Re: How to print out html tags excluding the attributes
On 21/07/2019 02:04, sum abiut wrote: I want to use regular expression to print out the HTML tags excluding the attributes. That's a very good way of creating hard-to-read code and introducing subtle bugs and unexpected behaviours. Try using an HTML parser like BeautifulSoup instead. -- Rhodri James *-* Kynesim Ltd -- https://mail.python.org/mailman/listinfo/python-list
Re: How to print out html tags excluding the attributes
On 20/07/2019 20.04, sum abiut wrote: > I want to use regular expression to print out the HTML tags excluding the > attributes. > > for example: > > import re > html = 'Hitest test' > tags = re.findall(r'<[^>]+>', html) > for a in tags: > print(a) > > > the output is : > > > > > > > > > But I just want the tag, not the attributes Try this: for a in tags: a = re.sub( " .*>", ">", a ) print(a) (The two statements could be combined.) -- Michael F. Stemper Galatians 3:28 -- https://mail.python.org/mailman/listinfo/python-list
Re: How to print out html tags excluding the attributes
On Sun, Jul 21, 2019 at 11:06 AM sum abiut wrote: > > I want to use regular expression to print out the HTML tags excluding the > attributes. I'll just leave this here... https://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags No, I won't be that cruel. I'll also suggest that Beautiful Soup is an excellent non-regex way to parse HTML. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
How to print out html tags excluding the attributes
I want to use regular expression to print out the HTML tags excluding the attributes. for example: import re html = 'Hitest test' tags = re.findall(r'<[^>]+>', html) for a in tags: print(a) the output is : But I just want the tag, not the attributes -- https://mail.python.org/mailman/listinfo/python-list
