Re: Clever way of sorting strings containing integers?
On 9 Okt., 09:41, Holger [EMAIL PROTECTED] wrote: I tried to do this elegantly, but did not come up with a good solution Sort strings like foo1bar2 foo10bar10 foo2bar3 foo10bar2 So that they come out: foo1bar2 foo2bar3 foo10bar2 foo10bar10 I.e. isolate integer parts and sort them according to integer value. Thx Holger or even: foo1bar2 foo10bar10 foo2bar3 foo10bar2 fo bar1000 777 To: 777 bar1000 fo foo1bar2 foo2bar3 foo10bar2 foo10bar10 Here's my own take, but it doesn't quite work yet: txtline = re.compile(r'(\D*)(\d+)') lines = [x.strip() for x in sys.stdin.readlines()] res = [] for l in [ x for x in lines if x]: groups = txtline.findall(l) res.append([[[x[0], int(x[1],0)] for x in groups],l]) res.sort() for x in res: print x[1] -- http://mail.python.org/mailman/listinfo/python-list
Re: Clever way of sorting strings containing integers?
On 9 Okt., 10:57, Marc 'BlackJack' Rintsch [EMAIL PROTECTED] wrote: On Thu, 09 Oct 2008 00:41:27 -0700, Holger wrote: I tried to do this elegantly, but did not come up with a good solution Sort strings like foo1bar2 foo10bar10 foo2bar3 foo10bar2 So that they come out: foo1bar2 foo2bar3 foo10bar2 foo10bar10 I.e. isolate integer parts and sort them according to integer value. import re def key_func(string): result = re.split(r'(\d+)', string) for i in xrange(1, len(result), 2): result[i] = int(result[i]) return result def main(): lines = ['foo1bar2', 'foo10bar10', 'foo2bar3', 'foo10bar2', 'fo', 'bar1000', '777'] lines.sort(key=key_func) print '\n'.join(lines) Perfect! Thank you. -- http://mail.python.org/mailman/listinfo/python-list
Re: Clever way of sorting strings containing integers?
On Thu, 09 Oct 2008 00:41:27 -0700, Holger wrote: I tried to do this elegantly, but did not come up with a good solution Sort strings like foo1bar2 foo10bar10 foo2bar3 foo10bar2 So that they come out: foo1bar2 foo2bar3 foo10bar2 foo10bar10 I.e. isolate integer parts and sort them according to integer value. import re def key_func(string): result = re.split(r'(\d+)', string) for i in xrange(1, len(result), 2): result[i] = int(result[i]) return result def main(): lines = ['foo1bar2', 'foo10bar10', 'foo2bar3', 'foo10bar2', 'fo', 'bar1000', '777'] lines.sort(key=key_func) print '\n'.join(lines) Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list
Re: Clever way of sorting strings containing integers?
On 9 Ott, 09:41, Holger [EMAIL PROTECTED] wrote: I tried to do this elegantly, but did not come up with a good solution Sort strings like foo1bar2 foo10bar10 foo2bar3 foo10bar2 So that they come out: foo1bar2 foo2bar3 foo10bar2 foo10bar10 I.e. isolate integer parts and sort them according to integer value. Thx Holger This should work, if you have all stribngs in memory: import re REXP = re.compile( r'\d+' ) lines = ['foo1bar2', 'foo10bar10', 'foo2bar3', 'foo10bar2' ] def key_function( s ): return map(int, re.findall(REXP, s )) lines.sort( key=key_function) Ciao FB -- http://mail.python.org/mailman/listinfo/python-list
