Re: converting to and from octal escaped UTF--8
Michael Goerz [EMAIL PROTECTED] (MG) wrote: MG if (ord(character) 32) or (ord(character) 128): If you encode chars 32 it seems more appropriate to also encode 127. Moreover your code is quadratic in the size of the string so if you use long strings it would be better to use join. -- Piet van Oostrum [EMAIL PROTECTED] URL: http://www.cs.uu.nl/~piet [PGP 8DAE142BE17999C4] Private email: [EMAIL PROTECTED] -- http://mail.python.org/mailman/listinfo/python-list
Re: converting to and from octal escaped UTF--8
On Dec 3, 8:10 am, Michael Goerz [EMAIL PROTECTED] wrote:
MonkeeSage wrote:
On Dec 3, 1:31 am, MonkeeSage [EMAIL PROTECTED] wrote:
On Dec 2, 11:46 pm, Michael Spencer [EMAIL PROTECTED] wrote:
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
Perhaps something along the lines of:
def encode(source):
... return .join(\%o % ord(c) for c in source.encode('utf8'))
...
def decode(encoded):
... bytes = .join(chr(int(c, 8)) for c in encoded.split('\\')[1:])
... return bytes.decode('utf8')
...
encode(uÍ)
'\\303\\215'
print decode(_)
Í
HTH
Michael
Nice one. :) If I might suggest a slight variation to handle cases
where the encoded string contains plain text as well as octal
escapes...
def decode(encoded):
for octc in (c for c in re.findall(r'\\(\d{3})', encoded)):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
This way it can handle both \\141\\144\\146\\303\\215\\141\\144\\146
as well as adf\\303\\215adf.
Regards,
Jordan
err...
def decode(encoded):
for octc in re.findall(r'\\(\d{3})', encoded):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
Great suggestions from both of you! I came up with my final solution
based on them. It encodes only non-ascii and non-printables, and stays
in unicode strings for both input and output. Also, low ascii values now
encode into a 3-digit octal sequence also, so that decode can catch them
properly.
Thanks a lot,
Michael
import re
def encode(source):
encoded =
for character in source:
if (ord(character) 32) or (ord(character) 128):
for byte in character.encode('utf8'):
encoded += (\%03o % ord(byte))
else:
encoded += character
return encoded.decode('utf-8')
def decode(encoded):
decoded = encoded.encode('utf-8')
for octc in re.findall(r'\\(\d{3})', decoded):
decoded = decoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return decoded.decode('utf8')
orig = ublaÍblub + chr(10)
enc = encode(orig)
dec = decode(enc)
print orig
print enc
print dec
An optimization...in decode() store matches as keys in a dict, so you
only do the string replacement once for each unique character...
def decode(encoded):
decoded = encoded.encode('utf-8')
matches = {}
for octc in re.findall(r'\\(\d{3})', decoded):
matches[octc] = None
for octc in matches:
decoded = decoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return decoded.decode('utf8')
Untested...
Regards,
Jordan
--
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Re: converting to and from octal escaped UTF--8
MonkeeSage wrote:
On Dec 3, 1:31 am, MonkeeSage [EMAIL PROTECTED] wrote:
On Dec 2, 11:46 pm, Michael Spencer [EMAIL PROTECTED] wrote:
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
Perhaps something along the lines of:
def encode(source):
... return .join(\%o % ord(c) for c in source.encode('utf8'))
...
def decode(encoded):
... bytes = .join(chr(int(c, 8)) for c in encoded.split('\\')[1:])
... return bytes.decode('utf8')
...
encode(uÍ)
'\\303\\215'
print decode(_)
Í
HTH
Michael
Nice one. :) If I might suggest a slight variation to handle cases
where the encoded string contains plain text as well as octal
escapes...
def decode(encoded):
for octc in (c for c in re.findall(r'\\(\d{3})', encoded)):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
This way it can handle both \\141\\144\\146\\303\\215\\141\\144\\146
as well as adf\\303\\215adf.
Regards,
Jordan
err...
def decode(encoded):
for octc in re.findall(r'\\(\d{3})', encoded):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
Great suggestions from both of you! I came up with my final solution
based on them. It encodes only non-ascii and non-printables, and stays
in unicode strings for both input and output. Also, low ascii values now
encode into a 3-digit octal sequence also, so that decode can catch them
properly.
Thanks a lot,
Michael
import re
def encode(source):
encoded =
for character in source:
if (ord(character) 32) or (ord(character) 128):
for byte in character.encode('utf8'):
encoded += (\%03o % ord(byte))
else:
encoded += character
return encoded.decode('utf-8')
def decode(encoded):
decoded = encoded.encode('utf-8')
for octc in re.findall(r'\\(\d{3})', decoded):
decoded = decoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return decoded.decode('utf8')
orig = ublaÍblub + chr(10)
enc = encode(orig)
dec = decode(enc)
print orig
print enc
print dec
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Re: converting to and from octal escaped UTF--8
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
I know I can get the code point by doing
Í.decode('utf-8').encode('unicode_escape')
but there doesn't seem to be any similar method for getting the octal
escaped version.
Thanks,
Michael
I've come up with the following solution. It's not very pretty, but it
works (no bugs, I hope). Can anyone think of a better way to do it?
