Parsing a large number of parms to a print statement.
Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? Thanks in advance. -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
KB wrote: Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? Thanks in advance. Actually, you are only sending one parameter to print. Is v iterable? _And_ does v have 150 values? _And_ can you say tuple(v) and get (v[0], v[1], v[2], ..., v[149])? If so, try: print %s blah %s blah blah %s % tuple(v) ~Ethan~ -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
KB wrote: Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? print %s text %s other text %s 150'th unique text %s % tuple(v) If v is already a tuple then that's not necessary! :-) -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
On Thu, Oct 22, 2009 at 5:16 PM, KB ke...@nekotaku.com wrote: Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? Thanks in advance. Why use a lambda? long string with lots of params % tuple(v) -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
KB ke...@nekotaku.com writes: I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. print %s text ... % tuple(v[:150]) But what you're trying to do looks bizarre. Find a way to make the constant strings inside the print statement part of the data. -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
On Thu, Oct 22, 2009 at 11:16 PM, KB ke...@nekotaku.com wrote: Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? It's not a lambda function, but what about print %s text %s other text %s 150'th unique text %s % tuple(v) -- André Engels, andreeng...@gmail.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Parsing a large number of parms to a print statement.
Excuse the top-post, but thanks to all, the tuple was the way to go. On Oct 22, 2:16 pm, KB ke...@nekotaku.com wrote: Hi, I have to pass over 150 parameters to a print statement ala: print %s text %s other text %s 150'th unique text %s % (v [0], v[1], ... v[150]) I can't use a for loop like I normally would over the list v due to the different text fragments between each var. Is there a lambda function I can use in place of '% (v[0],v[1]...v [150])' ??? Thanks in advance. -- http://mail.python.org/mailman/listinfo/python-list
