Tertius Cronje wrote:
Hi all,
This does not feel Pythonic. Is there a better way to do the same?
Many TIA
T
# L = [1,2,3,4,5,6, etc]
# L can contain 'n' elements
# fmt is made up to each particular specification
if len(L) == 0:
return ''
elif len(L) == 1:
return struct.pack(fmt,L[0] )
elif len(L) == 2:
return struct.pack(fmt,L[0] , L[1])
elif len(L) == 3:
return struct.pack(fmt,L[0] , L[1], L[2])
elif len(L) == 4:
return struct.pack(fmt,L[0] , L[1], L[2], L[3])
elif len(L) == 5:
return struct.pack(fmt,L[0] , L[1], L[2], L[3], L[4])
elif len(L) == 6:
return struct.pack(fmt,L[0] , L[1], L[2], L[3], L[4], L[5])
# etc... etc... etc ...
return struct.pack(fmt, *L)
Should do the trick
ola
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Ola Natvig [EMAIL PROTECTED]
infoSense AS / development
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