Re: File Path retrieving problem
Hi Dennis Thanks for your reply and also the detailed explanation.
Or do you mean you want something that, given a bare name, searches
your file system to find where a file with that name actually is?
Yes, this is what i exactly needed.
I have found something interesting to do this using the os.walk(path)
function, and it worked
I am pasting the code which i used for this:
testpath=rC:\\
logpath=rC:\Pathfinder.txt
csvpath=rC:\Pathfinder.csv
import os, csv
def logData(d={}, logfile=c://filename999.txt, separator=\n):
Takes a dictionary of values and writes them to the provided
file path
logstring=separator.join([str(key)+: +d[key] for key in
d.keys()])+\n
f=open(logfile,'a')
f.write(logstring)
f.close()
return
def walker(topPath,csvpath):
fDict={}
logDict={}
limit=1000
freed_space=0
items=0
fileHandle = csv.writer(open(csvpath, 'w'))
fileHandle.writerow(['Index','Path'])
for root, dirs, files in os.walk(topPath):
for name in files:
fpath=os.path.join(root,name)
logDict[Name]=name
logDict[Path]=fpath
if name.find(NEWS):
continue
else:
logData(logDict, logpath, \t)
fDict[items] = name
items=len(fDict.keys())
fileHandle.writerow([items,fpath])
print Dict entry: ,items,
print Path: ,fpath
if items limit:
break
if items limit:
break
walker(testpath,csvpath)
Finally thank you all very much for the patience to listen to me.
Regards,
Sudhir
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
music24...@gmail.com wrote:
On Feb 26, 9:03 am, Steve Holden st...@holdenweb.com wrote:
music24...@gmail.com wrote:
On Feb 26, 2:35 am, Emile van Sebille em...@fenx.com wrote:
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
Hi,
This is the following code which i have used to retrieve the pathname
of a filename given by the user
filename = self.enText.get() # get the text entered in the
text box
if os.path.exists(filename): # checking if the filename
exists , had replaced it with os.path.exists(os.path.abspath
(filename))
print os.path.abspath(filename)
else:
print Not found
actually i need to list all the files/folders with the given filename
alongwith path and store it in an CSV file with index.
But i am unable to get even a single filepath correctly.
Whatever filename i enter the output is as : C:\Python25\WorkSpace
\xyz
i.e the name i entered is being appended to my workspace and
displayed.
Guys, i am not able to understand what shall i do here...plz help me
out.
Look, we aren't psychic. We can't debug code and directories we can't
see. Work with us here - give us the information we need to help you.
The actual code. A directory listing? Any error messages?
regards
Steve
--
Steve Holden+1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
Hi Steve,
Following is the code which i have written to display a GUI textbox
and get any name entered by the user and search the path of this
filename and then list it into an CSV file.
For this i initially created an textbox widget and added an button to
it.
Now, i have entered a filename (like NEWS.txt) in the text boz,
as you can see when i press the button i retrieve the text and then
search its filepath.
currently i am printing this filepath on the shell.
from Tkinter import *
So this is Python 2.x ...
import os
from os.path import realpath, exists, abspath
import tkMessageBox
import Tkinter
Not sure why you bother to import Tkinter when you have above just
imported everything *from* Tkinter ...
#import filePath
class GUIFrameWork(Frame):
This is the GUI
def __init__(self,master=None):
Initialize yourself
Initialise the base class
Frame.__init__(self,master)
Set the Window Title
self.master.title(Enter Text to search)
Display the main window
with a little bit of padding
self.grid(padx=10,pady=10)
self.CreateWidgets()
def CreateWidgets(self):
self.enText = Entry(self)
self.enText.grid(row=0, column=1, columnspan=3)
Create the Button, set the text and the
command that will be called when the button is clicked
self.btnDisplay = Button(self, text=Display!,
command=self.Display)
self.btnDisplay.grid(row=0, column=4)
def Display(self):
Called when btnDisplay is clicked, displays the contents of
self.enText
filename = self.enText.get()
if os.path.exists(os.path.abspath(filename)):
print os.path.abspath(filename)
First, move this line up one (losing an indent level) so you always
print the full path. This will verify you are looking where you think
you are looking.
