Re: Do I need a nested lambda to do this?
very nice bill. thanks all. -- http://mail.python.org/mailman/listinfo/python-list
Re: Do I need a nested lambda to do this?
raoul wrote: I can't figure this one out. Trying to be unnecessarily functional I suspect. I have the following lists. vals = [1.000,2.344,4.2342] tab = [((0,1),(0,3),(0,4)), ((2,2),(3,0),(3,9)), ((3,4),(6,3),(7,1))] I'm trying to create a one liner using map/reduce/lambda/zip(* etc to do replace the first element of each pair in each row by the the values in vals as follows: tab = [((1.000,1),(1.000,3),(1.000,4)), ((2.344,2),(2.344,0),(2.344,9)), ((4.2342,4),(4.2342,3),(4.2342,1))] I don't know about map/etc but it's pretty easy using list comp and gen exp: print [ tuple( (val, t[1]) for t in tt ) for val, tt in zip(vals, tab) ] Kent -- http://mail.python.org/mailman/listinfo/python-list
Re: Do I need a nested lambda to do this?
On 4/25/05, R. C. James Harlow <[EMAIL PROTECTED]> wrote: > On Tuesday 26 April 2005 00:34, raoul wrote: > > I can't figure this one out. Trying to be unnecessarily functional I > > suspect. > > With list comprehensions: > > Python 2.3.4 (#1, Mar 26 2005, 20:54:10) > [GCC 3.3.4 20040623 (Gentoo Linux 3.3.4-r1, ssp-3.3.2-2, pie-8.7.6)] on linux2 > Type "help", "copyright", "credits" or "license" for more information. > >>> vals = [1.000,2.344,4.2342] > >>> tabs = [((0,1),(0,3),(0,4)), > ...((2,2),(3,0),(3,9)), > ...((3,4),(6,3),(7,1))] > >>> [(tuple([(vals[index],subtab[1]) for subtab in tab])) for index,tab in > enumerate(tabs)] > [((1.0, 1), (1.0, 3), (1.0, 4)), ((2.3439, 2), > (2.3439, 0), (2.3439, 9)), ((4.23420004, 4), > (4.23420004, 3), (4.23420004, 1))] Slightly nicer, I think: >>> vals [1.0, 2.3439, 4.23420004] >>> tabs [((0, 1), (0, 3), (0, 4)), ((2, 2), (3, 0), (3, 9)), ((3, 4), (6, 3), (7, 1))] >>> [tuple([(v, t[1]) for t in tab]) for v, tab in zip(vals, tabs)] [((1.0, 1), (1.0, 3), (1.0, 4)), ((2.3439, 2), (2.3439, 0), (2.3439, 9)), ((4.23420004, 4), (4.23420004, 3), (4.23420004, 1))] Peace Bill Mill bill.mill at gmail.com > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
Re: Do I need a nested lambda to do this?
On Tuesday 26 April 2005 00:34, raoul wrote: > I can't figure this one out. Trying to be unnecessarily functional I > suspect. With list comprehensions: Python 2.3.4 (#1, Mar 26 2005, 20:54:10) [GCC 3.3.4 20040623 (Gentoo Linux 3.3.4-r1, ssp-3.3.2-2, pie-8.7.6)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> vals = [1.000,2.344,4.2342] >>> tabs = [((0,1),(0,3),(0,4)), ...((2,2),(3,0),(3,9)), ...((3,4),(6,3),(7,1))] >>> [(tuple([(vals[index],subtab[1]) for subtab in tab])) for index,tab in enumerate(tabs)] [((1.0, 1), (1.0, 3), (1.0, 4)), ((2.3439, 2), (2.3439, 0), (2.3439, 9)), ((4.23420004, 4), (4.23420004, 3), (4.23420004, 1))] -- http://mail.python.org/mailman/listinfo/python-list
Do I need a nested lambda to do this?
I can't figure this one out. Trying to be unnecessarily functional I suspect. I have the following lists. vals = [1.000,2.344,4.2342] tab = [((0,1),(0,3),(0,4)), ((2,2),(3,0),(3,9)), ((3,4),(6,3),(7,1))] I'm trying to create a one liner using map/reduce/lambda/zip(* etc to do replace the first element of each pair in each row by the the values in vals as follows: tab = [((1.000,1),(1.000,3),(1.000,4)), ((2.344,2),(2.344,0),(2.344,9)), ((4.2342,4),(4.2342,3),(4.2342,1))] I'm pretty sure there's a oneline way to do this. Naturally, one could loop mindlessly but this is my self-imposed programming challenge for the day and I'm not feeling much love from my python. -- http://mail.python.org/mailman/listinfo/python-list
