A smallish Tkinter question
""" What I want: A little window to open with a 0 in it. Every second, the 0 should increment by 1. What I get: A one second delay, see the window with a 1 in it, and then nothing appears to happen. Never see the 0, never see a 2. Any quick clues? Thanks. Nick. (Python 2.4, Win98). """ from Tkinter import * from time import sleep class Clock: def __init__(self, parent): self.time = 0 self.display = Label(parent) self.display["font"] = "Arial 16" self.display["text"] = str(self.time) self.display.pack() def run(self): #also tried self,parent sleep(1.0) self.time = self.time + 1 self.display["text"] = str(self.time) win = Tk() app = Clock(win) app.run() #also tried run(win) with self,parent above win.mainloop() -- http://mail.python.org/mailman/listinfo/python-list
Re: A smallish Tkinter question
[EMAIL PROTECTED] wrote: """ What I want: A little window to open with a 0 in it. Every second, the 0 should increment by 1. What I get: A one second delay, see the window with a 1 in it, and then nothing appears to happen. Never see the 0, never see a 2. Any quick clues? Thanks. Nick. (Python 2.4, Win98). Your run() method doesn't loop, so it only updates once. But there is a fundamental problem; the run() method is called before you even start Tkinter by calling mainloop(). That's why you never see the 0. If you change run to loop forever, it won't return and you will never even get to the mainloop() call. Tkinter supports timed, asynchronous callbacks. Here is a program that uses a callback to display a ticker: from Tkinter import * count = 0 def update(): ''' Callback method updates the label ''' global count count += 1 label.configure(text=str(count)) # Schedule another callback root.after(1000, update) root=Tk() label=Label(root,text="0") label.pack() b=Button(root,text="Bye",command='exit') b.pack() # Schedule the initial callback root.after(1000, update) root.mainloop() Kent """ from Tkinter import * from time import sleep class Clock: def __init__(self, parent): self.time = 0 self.display = Label(parent) self.display["font"] = "Arial 16" self.display["text"] = str(self.time) self.display.pack() def run(self): #also tried self,parent sleep(1.0) self.time = self.time + 1 self.display["text"] = str(self.time) win = Tk() app = Clock(win) app.run() #also tried run(win) with self,parent above win.mainloop() -- http://mail.python.org/mailman/listinfo/python-list
Re: A smallish Tkinter question
[EMAIL PROTECTED] wrote: """ What I want: A little window to open with a 0 in it. Every second, the 0 should increment by 1. What I get: A one second delay, see the window with a 1 in it, and then nothing appears to happen. Never see the 0, never see a 2. Any quick clues? Thanks. Nick. (Python 2.4, Win98). """ from Tkinter import * from time import sleep class Clock: def __init__(self, parent): self.time = 0 self.display = Label(parent) self.display["font"] = "Arial 16" self.display["text"] = str(self.time) self.display.pack() def run(self): #also tried self,parent sleep(1.0) self.time = self.time + 1 self.display["text"] = str(self.time) win = Tk() app = Clock(win) app.run() #also tried run(win) with self,parent above win.mainloop() Nick, Look at the after method of the Tk widget also google for Tkinter clock examples should get results Cheers, Martin. -- http://mail.python.org/mailman/listinfo/python-list
Re: A smallish Tkinter question
Mediocre Person wrote: What I want: A little window to open with a 0 in it. Every second, the 0 should increment by 1. What I get: A one second delay, see the window with a 1 in it, and then nothing appears to happen. Never see the 0, never see a 2. Any quick clues? Thanks. Nick. (Python 2.4, Win98). simple solution: def run(self): #also tried self,parent sleep(1.0) self.time = self.time + 1 self.display["text"] = str(self.time) self.update() # make sure to process all outstanding events smarter solution: def run(self): self.display["text"] = str(self.time) self.time = self.time + 1 self.after(1000, self.run) # no need to use update in this case even smarter solution: import time TICK = 1.0 # time between updates, in seconds def run(self): self.display["text"] = str(self.time) self.time = self.time + 1 delay = TICK - (time.time() % TICK) self.after(int(delay*1000), self.run) # no need to use update in this case also see: http://tkinter.unpythonic.net/wiki/TkinterDiscuss -- http://mail.python.org/mailman/listinfo/python-list
Re: A smallish Tkinter question
***Many*** thanks. I was getting right confused, but this is pretty clear. I had also tried, in run(...): while True: sleep(1.0) ... But it's clear from your response why this also didn't work! Nick. -- http://mail.python.org/mailman/listinfo/python-list
Re: A smallish Tkinter question
Hello Nick, > """ > What I want: A little window to open with a 0 in it. Every second, the > 0 should increment by 1. > What I get: A one second delay, see the window with a 1 in it, and then > nothing appears to happen. Never see the 0, never see a 2. Any quick > clues? Thanks. Nick. (Python 2.4, Win98). > """ Read: http://www.pythonware.com/library/tkinter/introduction/ and mainly http://www.pythonware.com/library/tkinter/introduction/x9507-alarm-handlers-and-other.htm from Tkinter import * class Clock(Frame): #<<< def __init__(self, parent): Frame.__init__(self, parent) #<<< self.time = 0 self.display = Label(parent) self.display["font"] = "Arial 16" self.display["text"] = str(self.time) self.display.pack() def run(self): #<<< self.loop() def loop(self): #<<< self.time = self.time + 1 self.display["text"] = str(self.time) self.after(1000, self.loop) win = Tk() app = Clock(win) app.run() #also tried run(win) with self,parent above win.mainloop() HTH. -- Miki Tebeka <[EMAIL PROTECTED]> http://tebeka.bizhat.com The only difference between children and adults is the price of the toys pgp6U4b8lkFDH.pgp Description: PGP signature -- http://mail.python.org/mailman/listinfo/python-list
