error

[Prasanna kumar]

Sir/mam,
Fatal error in launcher: Unable to create process using   this is error which I 
am not getting clear with it . so, I request you to help me it.
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Re: Python XMLRPC question

[prasanna]

Thanks a bunch. Qill give it a shot.

--p

On Oct 14, 8:18 pm, Gabriel Genellina gagsl-...@yahoo.com.ar
wrote:
 En Wed, 14 Oct 2009 22:08:09 -0300,prasannaprasa...@ix.netcom.com  
 escribió:

  Out of curiosity--one more thing I haven't yet figured out, is there a
  xmlrpc command I can send that stops or restarts the server?

 If you're using Python 2.6, the easiest way is to register its shutdown()  
 method. Note that it *must* be called from a separate thread (just inherit  
  from ForkingMixIn)

 On earlier versions, overwrite the serve_forever loop (so it reads `while  
 not self._quit: ...`) and add a shutdown() method that sets self._quit to  
 True. You'll need to call shutdown twice in that case.

 === begin xmlrpcshutdown.py ===
 import sys

 def server():
      from SocketServer import ThreadingMixIn
      from SimpleXMLRPCServer import SimpleXMLRPCServer

      # ThreadingMixIn must be included when publishing
      # the shutdown method
      class MyXMLRPCServer(ThreadingMixIn, SimpleXMLRPCServer):
          pass

      print 'Running XML-RPC server on port 8000'
      server = MyXMLRPCServer((localhost, 8000),
          logRequests=False, allow_none=True)
          # allow_none=True because of shutdown
      server.register_function(lambda x,y: x+y, 'add')
      server.register_function(server.shutdown)
      server.serve_forever()

 def client():
      from xmlrpclib import ServerProxy

      print 'Connecting to XML-RPC server on port 8000'
      server = ServerProxy(http://localhost:8000;)
      print 2+3=, server.add(2, 3)
      print asking server to shut down
      server.shutdown()

 if sys.argv[1]==server: server()
 elif sys.argv[1]==client: client()
 === end xmlrpcshutdown.py ===

 C:\TEMPstart python xmlrpcshutdown.py server

 C:\TEMPpython xmlrpcshutdown.py client
 Connecting to XML-RPC server on port 8000
 2+3= 5
 asking server to shut down

 C:\TEMP

 --
 Gabriel Genellina

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Re: Python XMLRPC question

[prasanna]

On Oct 13, 1:22 pm, Gabriel Genellina gagsl-...@yahoo.com.ar
wrote:
 En Tue, 13 Oct 2009 16:55:09 -0300, Falcolas garri...@gmail.com escribió:





  On Oct 13, 12:47 pm,prasannaprasa...@ix.netcom.com wrote:
  In using Python's XMLRPC, there is a statement that gets printed on
  stdout of the form:
                   localhost - - [12/Oct/2009 23:36:12] POST /RPC2 HTTP/
  1.0 200 -

  Where does this message originate? Can I turn it off, or at least
  redirect it into a logging file? I am planning to run the server code
  automatically at start up and wouldn't have a terminal window open to
  get this message. I guess I could redirect/pipe it to a file, but it
  would be more useful I could send it to the same log file that I have
  the server writing other messages to.

  Thanks for any help.

  Looking back through the SimpleXMLRPCServer code, it appears that this
  happens if the logRequests parameter in the SimpleXMLRPCServer class
  initialization is set to True, which it is by default. The underlying
  implementation of the logging is in BaseHTTPServer.py, which uses
  sys.stderr.

  Looks like the simplest way to change that would be to inherit from
  the SimpleXMLRPCRequestHandler class and implement your own
  log_request method. You could then pass that to the SimpleXMLRPCServer
  constructor.

 I think it's easier to pass logRequests=False when creating the server.

 --
 Gabriel Genellina

Thanks. That helped get rid of the message.

Out of curiosity--one more thing I haven't yet figured out, is there a
xmlrpc command I can send that stops or restarts the server?

--p
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Python XMLRPC question

[prasanna]

In using Python's XMLRPC, there is a statement that gets printed on
stdout of the form:
 localhost - - [12/Oct/2009 23:36:12] POST /RPC2 HTTP/
1.0 200 -

Where does this message originate? Can I turn it off, or at least
redirect it into a logging file? I am planning to run the server code
automatically at start up and wouldn't have a terminal window open to
get this message. I guess I could redirect/pipe it to a file, but it
would be more useful I could send it to the same log file that I have
the server writing other messages to.

Thanks for any help.
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Re: New Bee

[Prasanna]

Thanx for ur info.

Prasanna

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New Bee

[Prasanna]

Hi all,
I am new to this group.I am willing to learn PYTHON can anyone suggest
me where to start.I have installed PYTHON 2.4 windows platform.Where
can I get books for beginners.How to go about?.It would be helpful if
anyone is will to guide me.

Thanks and Regards,
Prasanna

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