Michael
_
import binascii
def escape(s):
hexstring = binascii.b2a_hex(s)
result =
while len(hexstring) 0:
(hexbyte, hexstring) = (hexstring[:2], hexstring[2:])
octbyte = oct(int(hexbyte, 16)).zfill(3)
result += \\ + octbyte[-3:]
return result
def unescape(s):
result =
while len(s) 0:
if s[0] == \\:
(octbyte, s) = (s[1:4], s[4:])
try:
result += chr(int(octbyte, 8))
except ValueError:
result += \\
s = octbyte + s
else:
result += s[0]
s = s[1:]
return result
print escape(\303\215)
print unescape('adf\\303\\215adf')
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Re: converting to and from octal escaped UTF--8
On Dec 2, 8:38 pm, Michael Goerz [EMAIL PROTECTED] wrote:
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
I know I can get the code point by doing
Í.decode('utf-8').encode('unicode_escape')
but there doesn't seem to be any similar method for getting the octal
escaped version.
Thanks,
Michael
I've come up with the following solution. It's not very pretty, but it
works (no bugs, I hope). Can anyone think of a better way to do it?
Michael
_
import binascii
def escape(s):
hexstring = binascii.b2a_hex(s)
result =
while len(hexstring) 0:
(hexbyte, hexstring) = (hexstring[:2], hexstring[2:])
octbyte = oct(int(hexbyte, 16)).zfill(3)
result += \\ + octbyte[-3:]
return result
def unescape(s):
result =
while len(s) 0:
if s[0] == \\:
(octbyte, s) = (s[1:4], s[4:])
try:
result += chr(int(octbyte, 8))
except ValueError:
result += \\
s = octbyte + s
else:
result += s[0]
s = s[1:]
return result
print escape(\303\215)
print unescape('adf\\303\\215adf')
Looks like escape() can be a bit simpler...
def escape(s):
result = []
for char in s:
result.append(\%o % ord(char))
return ''.join(result)
Regards,
Jordan
--
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Re: converting to and from octal escaped UTF--8
MonkeeSage wrote: Looks like escape() can be a bit simpler... def escape(s): result = [] for char in s: result.append(\%o % ord(char)) return ''.join(result) Regards, Jordan Very neat! Thanks a lot... Michael -- http://mail.python.org/mailman/listinfo/python-list
Re: converting to and from octal escaped UTF--8
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
Perhaps something along the lines of:
def encode(source):
... return .join(\%o % ord(c) for c in source.encode('utf8'))
...
def decode(encoded):
... bytes = .join(chr(int(c, 8)) for c in encoded.split('\\')[1:])
... return bytes.decode('utf8')
...
encode(uÍ)
'\\303\\215'
print decode(_)
Í
HTH
Michael
--
http://mail.python.org/mailman/listinfo/python-list
Re: converting to and from octal escaped UTF--8
On Dec 2, 11:46 pm, Michael Spencer [EMAIL PROTECTED] wrote:
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
Perhaps something along the lines of:
def encode(source):
... return .join(\%o % ord(c) for c in source.encode('utf8'))
...
def decode(encoded):
... bytes = .join(chr(int(c, 8)) for c in encoded.split('\\')[1:])
... return bytes.decode('utf8')
...
encode(uÍ)
'\\303\\215'
print decode(_)
Í
HTH
Michael
Nice one. :) If I might suggest a slight variation to handle cases
where the encoded string contains plain text as well as octal
escapes...
def decode(encoded):
for octc in (c for c in re.findall(r'\\(\d{3})', encoded)):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
This way it can handle both \\141\\144\\146\\303\\215\\141\\144\\146
as well as adf\\303\\215adf.
Regards,
Jordan
--
http://mail.python.org/mailman/listinfo/python-list
Re: converting to and from octal escaped UTF--8
On Dec 3, 1:31 am, MonkeeSage [EMAIL PROTECTED] wrote:
On Dec 2, 11:46 pm, Michael Spencer [EMAIL PROTECTED] wrote:
Michael Goerz wrote:
Hi,
I am writing unicode stings into a special text file that requires to
have non-ascii characters as as octal-escaped UTF-8 codes.
For example, the letter Í (latin capital I with acute, code point 205)
would come out as \303\215.
I will also have to read back from the file later on and convert the
escaped characters back into a unicode string.
Does anyone have any suggestions on how to go from Í to \303\215 and
vice versa?
Perhaps something along the lines of:
def encode(source):
... return .join(\%o % ord(c) for c in source.encode('utf8'))
...
def decode(encoded):
... bytes = .join(chr(int(c, 8)) for c in encoded.split('\\')[1:])
... return bytes.decode('utf8')
...
encode(uÍ)
'\\303\\215'
print decode(_)
Í
HTH
Michael
Nice one. :) If I might suggest a slight variation to handle cases
where the encoded string contains plain text as well as octal
escapes...
def decode(encoded):
for octc in (c for c in re.findall(r'\\(\d{3})', encoded)):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
This way it can handle both \\141\\144\\146\\303\\215\\141\\144\\146
as well as adf\\303\\215adf.
Regards,
Jordan
err...
def decode(encoded):
for octc in re.findall(r'\\(\d{3})', encoded):
encoded = encoded.replace(r'\%s' % octc, chr(int(octc, 8)))
return encoded.decode('utf8')
--
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