Re: connect SIGINT to custom interrupt handler
Christoph Scheingraber wrote: On 2011-05-15, Thomas 'PointedEars' Lahn pointede...@web.de wrote: Obviously. `signal' refers to an `int' object, probably by something like signal = 42 before. E.g. `print' or a debugger will tell you, as you have not showed the relevant parts of the code. The problem is that I am running someone else's module which seems to use signal, I guess that means I have to create a child method? Is it correct anyway to have signal.siginterrupt(signal.SIGINT, False) in my custom interrupt_handler function Only if `signal' is not the name of an int argument. or should it be outside but after signal.signal(signal.SIGINT, interrupt_handler)? In the meantime, Chris Angelico has pointed out the cause of the problem. Please follow his advice, i.e. rename your argument. -- PointedEars Bitte keine Kopien per E-Mail. / Please do not Cc: me. -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On Wed, 18 May 2011 07:16:40 -0700, Jean-Paul Calderone wrote: Setting SA_RESTART on SIGINT is probably the right thing to do. It's not totally clear to me from the messages in this thread if you managed to get that approach working. He didn't; select() isn't SA_RESTART-able. Unfortunately, the author of select.select() decided to treat EINTR as an error. It isn't; it's a third way, neither success nor failure, similar to EAGAIN. Normally, you would treat EINTR from select() in the same way as a timeout. While it's possible to work around this, the interface encourages getting it wrong. -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On 2011-05-15, Miki Tebeka miki.teb...@gmail.com wrote:
Why not just catch KeyboardInterrupt?
Would it be possible to continue my program as nothing had happened in
that case (like I did before, setting a flag to tell main() to finish the
running data download and quit instead of starting the next data download
{it's a for-loop})?
I have tried it, but after catching the KeyboardInterrupt I could only
continue to the next iteration.
--
http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On May 18, 9:28 am, Christoph Scheingraber s...@scheingraber.net
wrote:
On 2011-05-15, Miki Tebeka miki.teb...@gmail.com wrote:
Why not just catch KeyboardInterrupt?
Would it be possible to continue my program as nothing had happened in
that case (like I did before, setting a flag to tell main() to finish the
running data download and quit instead of starting the next data download
{it's a for-loop})?
I have tried it, but after catching the KeyboardInterrupt I could only
continue to the next iteration.
No, since the exception being raised represents a different flow of
control
through the program, one that is mutually exclusive with the flow of
control
which would be involved with continuing the processing in the
current
iteration of your loop.
Setting SA_RESTART on SIGINT is probably the right thing to do. It's
not
totally clear to me from the messages in this thread if you managed to
get
that approach working. The most commonly encountered problem with
this
approach is that it means that any blocking (eg I/O) operation in
progress
won't be interrupted and you'll have to wait for it to complete
normally.
In this case, it sounds like this is the behavior you actually want,
though.
Jean-Paul
--
http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On Sun, 15 May 2011 09:44:04 +, Christoph Scheingraber wrote: signal.signal(signal.SIGINT, interrupt_handler) This worked fine in some rare lucky cases, but most of the times, the module I am using (my university's seismology project) catches the SIGINT and quits: select.error: (4, 'Interrupted system call') After installing the signal handler, call: signal.siginterrupt(signal.SIGINT, False) This will cause (most) interrupted system calls to be restarted after the signal has been handled. How can I prevent the imported module's function from catching the interrupt signal? It isn't catching the signal. Unless you enable restarting of system calls, an interrupted system call will typically fail with EINTR. Python typically reports failures via exceptions; failures due to EINTR aren't handled differently. -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
I now have signal.siginterrupt(signal.SIGINT, False) in the line below signal.signal(signal.SIGINT, interrupt_handler) Unfortunately, pressing ^c still results in the same interrupt error. I also tried putting signal.siginterrupt into the interrupt_handler function, which gave an interesting result: File /usr/local/bin/obspysod, line 586, in interrupt_handler signal.siginterrupt(signal.SIGINT, False) AttributeError: 'int' object has no attribute 'siginterrupt' Could there be a namespace problem? On 2011-05-15, Nobody nob...@nowhere.com wrote: On Sun, 15 May 2011 09:44:04 +, Christoph Scheingraber wrote: signal.signal(signal.SIGINT, interrupt_handler) This worked fine in some rare lucky cases, but most of the times, the module I am using (my university's seismology project) catches the SIGINT and quits: select.error: (4, 'Interrupted system call') After installing the signal handler, call: signal.siginterrupt(signal.SIGINT, False) This will cause (most) interrupted system calls to be restarted after the signal has been handled. How can I prevent the imported module's function from catching the interrupt signal? It isn't catching the signal. Unless you enable restarting of system calls, an interrupted system call will typically fail with EINTR. Python typically reports failures via exceptions; failures due to EINTR aren't handled differently. -- Chris Scheingraber - www.scheingraber.net -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
