Re: array of array of float
"Schüle Daniel" wrote: > > a = [[] for in range(200)] > > correction :) > > a = [[] for i in range(200)] the "*500" part still seems to be missing... -- http://mail.python.org/mailman/listinfo/python-list
Re: array of array of float
Use nested list comprehensions: matrix = [[0.0 for x in xrange(n)] for y in xrange(m)] This is similar to "float matrix[m][n]" in C. All cells are independent of each other in doing this. -- http://mail.python.org/mailman/listinfo/python-list
Re: array of array of float
Schüle Daniel schrieb: > [EMAIL PROTECTED] schrieb: >> i used C too much and haven't used Python for a while... >> >> like in C, if we want an array of array of float, we use >> >> float a[200][500]; >> >> now in Python, seems like we have to do something like >> >> a = [ [ ] ] * 200 >> >> and then just use >> >> a[1].append(12.34) etc >> >> but it turns out that all 200 elements points to the same list... >> and i have to use >> >> a = [ ] >> for i in range (0, 200): >> a.append([ ]) >> >> is there a simpler way... i wonder... > > a = [[] for in range(200)] correction :) a = [[] for i in range(200)] -- http://mail.python.org/mailman/listinfo/python-list
Re: array of array of float
[EMAIL PROTECTED] schrieb: > i used C too much and haven't used Python for a while... > > like in C, if we want an array of array of float, we use > > float a[200][500]; > > now in Python, seems like we have to do something like > > a = [ [ ] ] * 200 > > and then just use > > a[1].append(12.34) etc > > but it turns out that all 200 elements points to the same list... > and i have to use > > a = [ ] > for i in range (0, 200): > a.append([ ]) > > is there a simpler way... i wonder... a = [[] for in range(200)] -- http://mail.python.org/mailman/listinfo/python-list
Re: array of array of float
[EMAIL PROTECTED] wrote: > i used C too much and haven't used Python for a while... > > like in C, if we want an array of array of float, we use > > float a[200][500]; > > now in Python, seems like we have to do something like > > a = [ [ ] ] * 200 > > and then just use > > a[1].append(12.34) etc > > but it turns out that all 200 elements points to the same list... > and i have to use > > a = [ ] > for i in range (0, 200): > a.append([ ]) > > is there a simpler way... i wonder... > Right, try the numpy module, and you can do: from numpy import * a = zeros((200,500), Float) documentation: http://numeric.scipy.org/numpydoc/numpy-6.html#pgfId-60291 download: http://sourceforge.net/project/showfiles.php?group_id=1369&package_id=175103 main page: http://numeric.scipy.org/ -- http://mail.python.org/mailman/listinfo/python-list
Re: array of array of float
[EMAIL PROTECTED] wrote: > i used C too much and haven't used Python for a while... > > like in C, if we want an array of array of float, we use > > float a[200][500]; > > now in Python, seems like we have to do something like > > a = [ [ ] ] * 200 > > and then just use > > a[1].append(12.34) etc > > but it turns out that all 200 elements points to the same list... > and i have to use > > a = [ ] > for i in range (0, 200): > a.append([ ]) > > is there a simpler way... i wonder... this is FAQ: http://pyfaq.infogami.com/how-do-i-create-a-multidimensional-list -- http://mail.python.org/mailman/listinfo/python-list
