Re: Question on Debugging a code line
On Sunday, May 11, 2014 12:57:34 AM UTC+5:30, subhaba...@gmail.com wrote:
Dear Room,
I was trying to go through a code given in
http://en.wikipedia.org/wiki/Forward%E2%80%93backward_algorithm[ Forward
Backward is an algorithm of Machine Learning-I am not talking on that
I am just trying to figure out a query on its Python coding.]
I came across the following codes.
states = ('Healthy', 'Fever')
end_state = 'E'
observations = ('normal', 'cold', 'dizzy')
start_probability = {'Healthy': 0.6, 'Fever': 0.4}
transition_probability = {
'Healthy' : {'Healthy': 0.69, 'Fever': 0.3, 'E': 0.01},
'Fever' : {'Healthy': 0.4, 'Fever': 0.59, 'E': 0.01},
}
emission_probability = {
'Healthy' : {'normal': 0.5, 'cold': 0.4, 'dizzy': 0.1},
'Fever' : {'normal': 0.1, 'cold': 0.3, 'dizzy': 0.6},
}
def fwd_bkw(x, states, a_0, a, e, end_st):
L = len(x)
fwd = []
f_prev = {} #THE PROBLEM
# forward part of the algorithm
for i, x_i in enumerate(x):
f_curr = {}
for st in states:
if i == 0:
# base case for the forward part
prev_f_sum = a_0[st]
else:
prev_f_sum = sum(f_prev[k]*a[k][st] for k in states) ##
f_curr[st] = e[st][x_i] * prev_f_sum
fwd.append(f_curr)
f_prev = f_curr
p_fwd = sum(f_curr[k]*a[k][end_st] for k in states)
As this value was being called in prev_f_sum = sum(f_prev[k]*a[k][st] for k
in states marked ##
I wanted to know what values it is generating.
So, I had made the following experiment, after
for i, x_i in enumerate(x):
I had put print f_prev
but I am not getting how f_prev is getting the values.
Here,
x=observations,
states= states,
a_0=start_probability,
a= transition_probability,
e=emission_probability,
end_st= end_state
Am I missing any minor aspect?
Code is running fine.
If any one of the esteemed members may kindly guide me.
Regards,
Subhabrata Banerjee.
Dear Sir,
Thank you for your kind reply. I will check.
Regards,
Subhabrata Banerjee.
--
https://mail.python.org/mailman/listinfo/python-list
Re: Question on Debugging a code line
On Sunday, May 11, 2014 11:50:32 AM UTC+5:30, subhaba...@gmail.com wrote:
On Sunday, May 11, 2014 12:57:34 AM UTC+5:30, subhaba...@gmail.com wrote:
Dear Room,
I was trying to go through a code given in
http://en.wikipedia.org/wiki/Forward%E2%80%93backward_algorithm[ Forward
Backward is an algorithm of Machine Learning-I am not talking on that
I am just trying to figure out a query on its Python coding.]
I came across the following codes.
states = ('Healthy', 'Fever')
end_state = 'E'
observations = ('normal', 'cold', 'dizzy')
start_probability = {'Healthy': 0.6, 'Fever': 0.4}
transition_probability = {
'Healthy' : {'Healthy': 0.69, 'Fever': 0.3, 'E': 0.01},
'Fever' : {'Healthy': 0.4, 'Fever': 0.59, 'E': 0.01},
}
emission_probability = {
'Healthy' : {'normal': 0.5, 'cold': 0.4, 'dizzy': 0.1},
'Fever' : {'normal': 0.1, 'cold': 0.3, 'dizzy': 0.6},
}
def fwd_bkw(x, states, a_0, a, e, end_st):
L = len(x)
fwd = []
f_prev = {} #THE PROBLEM
# forward part of the algorithm
for i, x_i in enumerate(x):
f_curr = {}
for st in states:
if i == 0:
# base case for the forward part
prev_f_sum = a_0[st]
else:
prev_f_sum = sum(f_prev[k]*a[k][st] for k in states) ##
f_curr[st] = e[st][x_i] * prev_f_sum
fwd.append(f_curr)
f_prev = f_curr
p_fwd = sum(f_curr[k]*a[k][end_st] for k in states)
As this value was being called in prev_f_sum = sum(f_prev[k]*a[k][st] for k
in states marked ##
I wanted to know what values it is generating.
So, I had made the following experiment, after
for i, x_i in enumerate(x):
I had put print f_prev
but I am not getting how f_prev is getting the values.
Here,
x=observations,
states= states,
a_0=start_probability,
a= transition_probability,
e=emission_probability,
end_st= end_state
Am I missing any minor aspect?
Code is running fine.
If any one of the esteemed members may kindly guide me.
Regards,
Subhabrata Banerjee.
Dear Sir,
Thank you for your kind reply. I will check.
Regards,
Subhabrata Banerjee.
Dear Sir,
Thank you. It worked. I made another similar statement over another set of
values on your reply it went nice.
Regards,
Subhabrata Banerjee.
