. t.i.a., E -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
Re: file descriptors & fdopen
foo = open('foo.txt', 'w')
duh.
Thanks -
Scott
On Dec 6, 2004, at 11:27 AM, Scott Frankel wrote:
Why does os.fdopen('foo.txt', 'w') require an integer?
Ultimately, I want to create a new file on disk.
Funny, I can't seem to suss-out how to create a new file without
resorting
to os.system('touch foo.txt'). ... Or maybe not so funny ...
>>> foo = os.fdopen('foo.txt', 'w')
Traceback (most recent call last):
File "", line 1, in ?
TypeError: an integer is required
Thanks in advance!
Scott
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file descriptors & fdopen
Why does os.fdopen('foo.txt', 'w') require an integer?
Ultimately, I want to create a new file on disk.
Funny, I can't seem to suss-out how to create a new file without
resorting
to os.system('touch foo.txt'). ... Or maybe not so funny ...
>>> foo = os.fdopen('foo.txt', 'w')
Traceback (most recent call last):
File "", line 1, in ?
TypeError: an integer is required
Thanks in advance!
Scott
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Re: knowing a file's own name
Thanks for the responses!
I'd forgotten about using the sys module:
import sys
filename = sys.argv[0]
Using "__file__" also works.
Thanks
Scott
On Nov 29, 2004, at 9:37 AM, Scott Frankel wrote:
I'm looking for a way to identify a filename remotely. Put
differently,
is there a way a file can get its own name from its globals()?
doit.py calls exec() on a second py script, tpairs.py, to obtain a
dict of the
globals in tpairs.py. How can I add the filename, "tpairs.py," to the
resulting dict?
i.e.:
# - - - - - - - - - - - - - - - -
# -- tpairs.py
# - - - - - - - - - - - - - - - -
this = "this"
that = "that"
gdict = globals()
# - - - - - - - - - - - - - - - -
# -- doit.py
# - - - - - - - - - - - - - - - -
#!/usr/bin/env python
theFile = "./tpairs.py"
theDict = {}
execfile(theFile, theDict)
# somehow add theFile to gdict, i.e.:
# gdict['theFile'] = theFile
Thanks in advance!
Scott
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knowing a file's own name
I'm looking for a way to identify a filename remotely. Put differently,
is there a way a file can get its own name from its globals()?
doit.py calls exec() on a second py script, tpairs.py, to obtain a dict
of the
globals in tpairs.py. How can I add the filename, "tpairs.py," to the
resulting dict?
i.e.:
# - - - - - - - - - - - - - - - -
# -- tpairs.py
# - - - - - - - - - - - - - - - -
this = "this"
that = "that"
gdict = globals()
# - - - - - - - - - - - - - - - -
# -- doit.py
# - - - - - - - - - - - - - - - -
#!/usr/bin/env python
theFile = "./tpairs.py"
theDict = {}
execfile(theFile, theDict)
# somehow add theFile to gdict, i.e.:
# gdict['theFile'] = theFile
Thanks in advance!
Scott
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