Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
*if any(roll != 1 and roll != 5 for roll in result):* another extract of py's beauty! Abdur-Rahmaan Janhangeer https://github.com/Abdur-rahmaanJ Mauritius -- https://mail.python.org/mailman/listinfo/python-list
Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
On 2018-10-06, eliteanarchyra...@gmail.com
wrote:
> Hi, I am new to python and would like someones help on the
> following:
>
> After rolling 5 dice and putting the results into a list, I
> need to check if any dice is not a 1 or 5.
if any(roll != 1 and roll != 5 for roll in result):
> # - THIS LINE IS WHERE I NEED HELP # ( if 2, 3, 4, 6 in list: )
> print("you can roll again")
> else:
> print("you have all 1's and 5's in your result")
Ha! Didn't think I'd get to apply DeMorgan's Law so soon.
--
Neil Cerutti
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Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
# your program is quite complicated. classes are overkill. A simpler
solution is:
import random
for i in range(5):
roll = random.randint(1,6)
if roll not in (1,5):
print('you can roll again')
break
else:
print("you have all 1's and 5's in your result'")
# comments on using classes:
class Dice:
...
# no need for die1...die5 - use list comprehension:
alldice = [Dice(6) for i in range(5)]
# object is a bult-in type. it is inadvisable to assign to names of
built-ins
# as this makes the built-in unavailable. Look up builtins (module) in
help for
# a complete list.
# use list comprehension roll and report:
print([d.roll_dice() for d in alldice])
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Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
Well these worked like a charm. Cant say I understand some of them and will have to look into utilizing them in the future, but I appreciate everyones responses and thank you all. Never needed to check for multiple instances in a list before. Nice to have help! -- https://mail.python.org/mailman/listinfo/python-list
Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
On Sat, 06 Oct 2018 21:56:09 +0200, Thomas Jollans wrote:
> On 06/10/2018 20:10, eliteanarchyra...@gmail.com wrote:
>> # - THIS LINE IS WHERE I NEED HELP # ( if 2, 3, 4, 6 in list:
>> )
>> print("you can roll again")
>> else:
>> print("you have all 1's and 5's in your result")
>>
>>
> You can use a loop:
>
> for good_number in [2,3,4,6]:
> if good_number in result:
> print("you can roll again")
> break
> else:
> print("you have all 1's and 5's in your result")
or simply check for 1 & 5 to exit otherwise continue
--
Someone hooked the twisted pair wires into the answering machine.
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Re : Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
You could use any and a generator expression.
It sounds pretty hard, but it's actually easily expressed, and pretty
intelligible.
Here you go:
if any(n in result for n in [2, 3, 4, 6]):
# reroll
else:
# do your thing
-
Armand FOUCAULT
armand.fouca...@telecom-bretagne.eu
Message original
Objet**: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
De**: eliteanarchyra...@gmail.com
: python-list@python.org
Cc**:
Hi, I am new to python and would like someones help on the following:
After rolling 5 dice and putting the results into a list, I need to
check if any dice is not a 1 or 5.
if all dice in the list are either a 1 or 5 , I want to calculate a
result.
if there is a 2,3,4 or 6 in the list i want to let the user roll again
FOR EXACT LINE: PLEASE CHECK CODE
CODE:
from random import *
class Dice:
def __init__(self, sides, color="white"):
self.sides = sides
self.color = color
def roll_dice(self):
result = randint(1, self.sides)
return result
die1 = Dice(6)
die2 = Dice(6)
die3 = Dice(6)
die4 = Dice(6)
die5 = Dice(6)
alldice = [die1, die2, die3, die4, die5]
result = []
start = input("Press enter to roll your dice:")
for object in alldice:
temp = object.roll_dice()
result.append(temp)
print(result)
# - THIS LINE IS WHERE I NEED HELP # ( if 2, 3, 4, 6 in list: )
print("you can roll again")
else:
print("you have all 1's and 5's in your result")
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Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
On 06/10/2018 20:10, eliteanarchyra...@gmail.com wrote:
# - THIS LINE IS WHERE I NEED HELP # ( if 2, 3, 4, 6 in list: )
print("you can roll again")
else:
print("you have all 1's and 5's in your result")
You can use a loop:
for good_number in [2,3,4,6]:
if good_number in result:
print("you can roll again")
break
else:
print("you have all 1's and 5's in your result")
--
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Re: Creating dice game : NEED HELP ON CHECKING ELEMENTS IN A LIST
On 2018-10-06 19:10, eliteanarchyra...@gmail.com wrote:
Hi, I am new to python and would like someones help on the following:
After rolling 5 dice and putting the results into a list, I need to check if
any dice is not a 1 or 5.
if all dice in the list are either a 1 or 5 , I want to calculate a result.
if there is a 2,3,4 or 6 in the list i want to let the user roll again
FOR EXACT LINE: PLEASE CHECK CODE
CODE:
from random import *
class Dice:
def __init__(self, sides, color="white"):
self.sides = sides
self.color = color
def roll_dice(self):
result = randint(1, self.sides)
return result
die1 = Dice(6)
die2 = Dice(6)
die3 = Dice(6)
die4 = Dice(6)
die5 = Dice(6)
alldice = [die1, die2, die3, die4, die5]
result = []
start = input("Press enter to roll your dice:")
for object in alldice:
temp = object.roll_dice()
result.append(temp)
print(result)
# - THIS LINE IS WHERE I NEED HELP # ( if 2, 3, 4, 6 in list: )
print("you can roll again")
else:
print("you have all 1's and 5's in your result")
The simplest (and longest) way is:
if 2 in result or 3 in result or 4 in result or 6 in result:
A cleverer way is to use sets:
if set(result) & {2, 3, 4, 6}:
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