Re: A problem with Time
At 08:30 AM 8/16/2007, special_dragonfly wrote: Hello, I need to return the date yesterday in the form DDMM. I looked through the modules: time, datetime and calendar but can't find anything that leaps out at me. The problem I'm having is that although I can use time.localtime and get a tuple of the year, month, day and so forth, I don't believe I can just minus 1 from the day, because I don't think it's cyclic, also, I can't see the date being linked in with the month. So is there any way of getting yesterdays date? The question has already been well-answered, but since I've found using the datetime module to be tough going, I was wondering if either of these would be easier to understand and use: 1. http://www.egenix.com/products/python/mxBase/mxDateTime/ I see that mxDateTime comes with a 55-page manual as a PDF. 2. http://labix.org/python-dateutil Dick Moores -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
import time oneDay = 60 * 60 * 24 #seconds in one day date = time.time() yesterday = date - oneDay -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
On 8/16/07, special_dragonfly [EMAIL PROTECTED] wrote: Hello, I need to return the date yesterday in the form DDMM. I looked through the modules: time, datetime and calendar but can't find anything that leaps out at me. The problem I'm having is that although I can use time.localtime and get a tuple of the year, month, day and so forth, I don't believe I can just minus 1 from the day, because I don't think it's cyclic, also, I can't see the date being linked in with the month. So is there any way of getting yesterdays date? Thank You Dominic -- http://mail.python.org/mailman/listinfo/python-list The easiest way I have found, is to use epoch, subtract the length of time, then convert back to whatever format. 24 hours is 86400 seconds. import time time.localtime() (2007, 8, 16, 9, 41, 28, 3, 228, 1) time.localtime(time.time() - 86400) (2007, 8, 15, 9, 41, 21, 2, 227, 1) -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
special_dragonfly schrieb: Hello, I need to return the date yesterday in the form DDMM. I looked through the modules: time, datetime and calendar but can't find anything that leaps out at me. The problem I'm having is that although I can use time.localtime and get a tuple of the year, month, day and so forth, I don't believe I can just minus 1 from the day, because I don't think it's cyclic, also, I can't see the date being linked in with the month. So is there any way of getting yesterdays date? RTFM is the answer... import datetime today = datetime.date.today() yesterday = today - datetime.timedelta(days=1) print yesterday Diez -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
On 2007-08-16, Shawn Milochik [EMAIL PROTECTED] wrote:
import time
oneDay = 60 * 60 * 24 #seconds in one day
date = time.time()
yesterday = date - oneDay
Or use a timedelta.
import datetime
yesterday = datetime.datetime.today() - datetime.timedelta(days=1)
yesterday.strftime('%m%d%Y')
'08152007'
--
Neil Cerutti
It might take a season, it might take half a season, it might take a year.
--Elgin Baylor
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Re: A problem with Time
special_dragonfly wrote: Hello, I need to return the date yesterday in the form DDMM. I looked through the modules: time, datetime and calendar but can't find anything that leaps out at me. The problem I'm having is that although I can use time.localtime and get a tuple of the year, month, day and so forth, I don't believe I can just minus 1 from the day, because I don't think it's cyclic, also, I can't see the date being linked in with the month. So is there any way of getting yesterdays date? Thank You Dominic Here's how I'd do it: import time secondsPerDay = 24*60*60 today = time.time() yesterday = today - secondsPerDay print time.strftime(%d%m%Y,time.localtime(today)) 16082007 print time.strftime(%d%m%Y,time.localtime(yesterday)) 15082007 Gary Herron -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
On Aug 16, 10:54 am, Diez B. Roggisch [EMAIL PROTECTED] wrote: RTFM is the answer... I don't know. I remember scratching my head for a day or two over the module explanations and instructions until I found a little howto with a lot of explicite examples. http://pleac.sourceforge.net/pleac_python/datesandtimes.html rd -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
On Aug 16, 4:30 pm, special_dragonfly [EMAIL PROTECTED] wrote: Hello, I need to return the date yesterday in the form DDMM. I looked through the modules: time, datetime and calendar but can't find anything that leaps out at me. The problem I'm having is that although I can use time.localtime and get a tuple of the year, month, day and so forth, I don't believe I can just minus 1 from the day, because I don't think it's cyclic, also, I can't see the date being linked in with the month. So is there any way of getting yesterdays date? As well as the other replies, this also works (as far as I can tell!): import time today = time.localtime() yesterday = today[ : 2] + (today[2] - 1, ) + today[3 : ] yesterday = time.localtime(time.mktime(yesterday)) -- http://mail.python.org/mailman/listinfo/python-list
Re: A problem with Time
On Aug 16, 9:46 am, MRAB [EMAIL PROTECTED] wrote: As well as the other replies, this also works (as far as I can tell!): import time today = time.localtime() yesterday = today[ : 2] + (today[2] - 1, ) + today[3 : ] yesterday = time.localtime(time.mktime(yesterday)) This is something I have wondered about. The C library mktime function is documented to fix up out of range values,. For example July 32 becomes August 1 and August -1 becomes July 31. Python presumably inherits this very useful (and seemingly not well known) behavior, but it is not documented. Is this just an oversight, or is it intentional on the grounds that it might be platform-dependent? Any language lawyers out there that would care to comment? -- http://mail.python.org/mailman/listinfo/python-list
