Re: one Liner: Lisprint(x) --> (a, b, c) instead of ['a', 'b', 'c']

2023-02-27 Thread Greg Ewing via Python-list 

On 28/02/23 4:24 pm, Hen Hanna wrote:

   is it poss. to peek at the Python-list's  messages 
without joining ?


It's mirrored to the comp.lang.python usenet group, or
you can read it through gmane with a news client.

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Greg
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RE: one Liner: Lisprint(x) --> (a, b, c) instead of ['a', 'b', 'c']

2023-02-26 Thread avi.e.gross 
I so rarely need to save a list in python in a form acceptable to LISP but here 
is a go with no visible recursion needed.

>>> nested = [1, 2, [3, 4, [5, 6, 7], 8], 9]

>>> print(nested)
[1, 2, [3, 4, [5, 6, 7], 8], 9]

# Just converting to a tuple does not change nested lists
>>> print(tuple(nested))
(1, 2, [3, 4, [5, 6, 7], 8], 9)

# But a function that typographically replaces [] with () needs no recursion
>>> def p2b(nested_list): return 
>>> repr(nested_list).replace('[','(').replace(']',')')

>>> print(p2b(nested))
(1, 2, (3, 4, (5, 6, 7), 8), 9)

People who speak python well do not necessarily lisp.

-Original Message-
From: Python-list  On 
Behalf Of Hen Hanna
Sent: Sunday, February 26, 2023 4:54 AM
To: python-list@python.org
Subject: Re: one Liner: Lisprint(x) --> (a, b, c) instead of ['a', 'b', 'c']

On Saturday, February 25, 2023 at 11:45:12 PM UTC-8, Hen Hanna wrote:
> def Lisprint(x): print( ' (' + ', '.join(x) + ')' , '\n') 
> 
> a= ' a b c ? def f x if zero? x 0 1 ' 
> a += ' A B C ! just an example ' 
> x= a.split() 
> 
> print(x) 
> Lisprint(x) 
> 
> ['a', 'b', 'c', '?', 'def', 'f', 'x', 'if', 'zero?', 'x', '0', '1', 'A', 'B', 
> 'C', '!', 'just', 'an', 'example'] 
> 
> (a, b, c, ?, def, f, x, if, zero?, x, 0, 1, A, B, C, !, just, an, example)


For nested lists  impossible to improve   upon  P.Norvig's  code


def Lisprint(x):   print(lispstr(x))

def lispstr(exp):
"Convert a Python object back into a Lisp-readable string."
if isinstance(exp, list):
return '(' + ' '.join(map(lispstr, exp)) + ')' 
else:
return str(exp)

a=' a b c '
x= a.split()
x +=  [['a', 'b', 'c']]
x +=  x

print(x) 
Lisprint(x) 

['a', 'b', 'c', ['a', 'b', 'c'], 'a', 'b', 'c', ['a', 'b', 'c']]

(a b c (a b c) a b c (a b c))


  --   Without the commas,   the visual difference 
(concision)  is  striking !
-- 
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Re: one Liner: Lisprint(x) --> (a, b, c) instead of ['a', 'b', 'c']

2023-02-26 Thread Hen Hanna 
On Saturday, February 25, 2023 at 11:45:12 PM UTC-8, Hen Hanna wrote:
> def Lisprint(x): print( ' (' + ', '.join(x) + ')' , '\n') 
> 
> a= ' a b c ? def f x if zero? x 0 1 ' 
> a += ' A B C ! just an example ' 
> x= a.split() 
> 
> print(x) 
> Lisprint(x) 
> 
> ['a', 'b', 'c', '?', 'def', 'f', 'x', 'if', 'zero?', 'x', '0', '1', 'A', 'B', 
> 'C', '!', 'just', 'an', 'example'] 
> 
> (a, b, c, ?, def, f, x, if, zero?, x, 0, 1, A, B, C, !, just, an, example)


For nested lists  impossible to improve   upon  P.Norvig's  code


def Lisprint(x):   print(lispstr(x))

def lispstr(exp):
"Convert a Python object back into a Lisp-readable string."
if isinstance(exp, list):
return '(' + ' '.join(map(lispstr, exp)) + ')' 
else:
return str(exp)

a=' a b c '
x= a.split()
x +=  [['a', 'b', 'c']]
x +=  x

print(x) 
Lisprint(x) 

['a', 'b', 'c', ['a', 'b', 'c'], 'a', 'b', 'c', ['a', 'b', 'c']]

(a b c (a b c) a b c (a b c))


  --   Without the commas,   the visual difference 
(concision)  is  striking !
-- 
https://mail.python.org/mailman/listinfo/python-list