Re: How to get the extension of a filename from the path
On Thu, 8 Dec 2005, gene tani wrote: > Lad wrote: > >> what is a way to get the the extension of a filename from the path? > > minor footnote: windows paths can be raw strings for os.path.split(), > or you can escape "/" > tho Tom's examp indicates unescaped, non-raw string works with > splitext() DOH. Yes, my path's got a tab in it, hasn't it! tom -- Women are monsters, men are clueless, everyone fights and no-one ever wins. -- cleanskies -- http://mail.python.org/mailman/listinfo/python-list
Re: How to get the extension of a filename from the path
Lad wrote: > Thank you ALL for help > Regards, > L. addendum: ASPN Python cookbook often has something relevant / modifiable for your needs: http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/81931 http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52661 (in this case code from 2001 / 2 is probably py 2.0 or 2.1, shd still work) -- http://mail.python.org/mailman/listinfo/python-list
Re: How to get the extension of a filename from the path
Thank you ALL for help Regards, L. -- http://mail.python.org/mailman/listinfo/python-list
Re: How to get the extension of a filename from the path
Fredrik Lundh wrote: > on the other hand, for maximum portability, you can use > > f, e = os.path.splitext(filename) > if e.startswith(os.extsep): > e = e[len(os.extsep):] > if e == "txt": > ... Is there ever a time when the original `e` could evaluate True, yet not startswith(os.extsep)? In other words, could the first test be just if e: e = e[len(os.extsep):] Also, note that for truly maximum portability one probably needs to add to the code some knowledge of case-sensitivity and do a .lower() when appropriate, as "txt" and "TXT" (and others) are equivalent on Windows file systems. On that note, is there a common idiom for detecting that information? -Peter -- http://mail.python.org/mailman/listinfo/python-list
Re: How to get the extension of a filename from the path
Lad wrote:
> Hello,
> what is a way to get the the extension of a filename from the path?
> E.g., on my XP windows the path can be
> C:\Pictures\MyDocs\test.txt
> and I would like to get
> the the extension of the filename, that is here
> txt
>
>
> I would like that to work on Linux also
> Thank you for help
> L.
minor footnote: windows paths can be raw strings for os.path.split(),
or you can escape "/"
tho Tom's examp indicates unescaped, non-raw string works with
splitext()
import os.path
# winpath='C:\\Pictures\\MyDocs\\test.txt'
winpath=r'C:\Pictures\MyDocs\test.txt'
fpath,fname_ext=os.path.split(winpath)
print "path: %s ; fname and ext: %s"%(fpath, fname_ext)
ext=fname_ext.split(".")[-1]
print ext
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Re: How to get the extension of a filename from the path
"Lad" <[EMAIL PROTECTED]> wrote:
> what is a way to get the the extension of a filename from the path?
> E.g., on my XP windows the path can be
> C:\Pictures\MyDocs\test.txt
> and I would like to get
> the the extension of the filename, that is here
> txt
>
> I would like that to work on Linux also
> Thank you for help
os.path.splitext(filename) splits a filename into a name part (which may include
a path) and an extension part:
import os
f, e = os.path.splitext(filename)
the extension will include the separator, so the following is always true:
assert f + e == filename
if you don't want the period, you can strip it off:
if e[:1] == ".":
e = e[1:]
but it's often easier to change your code to take the dot into account; instead
of
if e[:1] == ".":
e = e[1:]
if e == "txt":
handle_text_file(filename)
elif e in ("png", "jpg"):
handle_image_file(filename)
do
if e == ".txt":
handle_text_file(filename)
elif e in (".png", ".jpg"):
handle_image_file(filename)
on the other hand, for maximum portability, you can use
f, e = os.path.splitext(filename)
if e.startswith(os.extsep):
e = e[len(os.extsep):]
if e == "txt":
...
but that's probably overkill...
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Re: How to get the extension of a filename from the path
On Thu, 8 Dec 2005, Lad wrote:
> what is a way to get the the extension of a filename from the path?
> E.g., on my XP windows the path can be
> C:\Pictures\MyDocs\test.txt
> and I would like to get
> the the extension of the filename, that is here
> txt
You want os.path.splitext:
>>> import os
>>> os.path.splitext("C:\Pictures\MyDocs\test.txt")
('C:\\Pictures\\MyDocs\test', '.txt')
>>> os.path.splitext("C:\Pictures\MyDocs\test.txt")[1]
'.txt'
>>>
> I would like that to work on Linux also
It'll be fine.
tom
--
[Philosophy] is kind of like being driven behind the sofa by Dr Who -
scary, but still entertaining. -- Itchyfidget
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Re: How to get the extension of a filename from the path
Lad wrote:
> Hello,
> what is a way to get the the extension of a filename from the path?
> E.g., on my XP windows the path can be
> C:\Pictures\MyDocs\test.txt
> and I would like to get
> the the extension of the filename, that is here
> txt
>
>
> I would like that to work on Linux also
> Thank you for help
> L.
Like this, you mean?
>>> import os.path
>>> os.path.splitext("c:\\pictures\\mydocs\\test.txt")
('c:\\pictures\\mydocs\\test', '.txt')
--
Dale Strickland-Clark
Riverhall Systems www.riverhall.co.uk
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How to get the extension of a filename from the path
Hello, what is a way to get the the extension of a filename from the path? E.g., on my XP windows the path can be C:\Pictures\MyDocs\test.txt and I would like to get the the extension of the filename, that is here txt I would like that to work on Linux also Thank you for help L. -- http://mail.python.org/mailman/listinfo/python-list
