Re: String Formatting
OriginalBrownster wrote:
> Hi there:
>
> I was wondering if its at all possible to search through a string for a
> specific character.
>
> I want to search through a string backwords and find the last
> period/comma, then take everything after that period/comma
>
> Example
>
> If i had a list:bread, butter, milk
>
> I want to just take that last entry of milk. However the need for it
> arises from something more complicated.
>
> Any help would be appreciated
>
Would that work for you ?
>>> a = 'bread, butter, milk'
>>> a
'bread, butter, milk'
>>> b = a.split(',')
>>> b
['bread', ' butter', ' milk']
>>> c = b[-1]
>>> c
' milk'
>>> d = c.strip()
>>> d
'milk'
HIH
Avell
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Re: String Formatting
On Thu, 10 Aug 2006 05:35:26 -0700, OriginalBrownster wrote:
> Hi there:
>
> I was wondering if its at all possible to search through a string for a
> specific character.
>
> I want to search through a string backwords and find the last
> period/comma, then take everything after that period/comma
>
> Example
>
> If i had a list:bread, butter, milk
>
> I want to just take that last entry of milk. However the need for it
> arises from something more complicated.
>
> Any help would be appreciated
>>> s='bread, butter, milk'
>>> s.rsplit(',', 1)[-1]
' milk'
>>> s.rsplit(',', 1)[-1].strip()
'milk'
Hope that helps.
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Re: String Formatting
OriginalBrownster wrote:
> Hi there:
>
> I was wondering if its at all possible to search through a string for a
> specific character.
>
> I want to search through a string backwords and find the last
> period/comma, then take everything after that period/comma
>
> Example
>
> If i had a list:bread, butter, milk
>
> I want to just take that last entry of milk. However the need for it
> arises from something more complicated.
>
> Any help would be appreciated
The rfind() method of strings will search through a string for the
first occurance of a substring, starting from the end. (find() starts
from the beginning.)
|>> s = "bread, butter, milk"
|>> s.rfind(',')
13
|>> s.rfind('!')
-1
|>> s[s.rfind(',') + 1:]
' milk'
If you want to find either a period or comma you could do it like this:
|>> i = max(s.rfind(ch) for ch in ',.')
|>> i
13
|>> s[i + 1:]
' milk'
Here's the output of help(s.rfind):
Help on built-in function rfind:
rfind(...)
S.rfind(sub [,start [,end]]) -> int
Return the highest index in S where substring sub is found,
such that sub is contained within s[start,end]. Optional
arguments start and end are interpreted as in slice notation.
Return -1 on failure.
Enjoy
Peace,
~Simon
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Re: String Formatting
OriginalBrownster wrote:
> Example
>
> If i had a list:bread, butter, milk
def get_word(s, which=1, sep=','):
return s.split(sep)[which-1].strip()
>>>
>>> get_word('bread, butter, milk')
'milk'
>>>
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Re: String Formatting
alisonken1 wrote: > OriginalBrownster wrote: > > > Example sorry, forgot the '... everything after the last comma ...' part. -- http://mail.python.org/mailman/listinfo/python-list
Re: String Formatting
Sorry, missed an option in there:
> def get_word(s, which=1, sep=','):
> return s.split(sep)[which-1].strip()
>
> >>>
> >>> get_word('bread, butter, milk')
> 'milk'
>
> >>>
>>> get_word('bread, butter, milk')
'bread'
>>> get_word('bread, butter, milk', 3)
'milk'
>>> get_word('bread is brown, butter is yellow, milk is white')
'bread is brown'
>>> get_word('bread is brown, butter is yello, milk is white', 3)
'milk is white'
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Re: String Formatting
OriginalBrownster wrote:
> Hi there:
>
> I was wondering if its at all possible to search through a string for a
> specific character.
Don't wonder; read the tutorials, read the manuals, and ponder the
sheer uselessness of any computer language that offered neither such a
facility nor the means to build it yourself.
>
> I want to search through a string backwords and find the last
> period/comma, then take everything after that period/comma
>
> Example
>
> If i had a list:bread, butter, milk
>
> I want to just take that last entry of milk. However the need for it
> arises from something more complicated.
>
Python terminology: that's not a list, it's a string.
> Any help would be appreciated
If you already know that you are looking for a comma, then the
following will do the job. If you know that you are looking for a
period, make the obvious substitution.
>>> x = " bread, butter, milk "
>>> x.split(",")
[' bread', ' butter', ' milk ']
>>> x.split(",")[-1]
' milk '
>>> x.split(",")[-1].strip()
'milk'
>>> x = " no commas at all "
>>> x.split(",")
[' no commas at all ']
>>> x.split(",")[-1]
' no commas at all '
>>> x.split(",")[-1].strip()
'no commas at all'
>>>
*HOWEVER* if you really mean what you said (i.e. start at the
rightmost, go left until you strike either a comma or a period,
whichever comes first) then you need something like this:
>>> def grab_last_chunk(s):
...return s[max(s.rfind(','), s.rfind('.')) + 1:]
...