else:
print Not found
#tkMessageBox.showinfo(Text, You typed: %s %
os.path.abspath(os.path.dirname(filename)))
#filepath.mydir(self.enText.get())
if __name__ == __main__:
guiFrame = GUIFrameWork()
guiFrame.mainloop()
User Input: NEWS.txt
Output: Not Found (though this file is actually present)
Thanks for the information. I'm wondering whether there might be some
filename encoding issue here, but others may have some better ideas.
regards
Steve
--
Steve Holden+1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
Dennis Lee Bieber wrote: On Wed, 25 Feb 2009 07:37:21 -0800 (PST), music24...@gmail.com declaimed the following in comp.lang.python: WARNING -- I will probably NOT see your response; since 90+% of the spam in comp.lang.python is injected via googlegroups and gmail accounts, my client is configured to filter out messages with a from address having gmail.com. I only found this message by doing fetches on the reference header of the replies that did get by the filter. Well, since it's more likely you'll see this, let me tell you that if you access the group via gmane (as I do) you rarely see the spam anyway. There's been a lot more work on spam filtering lately. regards Steve -- Steve Holden+1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list
File Path retrieving problem
Hi all, I am new to Python, i have installed python 2.5.4 and it is my requirement. I need to retrieve the path of filename in python. I have found some API's to get this: from os.path import realpath print realpath(NEWS.txt) # here NEWS.txt exists and it shows the path of the file as C:\Python25\WorkSpace\NEWS.txt print realpath(abc.txt) # here abc.txt does not exist but still it shows C:\Python25\WorkSpace\abc.txt can anybody tell the reason why Now took some safety measures: found = lexists(realpath(filename)) if found == 0: print Not Found else: print realpath(filename) i have given the filename as NEWS.txt and abc.txt but i am always getting the output as Not Found Can anyone please tell me where am i doing wrong also any suggestions to retrieve the filepath from a given filename is highly appreciated. Thanks in advance. Regards, Sudhir -- http://mail.python.org/mailman/listinfo/python-list
File Path retrieving problem
Hi all, I am new to Python, i have installed python 2.5.4 and it is my requirement. I need to retrieve the path of filename in python. I have found some API's to get this: from os.path import realpath print realpath(NEWS.txt) # here NEWS.txt exists and it shows the path of the file as C:\Python25\WorkSpace\NEWS.txt print realpath(abc.txt) # here abc.txt does not exist but still it shows C:\Python25\WorkSpace\abc.txt can anybody tell the reason why Now took some safety measures: found = lexists(realpath(filename)) if found == 0: print Not Found else: print realpath(filename) i have given the filename as NEWS.txt and abc.txt but i am always getting the output as Not Found Can anyone please tell me where am i doing wrong also any suggestions to retrieve the filepath from a given filename is highly appreciated. Thanks in advance. Regards, Sudhir -- http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
music24...@gmail.com wrote: Hi all, I am new to Python, i have installed python 2.5.4 and it is my requirement. I need to retrieve the path of filename in python. I have found some API's to get this: from os.path import realpath print realpath(NEWS.txt) # here NEWS.txt exists and it shows the path of the file as C:\Python25\WorkSpace\NEWS.txt print realpath(abc.txt) # here abc.txt does not exist but still it shows C:\Python25\WorkSpace\abc.txt can anybody tell the reason why Now took some safety measures: found = lexists(realpath(filename)) if found == 0: print Not Found else: print realpath(filename) i have given the filename as NEWS.txt and abc.txt but i am always getting the output as Not Found Can anyone please tell me where am i doing wrong It seems pretty apparent that lexists() nevert returns a true result. Why not just if os.path.exists(filename): print os.path.realpath(filename) else: print Not found also any suggestions to retrieve the filepath from a given filename is highly appreciated. Well, realpath returns the path of the file targeted after any symbolic links have been evaluated, which may or may not be what you want. Have you looked at os.path.abspath? regards Steve -- Steve Holden+1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