--
https://mail.python.org/mailman/listinfo/python-list
Re: Question on Debugging a code line
On 11/05/2014 08:45, subhabangal...@gmail.com wrote: [268 lines snipped] Would you please use the mailing list https://mail.python.org/mailman/listinfo/python-list or read and action this https://wiki.python.org/moin/GoogleGroupsPython to prevent us seeing double line spacing and single line paragraphs, thanks. -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence --- This email is free from viruses and malware because avast! Antivirus protection is active. http://www.avast.com -- https://mail.python.org/mailman/listinfo/python-list
Question on Debugging a code line
Dear Room,
I was trying to go through a code given in
http://en.wikipedia.org/wiki/Forward%E2%80%93backward_algorithm[ Forward
Backward is an algorithm of Machine Learning-I am not talking on that
I am just trying to figure out a query on its Python coding.]
I came across the following codes.
states = ('Healthy', 'Fever')
end_state = 'E'
observations = ('normal', 'cold', 'dizzy')
start_probability = {'Healthy': 0.6, 'Fever': 0.4}
transition_probability = {
'Healthy' : {'Healthy': 0.69, 'Fever': 0.3, 'E': 0.01},
'Fever' : {'Healthy': 0.4, 'Fever': 0.59, 'E': 0.01},
}
emission_probability = {
'Healthy' : {'normal': 0.5, 'cold': 0.4, 'dizzy': 0.1},
'Fever' : {'normal': 0.1, 'cold': 0.3, 'dizzy': 0.6},
}
def fwd_bkw(x, states, a_0, a, e, end_st):
L = len(x)
fwd = []
f_prev = {} #THE PROBLEM
# forward part of the algorithm
for i, x_i in enumerate(x):
f_curr = {}
for st in states:
if i == 0:
# base case for the forward part
prev_f_sum = a_0[st]
else:
prev_f_sum = sum(f_prev[k]*a[k][st] for k in states) ##
f_curr[st] = e[st][x_i] * prev_f_sum
fwd.append(f_curr)
f_prev = f_curr
p_fwd = sum(f_curr[k]*a[k][end_st] for k in states)
As this value was being called in prev_f_sum = sum(f_prev[k]*a[k][st] for k in
states marked ##
I wanted to know what values it is generating.
So, I had made the following experiment, after
for i, x_i in enumerate(x):
I had put print f_prev
but I am not getting how f_prev is getting the values.
Here,
x=observations,
states= states,
a_0=start_probability,
a= transition_probability,
e=emission_probability,
end_st= end_state
Am I missing any minor aspect?
Code is running fine.
If any one of the esteemed members may kindly guide me.
Regards,
Subhabrata Banerjee.
--
https://mail.python.org/mailman/listinfo/python-list
Re: Question on Debugging a code line
On 2014-05-10 20:27, subhabangal...@gmail.com wrote:
Dear Room,
I was trying to go through a code given in
http://en.wikipedia.org/wiki/Forward%E2%80%93backward_algorithm[ Forward
Backward is an algorithm of Machine Learning-I am not talking on that
I am just trying to figure out a query on its Python coding.]
I came across the following codes.
states = ('Healthy', 'Fever')
end_state = 'E'
observations = ('normal', 'cold', 'dizzy')
start_probability = {'Healthy': 0.6, 'Fever': 0.4}
transition_probability = {
'Healthy' : {'Healthy': 0.69, 'Fever': 0.3, 'E': 0.01},
'Fever' : {'Healthy': 0.4, 'Fever': 0.59, 'E': 0.01},
}
emission_probability = {
'Healthy' : {'normal': 0.5, 'cold': 0.4, 'dizzy': 0.1},
'Fever' : {'normal': 0.1, 'cold': 0.3, 'dizzy': 0.6},
}
def fwd_bkw(x, states, a_0, a, e, end_st):
L = len(x)
fwd = []
f_prev = {} #THE PROBLEM
# forward part of the algorithm
for i, x_i in enumerate(x):
f_curr = {}
for st in states:
if i == 0:
# base case for the forward part
prev_f_sum = a_0[st]
else:
prev_f_sum = sum(f_prev[k]*a[k][st] for k in states) ##
f_curr[st] = e[st][x_i] * prev_f_sum
fwd.append(f_curr)
f_prev = f_curr
p_fwd = sum(f_curr[k]*a[k][end_st] for k in states)
As this value was being called in prev_f_sum = sum(f_prev[k]*a[k][st] for k in
states marked ##
I wanted to know what values it is generating.
So, I had made the following experiment, after
for i, x_i in enumerate(x):
I had put print f_prev
but I am not getting how f_prev is getting the values.
Here,
x=observations,
states= states,
a_0=start_probability,
a= transition_probability,
e=emission_probability,
end_st= end_state
Am I missing any minor aspect?
Code is running fine.
If any one of the esteemed members may kindly guide me.
The values calculated in the inner loop are being put into the dict
'f_curr'
and then, when that loop has completed, 'f_prev' is being bound to that
dict.
'f_curr' is bound to a new dict just before the inner loop, ready for
the new values.
--
https://mail.python.org/mailman/listinfo/python-list
