Re: Printing a variable's name not its value
[EMAIL PROTECTED] wrote: > Bruno Desthuilliers wrote: > > def printVerbose(*args, **kwargs): > > > > > if VERBOSE in globals: > > > for a in args: > > > if a in globals: > > > value = globals[a] > > for k, v in kwargs.iteritems(): > > > print "%s: %s" % (k, v) > > > > > Perfect. Thanks for the pointer. Well, almost perfect ;) -- Regards, Travis Spencer -- http://mail.python.org/mailman/listinfo/python-list
Re: Printing a variable's name not its value
Simon Dahlbacka wrote: > as you have been told, there is no way to get a variable's name Well, if you really want to, you can get all the names bound to a given object: def get_names(obj): g = globals() names = [] for name in g: if g[name] is obj: names.append(name) return names Then you can play around: >>> list1 = [] >>> list2 = [list1] >>> get_names(list2) ['list2'] >>> list3 = list2 >>> get_names(list2) ['list3', 'list2'] >>> get_names(1) [] >>> a = 1 >>> get_names(1) ['a'] >>> b = 1 >>> get_names(1) ['a', 'b'] >>> get_names(a) ['a', 'b'] >>> c = 4/3. >>> d = 4/3. >>> get_names(c) ['c'] >>> get_names(d) ['d'] >>> get_names(4/3.) [] >>> But I wouldn't do it. If I want a name to be attached to some objects, I usually include it as a member/property of my class. -- http://mail.python.org/mailman/listinfo/python-list
Re: Printing a variable's name not its value
Simon Dahlbacka wrote: > as you have been told, there is no way to get a variable's name, take a > look at http://effbot.org/zone/python-objects.htm to find out why this > is so. Thanks, Simon, for the link. -- Regards, Travis Spencer -- http://mail.python.org/mailman/listinfo/python-list
Re: Printing a variable's name not its value
Bruno Desthuilliers wrote:
> [EMAIL PROTECTED] a écrit :
> > globals = {}
>
> globals() is a builtin function, you should no shadow it.
Oh, woops. I'll fix that.
> def printVerbose(*args, **kwargs):
>
> > if VERBOSE in globals:
> > for a in args:
> > if a in globals:
> > value = globals[a]
>
> for k, v in kwargs:
> > print "%s: %s" % (k, v)
> >
Perfect. Thanks for the pointer.
> > I've been told on #python that there isn't a way to get a variable's
> > name. I hope this isn't so.
>
> It is so. In fact, there is nothing like a 'variable' in Python. What we
> have are names bound to objects. Names 'knows' what objects are bound to
> them, but objects knows *nothing* about names they are bound to.
OK. This seems like it might take some getting used to. Thanks again
for the help.
--
Regards,
Travis Spencer
--
http://mail.python.org/mailman/listinfo/python-list
Re: Printing a variable's name not its value
[EMAIL PROTECTED] a écrit :
> Hey,
>
> I am trying to write a function that takes an arbitrary number of
> arguments and does one of two things. If the variable is a key in a
> dictionary, it prints the key and its value. Otherwise, if any of the
> variables isn't in the dictionary, the function prints the variable's
> name and value.
>
> Here is what I have so far:
>
> globals = {}
globals() is a builtin function, you should no shadow it.
> HOME_DIR = "The user's home directory"
> SHELL = "The user's shell"
>
> def someFunction():
> someString = "This is a test"
> globals[VERBOSE] = True
> globals[HOME_DIR] = os.getenv("HOME")
> globals[SHELL] = os.getenv("SHELL")
>
> printVerbose(someString, HOME_DIR, SHELL)
-> printVerbose(HOME_DIR, SHELL, someString=someString)
> def printVerbose(*args):
def printVerbose(*args, **kwargs):
> if VERBOSE in globals:
> for a in args:
> if a in globals:
> value = globals[a]
for k, v in kwargs:
> print "%s: %s" % (k, v)
>
(snip)
> I've been told on #python that there isn't a way to get a variable's
> name. I hope this isn't so.
It is so. In fact, there is nothing like a 'variable' in Python. What we
have are names bound to objects. Names 'knows' what objects are bound to
them, but objects knows *nothing* about names they are bound to.
--
http://mail.python.org/mailman/listinfo/python-list
Re: Printing a variable's name not its value
as you have been told, there is no way to get a variable's name, take a look at http://effbot.org/zone/python-objects.htm to find out why this is so. -- http://mail.python.org/mailman/listinfo/python-list
Printing a variable's name not its value
Hey,
I am trying to write a function that takes an arbitrary number of
arguments and does one of two things. If the variable is a key in a
dictionary, it prints the key and its value. Otherwise, if any of the
variables isn't in the dictionary, the function prints the variable's
name and value.
Here is what I have so far:
globals = {}
HOME_DIR = "The user's home directory"
SHELL = "The user's shell"
def someFunction():
someString = "This is a test"
globals[VERBOSE] = True
globals[HOME_DIR] = os.getenv("HOME")
globals[SHELL] = os.getenv("SHELL")
printVerbose(someString, HOME_DIR, SHELL)
def printVerbose(*args):
if VERBOSE in globals:
for a in args:
value = ""
if a in globals:
value = globals[a]
#else
#a = a.__name__
#value = a
print "%s: %s" % (a, value)
This prints something like this:
The user's home directory: /home/tspencer
The use's shell: zsh
But what I would like it to print is this:
The user's home directory: /home/tspencer
The use's shell: zsh
someString: This is a test
I've been told on #python that there isn't a way to get a variable's
name. I hope this isn't so. If it helps, I am trying to do something
like what the C preprocessor's # operator does.
TIA.
--
Regards,
Travis Spencer
--
http://mail.python.org/mailman/listinfo/python-list
