Re: What's the neatest way of getting dictionary entries in a specified order?
On Thursday, March 9, 2017 at 1:03:31 AM UTC+5:30, Chris Green wrote:
> I have a fairly simple application that populates a GUI window with
> fields from a database table. The fields are defined/configured by a
> dictionary as follows:-
>
> #
> #
> # Address Book field details, dictionary key is the database column
> #
> dbcol = {}
> dbcol['firstname'] = col('First Name', True, False)
> dbcol['lastname'] = col('Last Name', True, False)
> dbcol['email'] = col('E-Mail', True, True)
> dbcol['phone'] = col('Phone', True, True)
> dbcol['mobile'] = col('Mobile', True, True)
> dbcol['address'] = col('Address', True, False)
> dbcol['town'] = col('Town/City', True, False)
> dbcol['county'] = col('County/Region', True, False)
> dbcol['postcode'] = col('PostCode', True, False)
> dbcol['country'] = col('Country', True, False)
> dbcol['notes'] = col('Notes', True, False)
> dbcol['www'] = col('Web Page', True, True)
> dbcol['categories'] = col('Categories', True, True)
>
> How can I get the fields in the GUI window in the order I want rather
> than the fairly random order that they appear in at the moment?
>
> Currently the GUI fields are populated by a for loop as follows:-
>
> #
> #
> # Put values into the fields
> #
> i = 0
> for col, field in abookdb.dbcol.items():
> print(field.heading)
> if (i > numkeys/2):
> self.addfieldentry(col, address, field, self.rtable, i-numkeys/2)
> else:
> self.addfieldentry(col, address, field, self.ltable, i)
> i = i + 1
>
> The for loop gets the items from the dictionary in an order that isn't
> what I want. How can I configure things so they're in the order I want?
>
> --
> Chris Green
> ·
There is OrderedDict.
https://docs.python.org/2/library/collections.html#collections.OrderedDict
https://docs.python.org/3/library/collections.html#collections.OrderedDict
--
https://mail.python.org/mailman/listinfo/python-list
Re: str.title() fails with words containing apostrophes
On Monday, March 6, 2017 at 2:37:11 PM UTC+5:30, Jussi Piitulainen wrote: > gvm...@gmail.com writes: > > > On Sunday, March 5, 2017 at 11:25:04 PM UTC+5:30, Steve D'Aprano wrote: > >> I'm trying to convert strings to Title Case, but getting ugly results > >> if the words contain an apostrophe: > >> > >> > >> py> 'hello world'.title() # okay > >> 'Hello World' > >> py> "i can't be having with this".title() # not okay > >> "I Can'T Be Having With This" > >> > >> > >> Anyone have any suggestions for working around this? > > [snip sig] > > > import string > > > > txt = "i can't be having with this" > > string.capwords(txt) > > > > That gives you "I Can't Be Having With This" > > > > Hope that helps. > > Won't Steve D'aprano And D'arcy Cain Be Happy Now :) I found it at https://docs.python.org/3/library/string.html#string.capwords :) -- https://mail.python.org/mailman/listinfo/python-list
Re: str.title() fails with words containing apostrophes
On Sunday, March 5, 2017 at 11:25:04 PM UTC+5:30, Steve D'Aprano wrote: > I'm trying to convert strings to Title Case, but getting ugly results if the > words contain an apostrophe: > > > py> 'hello world'.title() # okay > 'Hello World' > py> "i can't be having with this".title() # not okay > "I Can'T Be Having With This" > > > Anyone have any suggestions for working around this? > > > > -- > Steve > “Cheer up,” they said, “things could be worse.” So I cheered up, and sure > enough, things got worse. import string txt = "i can't be having with this" string.capwords(txt) That gives you "I Can't Be Having With This" Alternatively txt = "i can't be having with this" ' '.join([word.capitalize() for word in txt.split()]) will result in: "I Can't Be Having With This" -- https://mail.python.org/mailman/listinfo/python-list
Re: str.title() fails with words containing apostrophes
On Sunday, March 5, 2017 at 11:25:04 PM UTC+5:30, Steve D'Aprano wrote: > I'm trying to convert strings to Title Case, but getting ugly results if the > words contain an apostrophe: > > > py> 'hello world'.title() # okay > 'Hello World' > py> "i can't be having with this".title() # not okay > "I Can'T Be Having With This" > > > Anyone have any suggestions for working around this? > > > > -- > Steve > “Cheer up,” they said, “things could be worse.” So I cheered up, and sure > enough, things got worse. import string txt = "i can't be having with this" string.capwords(txt) That gives you "I Can't Be Having With This" Hope that helps. -- https://mail.python.org/mailman/listinfo/python-list
Re: list of the lists - append after search
On Thursday, March 2, 2017 at 9:33:14 PM UTC+5:30, Andrew Zyman wrote:
> Hello,
> please advise.
>
> I'd like search and append the internal list in the list-of-the-lists.
>
> Example:
> ll =[ [a,1], [b,2], [c,3], [blah, 1000] ]
>
> i want to search for the internal [] based on the string field and, if
> matches, append that list with a value.
>
> if internal_list[0] == 'blah':
> ll[ internal_list].append = [ 'new value']
>
> End result:
> ll =[ [a,1], [b,2], [c,3], [blah, 1000, 'new value'] ]
>
>
> I came up with the following, but the second stmnt is not correct:
>
> print [x for x in ll if x[0]== 'blah']
> print ll.index([x for x in ll if x[0]=='blah'])
>
> output:
> ValueError: [['blah', 1]] is not in list
>
>
>
>
> thank you
> AZ
list_of_lists = [['a', 1], ['b', 2], ['c', 3], ['blah', 1000]]
for sublist in list_of_lists:
if sublist[0] == 'blah':
sublist.append('new value')
Hope that helps.
--
https://mail.python.org/mailman/listinfo/python-list