>>> grab_last_chunk(" bread, butter, milk ")
' milk '
>>> grab_last_chunk(" bread, butter. milk ")
' milk '
>>> grab_last_chunk(" bread! butter! milk ")
' bread! butter! milk '
>>> grab_last_chunk(" bread, butter, milk.")
''
>>>
The serendipity in the above is that if the sought character is not
found, rfind() returns -1 which fits in nicely without the need for an
"if" statement to do something special.
HTH,
John
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Re: String formatting strangeness
[EMAIL PROTECTED] wrote: > I must be doing something wrong, but for the life of me, I can't figure > out what. Here's the code snippet which is giving me grief: > > print type(number), type(name), type(seconds // 60), type(seconds % 60) > print "\t\t\t\n" > % [number, name, seconds // 60, seconds % 60] [snip] > > Wait, what? The first line clearly identifies that the the first, > third, and fourth elements are all integers, yet the error says that > *lack* of integers is the problem. If I change all "%i"s to "%d", I > get the same problem, and changing to "%s" (hey, it was worth a shot) > gives "TypeError: not enough arguments for format string" instead. > Huh? I see four placeholders and a four-element tuple. Nope, you see a four-element list. Try changing it to a tuple... ;-) -Peter -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting strangeness
The argument to string format expression needs to be a tuple not a list. Also, all the string escaping makes this very hard to read. You can mix single and double quotes to achieve: print '\t\t\t\n' % \ (number, name, seconds // 60, seconds % 60) which IMHO is much easier to read. Larry Bates [EMAIL PROTECTED] wrote: > I must be doing something wrong, but for the life of me, I can't figure > out what. Here's the code snippet which is giving me grief: > > print type(number), type(name), type(seconds // 60), type(seconds % 60) > print "\t\t\t\n" > % [number, name, seconds // 60, seconds % 60] > > (These are lines 49 and 50 of the script; I can post the whole thing if > someone wants, but I think this is enough to see why it's driving me > nuts.) > > And the output: > > > Traceback (most recent call last): > File "X:\Music (FLAC)\Post-process new rips.py", line 50, in ? > print "\t\t\t length=\"%i:%i\"/>\n" % [number, name, seconds // 60, seconds % 60] > TypeError: int argument required > > Wait, what? The first line clearly identifies that the the first, > third, and fourth elements are all integers, yet the error says that > *lack* of integers is the problem. If I change all "%i"s to "%d", I > get the same problem, and changing to "%s" (hey, it was worth a shot) > gives "TypeError: not enough arguments for format string" instead. > Huh? I see four placeholders and a four-element tuple. > > Can anyone enlighten me here? > -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting strangeness
[EMAIL PROTECTED] wrote: > > Traceback (most recent call last): > File "X:\Music (FLAC)\Post-process new rips.py", line 50, in ? > print "\t\t\t length=\"%i:%i\"/>\n" % [number, name, seconds // 60, seconds % 60] > TypeError: int argument required > > Wait, what? The first line clearly identifies that the the first, > third, and fourth elements are all integers, yet the error says that > *lack* of integers is the problem. If I change all "%i"s to "%d", I > get the same problem, and changing to "%s" (hey, it was worth a shot) > gives "TypeError: not enough arguments for format string" instead. > Huh? I see four placeholders and a four-element tuple. [number, name, seconds // 60, seconds % 60] is not a tuple. (number, name, seconds // 60, seconds % 60) is a tuple. -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting strangeness
*hides face* Groan! This is what I get for trying to code first thing in the morning. Thanks, all, it works fine now... -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting quirk?
[EMAIL PROTECTED] wrote:
> ''%([]) doesn't raise exception
> but
> ''%('') does
>
> Can anyone explain me why??
That is a side-effect of duck-typing. The duck-type of an empty list is
indistinguishable from that of an empty dictionary. Not testing the exact
type here achieves consistency with the behaviour of custom dictionaries,
e. g:
>>> class List(list):
... def __getitem__(self, index):
... return list.__getitem__(self, int(index))
...
>>> "%(0)s" % List([42])
'42'
>>> "%(1)s %(0)s" % List([42, 24])
'24 42'
>>> "" % List([])
''
Peter
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Re: String formatting using dictionaries
Clodoaldo Pinto wrote:
> I know how to format strings using a dictionary:
>
d = {'list':[0, 1]}
'%(list)s' % d
> '[0, 1]'
>
> Is it possible to reference an item in the list d['list']?:
>
'%(list[0])s' % d
> Traceback (most recent call last):
> File "", line 1, in ?
> KeyError: 'list[0]'
No, but you can provide a modified dictionary to get the effect:
>>> class Dict(dict):
... def __getitem__(self, key):
... if key in self:
... return super(Dict, self).__getitem__(key)
... return eval(key, self)
...
