Re: Parsing soap result
Hi,
On 04/18/13 13:46, Ombongi Moraa Fe wrote:
Hi Burak, Team,
Apparently I was too deep in answering support questions for my company
:) This is python-list, so It's just me here :)
Your solution worked perfectly thanks.
Could you share the logic of this solution?
You're using suds. Let's have a look at what you see:
[(DeliveryInformation){
address = "254727"
deliveryStatus = "DeliveredToNetwork"
}]
You have it in square brackets, so it's an array. You apparently want
the first element, so it's result[0]. It's of type DeliveryInformation
with two fields, they are what you see there. Depending on the which
soap mode (rpc/document) your server uses, you should either use
result[0].deliveryStatus or result[0].DeliveryInformation.deliveryStatus.
I guess I got too much experience doing SOAP with python :) (I maintain
spyne, see: http://spyne.io)
I'm glad it worked.
Best,
Burak
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Re: Parsing soap result
Hi Burak, Team,
Your solution worked perfectly thanks.
Could you share the logic of this solution?
Saludos
Ombongi Moraa Faith
On 18 April 2013 00:41, Burak Arslan wrote:
> On 04/17/13 16:50, Ombongi Moraa Fe wrote:
>
> My
>
> client.service.gere(ri)
>
> method call logs the below soap response in my log file.
>
> http://schemas.xmlsoap.org/soap/envelope/"; xmlns:xsi="
> http://www.w3.org/2001/XMLSchema-instance";> xmlns:ns1="http://www.csapi.org/schema/parlayx/sms/send/v2_2/local
> ">254727DeliveredToNetwork
>
>
> If I assign the client.service.gere(ri) to a variable, i get the output
> on my screen:
>
> result=client.service.gere(ri)
>
> output:
> [(DeliveryInformation){
>address = "254727"
>deliveryStatus = "DeliveredToNetwork"
> }]
>
> string functions replace() and strip don't work.
>
> how do I use xml.etree.ElementTree to print the parameters address and
> deliveryStatus? Or is there a better python method?
>
>
> hi,
>
> try:
>
> result[0].deliveryStatus
>
> or
>
> result[0].DeliveryInformation.deliveryStatus
>
>
> and let us know.
>
> best,
> burak
>
>
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Re: Parsing soap result
On 04/17/13 16:50, Ombongi Moraa Fe wrote:
My
client.service.gere(ri)
method call logs the below soap response in my log file.
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>xmlns:ns1="http://www.csapi.org/schema/parlayx/sms/send/v2_2/local";>254727DeliveredToNetwork
If I assign the client.service.gere(ri) to a variable, i get the
output on my screen:
result=client.service.gere(ri)
output:
[(DeliveryInformation){
address = "254727"
deliveryStatus = "DeliveredToNetwork"
}]
string functions replace() and strip don't work.
how do I use xml.etree.ElementTree to print the parameters address and
deliveryStatus? Or is there a better python method?
hi,
try:
result[0].deliveryStatus
or
result[0].DeliveryInformation.deliveryStatus
and let us know.
best,
burak
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Re: Parsing soap result
On Apr 17, 1:05 pm, Christian Heimes wrote:
> Am 17.04.2013 19:55, schrieb darnold:
>
> > On Apr 17, 8:50 am, Ombongi Moraa Fe
> > wrote:
>
> >> how do I use xml.etree.ElementTree to print the parameters address and
> >> deliveryStatus? Or is there a better python method?
>
> > I'm sure there are prettier ways to do this, but you can use XPath
> > syntax to find all of your ns1:result nodes and loop through them:
>
> You want all {http://www.csapi.org/schema/parlayx/sms/send/v2_2/
> local}result tags. The prefix isn't fixed.
I'm sorry, but I'm not understanding the difference.
By specifying:
>>> myNamespaces=dict(ns1="http://www.csapi.org/schema/parlayx/sms/send/v2_2/local";)
Isn't this:
>>> for result in root.findall('.//ns1:result',namespaces=myNamespaces):
equivalent to:
>>> for result in
>>> root.findall('.//{http://www.csapi.org/schema/parlayx/sms/send/v2_2/local}result'):
?
Or am I misunderstanding? Is there a namespace-agnostic way of doing
this?
Admittedly, I haven't used ElementTree or XPath much prior to toying
with them to (attempt to) answer the OP's question.
Thanks for your patience,
Don
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Re: Parsing soap result
Am 17.04.2013 19:55, schrieb darnold:
> On Apr 17, 8:50 am, Ombongi Moraa Fe
> wrote:
>
>> how do I use xml.etree.ElementTree to print the parameters address and
>> deliveryStatus? Or is there a better python method?
>>
>
>
> I'm sure there are prettier ways to do this, but you can use XPath
> syntax to find all of your ns1:result nodes and loop through them:
You want all {http://www.csapi.org/schema/parlayx/sms/send/v2_2/
local}result tags. The prefix isn't fixed.
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Re: Parsing soap result
On Apr 17, 8:50 am, Ombongi Moraa Fe
wrote:
> how do I use xml.etree.ElementTree to print the parameters address and
> deliveryStatus? Or is there a better python method?
>
I'm sure there are prettier ways to do this, but you can use XPath
syntax to find all of your ns1:result nodes and loop through them:
>>> import xml.etree.ElementTree as ET
>>> myXML = '''\
http://schemas.xmlsoap.org/soap/
envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>
http://www.csapi.org/schema/parlayx/sms/send/v2_2/
local">
254727
DeliveredToNetwork
'''
>>> myNamespaces=dict(ns1="http://www.csapi.org/schema/parlayx/sms/send/v2_2/local",soapenv="http://schemas.xmlsoap.org/soap/envelope/";)
>>> root = ET.fromstring(myXML)
>>> for result in root.findall('.//ns1:result',namespaces=myNamespaces):
address = result.find('address').text
deliveryStatus = result.find('deliveryStatus').text
print "address: %s, deliveryStatus: %s" % (address,deliveryStatus)
address: 254727, deliveryStatus: DeliveredToNetwork
>>>
HTH,
Don
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Parsing soap result
My
client.service.gere(ri)
method call logs the below soap response in my log file.
http://schemas.xmlsoap.org/soap/envelope/"; xmlns:xsi="
http://www.w3.org/2001/XMLSchema-instance";>http://www.csapi.org/schema/parlayx/sms/send/v2_2/local
">254727DeliveredToNetwork
If I assign the client.service.gere(ri) to a variable, i get the output on
my screen:
result=client.service.gere(ri)
output:
[(DeliveryInformation){
address = "254727"
deliveryStatus = "DeliveredToNetwork"
}]
string functions replace() and strip don't work.
how do I use xml.etree.ElementTree to print the parameters address and
deliveryStatus? Or is there a better python method?
Thanks in advance.
Saludos
Ombongi Moraa Faith
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http://mail.python.org/mailman/listinfo/python-list
