Re: Newbie subprocess question
On 11/26/2010 12:18 AM, Tim Harig wrote: On 2010-11-25, Hugo Léveillé hu...@fastmail.net wrote: I'm starting various application using subprocess.Popen without any problem. The problem is with application inside Program Files. It looks like subprocess is stopping the application string after Program. I tried puting the programe name inside double quote like 'Program File*...'. No luck. Not sure you you are having issues. subprocess.Popen(C:\\Program Files\\Vim\\vim73\\gvim.exe) Above line should work. In order to avoid the double backslashes (such, that you can just copy paste from the windows explorer or from a command line shell you could additionally prefix the string with r. subprocess.Popen(rC:\Program Files\Vim\vim73\gvim.exe) copying and pasting reduces the risk of typos -- http://mail.python.org/mailman/listinfo/python-list
Newbie subprocess question
I'm starting various application using subprocess.Popen without any problem. The problem is with application inside Program Files. It looks like subprocess is stopping the application string after Program. I tried puting the programe name inside double quote like 'Program File*...'. No luck. How can I start a app inside this folder ? Thanks -- Hugo Léveillé TD Compositing, Vision Globale hu...@fastmail.net -- http://mail.python.org/mailman/listinfo/python-list
Re: Newbie subprocess question
On 2010-11-25, Hugo Léveillé hu...@fastmail.net wrote: I'm starting various application using subprocess.Popen without any problem. The problem is with application inside Program Files. It looks like subprocess is stopping the application string after Program. I tried puting the programe name inside double quote like 'Program File*...'. No luck. Not sure you you are having issues. subprocess.Popen(C:\\Program Files\\Vim\\vim73\\gvim.exe) -- http://mail.python.org/mailman/listinfo/python-list
Re: Newbie subprocess question
On 25/11/2010 22:56, Hugo Léveillé wrote: I'm starting various application using subprocess.Popen without any problem. The problem is with application inside Program Files. It looks like subprocess is stopping the application string after Program. I tried puting the programe name inside double quote like 'Program File*...'. No luck. How can I start a app inside this folder ? Try passing the application path and its arguments (if any) as a list like this: subprocess.Popen([app_path, arg1, arg2]) -- http://mail.python.org/mailman/listinfo/python-list
Re: Newbie subprocess question
On 01/-10/-28163 02:59 PM, Hugo Léveillé wrote: I'm starting various application using subprocess.Popen without any problem. The problem is with application inside Program Files. It looks like subprocess is stopping the application string after Program. I tried puting the programe name inside double quote like 'Program File*...'. No luck. How can I start a app inside this folder ? Thanks How about you show us exactly what you are doing, and just what you mean by no luck ? You also should tell us what version of Python you're running, and mention that you're on Windows (presumably, but not necessarily). Perhaps you're using shell=True, perhaps you have an executable in the root directory called c:\program.exe, Perhaps you're passing arguments, but not putting them in separate list items. Who knows? DaveA -- http://mail.python.org/mailman/listinfo/python-list