On Feb 25, 8:57 pm, Steve Holden st...@holdenweb.com wrote: music24...@gmail.com wrote: Hi all, I am new to Python, i have installed python 2.5.4 and it is my requirement. I need to retrieve the path of filename in python. I have found some API's to get this: from os.path import realpath print realpath(NEWS.txt) # here NEWS.txt exists and it shows the path of the file as C:\Python25\WorkSpace\NEWS.txt print realpath(abc.txt) # here abc.txt does not exist but still it shows C:\Python25\WorkSpace\abc.txt can anybody tell the reason why Now took some safety measures: found = lexists(realpath(filename)) if found == 0: print Not Found else: print realpath(filename) i have given the filename as NEWS.txt and abc.txt but i am always getting the output as Not Found Can anyone please tell me where am i doing wrong It seems pretty apparent that lexists() nevert returns a true result. Why not just if os.path.exists(filename): print os.path.realpath(filename) else: print Not found also any suggestions to retrieve the filepath from a given filename is highly appreciated. Well, realpath returns the path of the file targeted after any symbolic links have been evaluated, which may or may not be what you want. Have you looked at os.path.abspath? regards Steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ Hi Steve, I have tried your suggested code and also replaced os.path.realpath with os.path.abspath but still getting the same result. I want to know is there any workaround for retrieving the filepaths given only filename Regards, Sudhir -- http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
music24...@gmail.com wrote: On Feb 25, 8:57 pm, Steve Holden st...@holdenweb.com wrote: music24...@gmail.com wrote: Hi all, I am new to Python, i have installed python 2.5.4 and it is my requirement. I need to retrieve the path of filename in python. I have found some API's to get this: from os.path import realpath print realpath(NEWS.txt) # here NEWS.txt exists and it shows the path of the file as C:\Python25\WorkSpace\NEWS.txt print realpath(abc.txt) # here abc.txt does not exist but still it shows C:\Python25\WorkSpace\abc.txt can anybody tell the reason why Now took some safety measures: found = lexists(realpath(filename)) if found == 0: print Not Found else: print realpath(filename) i have given the filename as NEWS.txt and abc.txt but i am always getting the output as Not Found Can anyone please tell me where am i doing wrong It seems pretty apparent that lexists() nevert returns a true result. Why not just if os.path.exists(filename): print os.path.realpath(filename) else: print Not found also any suggestions to retrieve the filepath from a given filename is highly appreciated. Well, realpath returns the path of the file targeted after any symbolic links have been evaluated, which may or may not be what you want. Have you looked at os.path.abspath? regards Steve -- Steve Holden+1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ Hi Steve, I have tried your suggested code and also replaced os.path.realpath with os.path.abspath but still getting the same result. I want to know is there any workaround for retrieving the filepaths given only filename What, you are saying that os.path.exists(filename) is returning false when the file exists? I find that hard to believe. Please display some evidence so I can understand this. regards Steve -- Steve Holden+1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
Steve Holden wrote:
What, you are saying that
os.path.exists(filename)
is returning false when the file exists? I find that hard to believe.
Please display some evidence so I can understand this.
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Peter
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
On Feb 26, 2:35 am, Emile van Sebille em...@fenx.com wrote:
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
Hi,
This is the following code which i have used to retrieve the pathname
of a filename given by the user
filename = self.enText.get() # get the text entered in the
text box
if os.path.exists(filename): # checking if the filename
exists , had replaced it with os.path.exists(os.path.abspath
(filename))
print os.path.abspath(filename)
else:
print Not found
actually i need to list all the files/folders with the given filename
alongwith path and store it in an CSV file with index.
But i am unable to get even a single filepath correctly.
Whatever filename i enter the output is as : C:\Python25\WorkSpace
\xyz
i.e the name i entered is being appended to my workspace and
displayed.
Guys, i am not able to understand what shall i do here...plz help me
out.
