Re: Problem adding a Key Value pair

[MRAB]

On 2014-11-04 19:37, Anurag Patibandla wrote:


I am trying to add a key value pair of (Priority:1) to queue1, (Priority:2) to queue2, and 
(Priority:3) to queue3.
When I just add (Priority:1) to queue1, it works.
But when I run the above code, (Priority:3) is being added to all the 
queues.
This looks trivial and I don't understand why this is happening. Is there 
something wrong with what I am doing?

json_split = {}
value = {Status: Submitted, m_Controller: Python}
a = range(31)
del a[0]


That's better as:

a = range(1, 31)


for i in a:
 json_split[i] = value


Here the key will be whatever 'i' refers to (1..30) and the value will
be the dict referred to by 'value'.

Try adding the line:

print json_split[1] is json_split[2]

It'll print out 'True'; it's saying that they are the same dict.

You want the values of json_split to be _separate_ dicts.

The fix is simple. Just make a copy of the dict for each one:

for i in a:
  json_split[i] = dict(value)

[snip]

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Re: Problem adding a Key Value pair

[Anurag Patibandla]

On Tuesday, November 4, 2014 2:37:49 PM UTC-5, Anurag Patibandla wrote:
 I am trying to add a key value pair of (Priority:1) to queue1, 
 (Priority:2) to queue2, and (Priority:3) to queue3. 
 When I just add (Priority:1) to queue1, it works. 
 But when I run the above code, (Priority:3) is being added to all the 
 queues. 
 This looks trivial and I don't understand why this is happening. Is there 
 something wrong with what I am doing?
 
 json_split = {} 
 value = {Status: Submitted, m_Controller: Python} 
 a = range(31) 
 del a[0] 
 for i in a: 
 json_split[i] = value 
 keys = json_split.keys() 
 order = list(keys) 
 q1 = int(round(len(keys)*0.2)) 
 q2 = int(round(len(keys)*0.3)) 
 q3 = int(round(len(keys)*0.5)) 
 b = [q1,q2,q3] 
 n=0 
 threedicts = [] 
 for i in b: 
 queues = order[n:n+i] 
 n = n+i 
 lists = [(queues[j], json_split.get(queues[j])) for j in 
 range(len(queues))] 
 onedict = {} 
 for q in queues: 
 onedict[q] = json_split[q] 
 threedicts.append (onedict) 
 queue1, queue2, queue3 = threedicts 
 keys1 = queue1.keys() 
 for i in keys1: 
 queue1[i]['Priority'] = ['1'] 
 keys2 = queue2.keys() 
 for j in keys2: 
 queue2[j]['Priority'] = ['2'] 
 keys3 = queue3.keys() 
 for z in keys3: 
 queue3[z]['Priority'] = ['3']

Awesome! Thank you!!
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