Re: problem with python 3.5.0
On 18/03/2016 16:56, nasrin maarefi via Python-list wrote: HelloI installed the python 3.5.0(32bit) on 64bit win10 but I dont know how to install numpy pakage for this? I did not find something good on internet. could you please guide me?where can I find the suitable numpy for that? and where is the path and pip and? best regards. Download numpy-1.10.4+vanilla-cp35-none-win32.whl from http://www.lfd.uci.edu/~gohlke/pythonlibs/#numpy From cmd.exe run:- your\path\to\python3.5\scripts\pip install where\you\put\numpy-1.10.4+vanilla-cp35-none-win32.whl If you like you could download numpy-1.11.0rc1+mkl-cp35-cp35m-win32.whl. I don't know when the full release of numpy1.11 is due out. -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence -- https://mail.python.org/mailman/listinfo/python-list
problem with python 3.5.0
HelloI installed the python 3.5.0(32bit) on 64bit win10 but I dont know how to install numpy pakage for this? I did not find something good on internet. could you please guide me?where can I find the suitable numpy for that? and where is the path and pip and? best regards. -- https://mail.python.org/mailman/listinfo/python-list
Re: problem with python 3.5.0
On 18 Mar 2016 17:42, "Mark Lawrence" wrote: > > On 18/03/2016 16:56, nasrin maarefi via Python-list wrote: >> >> HelloI installed the python 3.5.0(32bit) on 64bit win10 but I dont know how to install numpy pakage for this? I did not find something good on internet. could you please guide me?where can I find the suitable numpy for that? and where is the path and pip and? >> best regards. >> > > Download numpy-1.10.4+vanilla-cp35-none-win32.whl from http://www.lfd.uci.edu/~gohlke/pythonlibs/#numpy > > From cmd.exe run:- > > your\path\to\python3.5\scripts\pip install where\you\put\numpy-1.10.4+vanilla-cp35-none-win32.whl > > If you like you could download numpy-1.11.0rc1+mkl-cp35-cp35m-win32.whl. > I don't know when the full release of numpy1.11 is due out. FTR "pip install numpy" should now work on Windows and OSX. -- Oscar -- https://mail.python.org/mailman/listinfo/python-list
Re: Problem with Python 3.5.0
On 11 October 2015 at 18:12, eetix letix wrote:
> Hi,
>
> I'm sorry but the last version of Python (3.5.0) had a problem. I start and
> I meet this problem :
>
a=5
if a>0:
> . . . print("a is a positive.")
> . . . if a<0:
> ^
> SyntaxError: invalid syntax
>
> Normally this should work but problem comes to the fact that Python
> considers "a" is a positive number and refuses to do the command >>>if a<0:
You're almost there, but your guess as to the reason for the error
isn't quite right.
It seems that the syntax in the Python shell is subtly different to
code in a module.
Because the second 'if' is a distinct statement from the first, the
python shell seems to require a second return.
However consider that perhaps using an 'else' or 'elif' instead of a
completely separate 'if'
And also consider that most people regard 0 to be positive, so you
probably meant (a>=0).
That means you can simplify to
if a>=0:
print("a is a positive")
else:
print("no need to evaluate a a second time")
> And the command \n is doesn't working :
>
a="test\nto\nsee\nif\nit\nis\nworking"
a
> 'test\nto\nsee\nif\nit\nis\nworking'
>
>
> Normally, \n should make that the text returns to the line but doesn't make
> it. And if y do :
>
a="""test
> . . . to
> . . . see
> . . . if
> . . . it
> . . . is
> . . . working"""
a
> 'test\nto\nsee\nif\nit\nis\nworking'
\n is an escape sequence rather than a command
Have a look at what happens if you try print(a)
> Thanks to fix this problems and good luck ;)
>
>
> PS : I'm sorry for this really bad english but I'm french and I'm 14
Don't worry, it's certainly better than my French!