Regards,
Sudhir
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
music24...@gmail.com wrote:
On Feb 26, 2:35 am, Emile van Sebille em...@fenx.com wrote:
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
Hi,
This is the following code which i have used to retrieve the pathname
of a filename given by the user
filename = self.enText.get() # get the text entered in the
text box
if os.path.exists(filename): # checking if the filename
exists , had replaced it with os.path.exists(os.path.abspath
(filename))
print os.path.abspath(filename)
else:
print Not found
actually i need to list all the files/folders with the given filename
alongwith path and store it in an CSV file with index.
But i am unable to get even a single filepath correctly.
Whatever filename i enter the output is as : C:\Python25\WorkSpace
\xyz
i.e the name i entered is being appended to my workspace and
displayed.
Guys, i am not able to understand what shall i do here...plz help me
out.
Look, we aren't psychic. We can't debug code and directories we can't
see. Work with us here - give us the information we need to help you.
The actual code. A directory listing? Any error messages?
regards
Steve
--
Steve Holden+1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
On Feb 26, 9:03 am, Steve Holden st...@holdenweb.com wrote:
music24...@gmail.com wrote:
On Feb 26, 2:35 am, Emile van Sebille em...@fenx.com wrote:
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
Hi,
This is the following code which i have used to retrieve the pathname
of a filename given by the user
filename = self.enText.get() # get the text entered in the
text box
if os.path.exists(filename): # checking if the filename
exists , had replaced it with os.path.exists(os.path.abspath
(filename))
print os.path.abspath(filename)
else:
print Not found
actually i need to list all the files/folders with the given filename
alongwith path and store it in an CSV file with index.
But i am unable to get even a single filepath correctly.
Whatever filename i enter the output is as : C:\Python25\WorkSpace
\xyz
i.e the name i entered is being appended to my workspace and
displayed.
Guys, i am not able to understand what shall i do here...plz help me
out.
Look, we aren't psychic. We can't debug code and directories we can't
see. Work with us here - give us the information we need to help you.
The actual code. A directory listing? Any error messages?
regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
Hi Steve,
Following is the code which i have written to display a GUI textbox
and get any name entered by the user and search the path of this
filename and then list it into an CSV file.
For this i initially created an textbox widget and added an button to
it.
Now, i have entered a filename (like NEWS.txt) in the text boz,
as you can see when i press the button i retrieve the text and then
search its filepath.
currently i am printing this filepath on the shell.
from Tkinter import *
import os
from os.path import realpath, exists, abspath
import tkMessageBox
import Tkinter
#import filePath
class GUIFrameWork(Frame):
This is the GUI
def __init__(self,master=None):
Initialize yourself
Initialise the base class
Frame.__init__(self,master)
Set the Window Title
self.master.title(Enter Text to search)
Display the main window
with a little bit of padding
self.grid(padx=10,pady=10)
self.CreateWidgets()
def CreateWidgets(self):
self.enText = Entry(self)
self.enText.grid(row=0, column=1, columnspan=3)
Create the Button, set the text and the
command that will be called when the button is clicked
self.btnDisplay = Button(self, text=Display!,
command=self.Display)
self.btnDisplay.grid(row=0, column=4)
def Display(self):
Called when btnDisplay is clicked, displays the contents of
self.enText
filename = self.enText.get()
if os.path.exists(os.path.abspath(filename)):
print os.path.abspath(filename)
else:
print Not found
#tkMessageBox.showinfo(Text, You typed: %s %
os.path.abspath(os.path.dirname(filename)))
#filepath.mydir(self.enText.get())
if __name__ == __main__:
guiFrame = GUIFrameWork()
guiFrame.mainloop()
User Input: NEWS.txt
Output: Not Found (though this file is actually present)
Regards,
Sudhir
--
http://mail.python.org/mailman/listinfo/python-list
Re: File Path retrieving problem
On Feb 26, 3:16 pm, music24...@gmail.com wrote:
On Feb 26, 9:03 am, Steve Holden st...@holdenweb.com wrote:
music24...@gmail.com wrote:
On Feb 26, 2:35 am, Emile van Sebille em...@fenx.com wrote:
Peter Otten wrote:
Maybe it's about access rights?