Greetings, I am trying to connect SIGINT (^c) to a custom interrupt handler like this (no threading, just straightforward): Why not just catch KeyboardInterrupt? All the best, -- Miki -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On Mon, May 16, 2011 at 12:32 AM, Christoph Scheingraber ch...@spam.org wrote: I now have signal.siginterrupt(signal.SIGINT, False) in the line below signal.signal(signal.SIGINT, interrupt_handler) Unfortunately, pressing ^c still results in the same interrupt error. I also tried putting signal.siginterrupt into the interrupt_handler function, which gave an interesting result: File /usr/local/bin/obspysod, line 586, in interrupt_handler signal.siginterrupt(signal.SIGINT, False) AttributeError: 'int' object has no attribute 'siginterrupt' Could there be a namespace problem? def interrupt_handler(signal, frame): You're using 'signal' as a parameter here. The local int is masking the global module. Chris Angelico -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
Christoph Scheingraber wrote: I now have signal.siginterrupt(signal.SIGINT, False) in the line below signal.signal(signal.SIGINT, interrupt_handler) Unfortunately, pressing ^c still results in the same interrupt error. I also tried putting signal.siginterrupt into the interrupt_handler function, which gave an interesting result: File /usr/local/bin/obspysod, line 586, in interrupt_handler signal.siginterrupt(signal.SIGINT, False) AttributeError: 'int' object has no attribute 'siginterrupt' Could there be a namespace problem? Obviously. `signal' refers to an `int' object, probably by something like signal = 42 before. E.g. `print' or a debugger will tell you, as you have not showed the relevant parts of the code. Please trim your quotes to the relevant minimum; DO NOT top-post. Also, it is not acceptable behavior to use domain namespaces without authorization (ch...@spam.org is not a mailbox, yet spam.org is registered to someone else). -- PointedEars Bitte keine Kopien per E-Mail. / Please do not Cc: me. -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On 2011-05-15, Thomas 'PointedEars' Lahn pointede...@web.de wrote: Obviously. `signal' refers to an `int' object, probably by something like signal = 42 before. E.g. `print' or a debugger will tell you, as you have not showed the relevant parts of the code. The problem is that I am running someone else's module which seems to use signal, I guess that means I have to create a child method? Is it correct anyway to have signal.siginterrupt(signal.SIGINT, False) in my custom interrupt_handler function or should it be outside but after signal.signal(signal.SIGINT, interrupt_handler)? Please trim your quotes to the relevant minimum; DO NOT top-post. Also, it is not acceptable behavior to use domain namespaces without authorization (ch...@spam.org is not a mailbox, yet spam.org is registered to someone else). I am sorry, I changed it to my own domain. -- Chris Scheingraber - www.scheingraber.net -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On Sun, 15 May 2011 17:05:57 +, Christoph Scheingraber wrote: Is it correct anyway to have signal.siginterrupt(signal.SIGINT, False) in my custom interrupt_handler function No. or should it be outside but after signal.signal(signal.SIGINT, interrupt_handler)? Yes. -- http://mail.python.org/mailman/listinfo/python-list
Re: connect SIGINT to custom interrupt handler
On Sun, 15 May 2011 14:32:13 +, Christoph Scheingraber wrote: I now have signal.siginterrupt(signal.SIGINT, False) in the line below signal.signal(signal.SIGINT, interrupt_handler) Unfortunately, pressing ^c still results in the same interrupt error. Sorry; I wasn't paying sufficient attention to the details: select.error: (4, 'Interrupted system call') According to Linux' signal(7) manpage, select() is never restarted, regardless of the siginterrupt() setting. In general, wait-for-something functions aren't restarted; the caller is expected to check that the waited-for condition actually happened, so returning prematurely isn't considered problematic. EINTR is one of those special errors (like EAGAIN) which don't actually indicate an error. In the context of select(), a return value of -1 with errno set to EINTR should normally be handled in the same way as a return value of zero, i.e. nothing has happened yet, try again. While the EINTR case isn't identical to the zero-return case, it's much closer to it than it is to a genuine error. If it's being treated like genuine errors (i.e. raising an exception), that's a defect in the Python bindings. In which case, I'd suggest catching the exception and checking the error code, e.g.: def myselect(rlist, wlist, xlist, timeout = None): try: return select.select(rlist, wlist, xlist, timeout) except select.error, e: if e[0] == errno.EINTR: return 0 raise -- http://mail.python.org/mailman/listinfo/python-list