--
Matt Wheeler
http://funkyh.at
--
https://mail.python.org/mailman/listinfo/python-list
Re: Problem with Python 3.5.0
Le 11/10/2015 19:12, eetix letix a écrit :
Hi,
I'm sorry but the last version of Python (3.5.0) had a problem. I
start and I meet this problem :
>>>a=5
>>>if a>0:
. . . print("a is a positive.")
. . . if a<0:
^
SyntaxError: invalid syntax
>>>
Normally this should work but problem comes to the fact that Python
considers "a" is a positive number and refuses to do the command >>>if
a<0:
And the command |\n is doesn't working :
|
|>>> a="test||\nto||\nsee||\nif||\nit||\nis||\nworking"
|
|>>> a
|
|'||test||\nto||\nsee||\nif||\nit||\nis||\nworking'
>>>
|
Normally, \n should make that the text returns to the line but doesn't
make it. And if y do :
>>> a="""test
. . . to
. . . see
. . . if
. . . it
. . . is
. . . working"""
>>>a
|'||test||\nto||\nsee||\nif||\nit||\nis||\nworking'
>>>
|
|Thanks to fix this problems and good luck ;)
|
|PS : I'm sorry for this really bad english but I'm french and I'm 14
|
Hi,
see:
>>> a = 5
>>> if a > 0:
... print('a is a positive')
... # here, type a Enter
a is a positive
>>> elif a
>>> a = "test\nto\nsee\nif\nit\nis\nworking"
>>> a
'test\nto\nsee\nif\nit\nis\nworking'
>>> print(a)
test
to
see
if
it
is
working
>>>
Clear ?
Vincent
--
https://mail.python.org/mailman/listinfo/python-list
Re: Problem with Python 3.5.0
On Sun, Oct 11, 2015 at 1:12 PM, eetix letix wrote:
> Hi,
>
> I'm sorry but the last version of Python (3.5.0) had a problem. I start
> and I meet this problem :
>
> >>>a=5
> >>>if a>0:
> . . . print("a is a positive.")
> . . . if a<0:
> ^
> SyntaxError: invalid syntax
> >>>
> Not sure what is going on above
>
> Normally this should work but problem
> comes to the
> fact that Python considers "a" is a positive number and refuses to do the
> command >>>if a<0:
>
> And the command \n is doesn't working :
>
> >>> a="test\nto\nsee\nif\nit\nis\nworking"
> >>> a
> 'test\nto\nsee\nif\nit\nis\nworking'
> >>>
>
> In the interactive python shell, typing a name will give the
> representation of the variable. So you will see the \n. If you type
> print(a), you will get what you expected
>
> Normally, \n should make
> that the text
> returns to the line but doesn't make it. And if y do :
>
> >>> a="""test
> . . . to
> . . . see
> . . . if
> . . . it
> . . . is
> . . . working"""
> >>>a
> 'test\nto\nsee\nif\nit\nis\nworking'
> >>>
>
>
> Thanks to fix this problems and good luck ;)
>
>
> PS : I'm sorry for this really bad english but I'm french and I'm 14
>
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
>
--
Joel Goldstick
http://joelgoldstick.com/stats/birthdays
--
https://mail.python.org/mailman/listinfo/python-list
Problem with Python 3.5.0
Hi,
I'm sorry but the last version of Python (3.5.0) had a problem. I start and
I meet this problem :
>>>a=5
>>>if a>0:
. . . print("a is a positive.")
. . . if a<0:
^
SyntaxError: invalid syntax
>>>
Normally this should work but problem
comes to the
fact that Python considers "a" is a positive number and refuses to do the
command >>>if a<0:
And the command \n is doesn't working :
>>> a="test\nto\nsee\nif\nit\nis\nworking"
>>> a
'test\nto\nsee\nif\nit\nis\nworking'
>>>
Normally, \n should make
that the text
returns to the line but doesn't make it. And if y do :
>>> a="""test
. . . to
. . . see
. . . if
. . . it
. . . is
. . . working"""
>>>a
'test\nto\nsee\nif\nit\nis\nworking'
>>>
Thanks to fix this problems and good luck ;)
PS : I'm sorry for this really bad english but I'm french and I'm 14
--
https://mail.python.org/mailman/listinfo/python-list