$ mkdir alpha
$ touch alpha/beta
$ python -cimport os; print os.path.exists('alpha/beta')
True
$ chmod u-x alpha
$ python -cimport os; print os.path.exists('alpha/beta')
False
$
I Don't know how this is handled on Windows...
Here's one way
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\mkdir alpha
C:\touch alpha\beta # cygwin at work here...
C:\python -cimport os; print os.path.exists('alpha/beta')
True
C:\cacls alpha /E /R Everyone
processed dir: C:\alpha
C:\cacls alpha /E /R Users
processed dir: C:\alpha
C:\cacls alpha /E /R Administrators
processed dir: C:\alpha
C:\python -cimport os; print os.path.exists('alpha/beta')
False
Hi,
This is the following code which i have used to retrieve the pathname
of a filename given by the user
filename = self.enText.get() # get the text entered in the
text box
if os.path.exists(filename): # checking if the filename
exists , had replaced it with os.path.exists(os.path.abspath
(filename))
print os.path.abspath(filename)
else:
print Not found
actually i need to list all the files/folders with the given filename
alongwith path and store it in an CSV file with index.
But i am unable to get even a single filepath correctly.
Whatever filename i enter the output is as : C:\Python25\WorkSpace
\xyz
i.e the name i entered is being appended to my workspace and
displayed.
Guys, i am not able to understand what shall i do here...plz help me
out.
Look, we aren't psychic. We can't debug code and directories we can't
see. Work with us here - give us the information we need to help you.
The actual code. A directory listing? Any error messages?
regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
Hi Steve,
Following is the code which i have written to display a GUI textbox
and get any name entered by the user and search the path of this
filename and then list it into an CSV file.
For this i initially created an textbox widget and added an button to
it.
Now, i have entered a filename (like NEWS.txt) in the text boz,
as you can see when i press the button i retrieve the text and then
search its filepath.
currently i am printing this filepath on the shell.
from Tkinter import *
import os
from os.path import realpath, exists, abspath
import tkMessageBox
import Tkinter
#import filePath
class GUIFrameWork(Frame):
This is the GUI
def __init__(self,master=None):
Initialize yourself
Initialise the base class
Frame.__init__(self,master)
Set the Window Title
self.master.title(Enter Text to search)
Display the main window
with a little bit of padding
self.grid(padx=10,pady=10)
self.CreateWidgets()
def CreateWidgets(self):
self.enText = Entry(self)
self.enText.grid(row=0, column=1, columnspan=3)
Create the Button, set the text and the
command that will be called when the button is clicked
self.btnDisplay = Button(self, text=Display!,
command=self.Display)
self.btnDisplay.grid(row=0, column=4)
def Display(self):
Called when btnDisplay is clicked, displays the contents of
self.enText
filename = self.enText.get()
Add some more code in here:
print filename, repr(filename)
cwd = os.getcwd()
print cwd, cwd
abspath = os.path.abspath(filename)
print abspath, repr(abspath)
exists = os.path.exists(abspath)
print exists, exists
and copy/paste the output into your reply.
Also tell us the name of the folder that the file allegedly exists in,
with a folder listing to prove it.
Also show us the result of using the ATTRIB command on your file, like
in the following examples:
C:\junkattrib c:\io.sys
SHR C:\IO.SYS
C:\junkattrib c:\python26\python.exe
A C:\python26\python.exe
Again, use copy/paste in your reply.
if os.path.exists(os.path.abspath(filename)):
print os.path.abspath(filename)
else:
print Not found
#tkMessageBox.showinfo(Text, You typed: %s %
os.path.abspath(os.path.dirname(filename)))
#filepath.mydir(self.enText.get())
if __name__ == __main__:
guiFrame = GUIFrameWork()
guiFrame.mainloop()
User Input: NEWS.txt
Output: Not Found (though this file is actually present)
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