>>> d = Dict(list=[0, 1])
>>> "%(list)s" % d
'[0, 1]'
>>> "%(list[0])s" % d
'0'
>>> "%(list[1]+42)s" % d
'43'
Peter
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Re: String formatting using dictionaries
Clodoaldo Pinto wrote:
> I know how to format strings using a dictionary:
>
> >>> d = {'list':[0, 1]}
> >>> '%(list)s' % d
> '[0, 1]'
>
> Is it possible to reference an item in the list d['list']?:
>
> >>> '%(list[0])s' % d
> Traceback (most recent call last):
> File "", line 1, in ?
> KeyError: 'list[0]'
not directly, but you can wrap the dictionary in a custom mapper
class:
class mapper(dict):
def __getitem__(self, key):
try:
return dict.__getitem__(self, key)
except KeyError:
k, i = key.split("[")
i = int(i[:-1])
return dict.__getitem__(self, k)[i]
>>> d = {"list": [0, 1]}
>>> d = mapper(d)
>>> '%(list)s' % d
[0, 1]
>>> '%(list[0])s' % d
0
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Re: String formatting using dictionaries
Thank you guys, you are great! -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
Darren Dale wrote: > Does anyone know if it is possible to represent a number as a string with > engineering notation (like scientific notation, but with 10 raised to > multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the > decimal.Decimal class, but repeatedly instantiating Decimals is inefficient > for my application (matplotlib plotting library). If it is not currently > possible, do you think the python devs would be receptive to including > support for engineering notation in future releases? > How close is this: >>> "%.3e" % 3.14159 '3.142e+00' regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://del.icio.us/steve.holden Blog of Note: http://holdenweb.blogspot.com See you at PyCon? http://us.pycon.org/TX2007 -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
Steve Holden wrote: > Darren Dale wrote: >> Does anyone know if it is possible to represent a number as a string with >> engineering notation (like scientific notation, but with 10 raised to >> multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the >> decimal.Decimal class, but repeatedly instantiating Decimals is >> inefficient for my application (matplotlib plotting library). If it is >> not currently possible, do you think the python devs would be receptive >> to including support for engineering notation in future releases? >> > How close is this: > > >>> "%.3e" % 3.14159 > '3.142e+00' >>> "%.3e" % 31415.9 '3.142e+04' What I am looking for is '31.4159e+03' Darren -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
On 2007-03-14, Steve Holden <[EMAIL PROTECTED]> wrote: > Darren Dale wrote: >> Does anyone know if it is possible to represent a number as a string with >> engineering notation (like scientific notation, but with 10 raised to >> multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the >> decimal.Decimal class, but repeatedly instantiating Decimals is inefficient >> for my application (matplotlib plotting library). If it is not currently >> possible, do you think the python devs would be receptive to including >> support for engineering notation in future releases? >> > How close is this: > > >>> "%.3e" % 3.14159 > '3.142e+00' Not close at all. It should be "3.14159" >>> "%.3e" % 31.4159 '3.142e+01' should be 31.4159 >>> "%.3e" % 314.159 '3.142e+02' should be 314.159 >>> "%.3e" % 31415.9 '3.142e+04' should be 31.4159e3 -- Grant Edwards grante Yow! LOU GRANT froze at my ASSETS!! visi.com -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
Steve Holden <[EMAIL PROTECTED]> writes: > Darren Dale wrote: >> Does anyone know if it is possible to represent a number as a string with >> engineering notation (like scientific notation, but with 10 raised to >> multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the >> decimal.Decimal class, but repeatedly instantiating Decimals is inefficient >> for my application (matplotlib plotting library). If it is not currently >> possible, do you think the python devs would be receptive to including >> support for engineering notation in future releases? >> > How close is this: > > >>> "%.3e" % 3.14159 > '3.142e+00' >>> "%.3e" % 314159 '3.142e+05' >>> Not close when you have the exponent. -- Jorge Godoy <[EMAIL PROTECTED]> -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
On Mar 14, 1:14 pm, Darren Dale <[EMAIL PROTECTED]> wrote: > Does anyone know if it is possible to represent a number as a string with > engineering notation (like scientific notation, but with 10 raised to > multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the > decimal.Decimal class, but repeatedly instantiating Decimals is inefficient > for my application (matplotlib plotting library). If it is not currently > possible, do you think the python devs would be receptive to including > support for engineering notation in future releases? Do you also consider this to be too inefficient? import math for exponent in xrange(-10, 11): flt = 1.23 * math.pow(10, exponent) l = math.log10(flt) if l < 0: l = l - 3 p3 = int(l / 3) * 3 multiplier = flt / pow(10, p3) print '%e => %fe%d' % (flt, multiplier, p3) -- Hope this helps, Steven -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting: engineering notation
[EMAIL PROTECTED] wrote: > On Mar 14, 1:14 pm, Darren Dale <[EMAIL PROTECTED]> wrote: >> Does anyone know if it is possible to represent a number as a string with >> engineering notation (like scientific notation, but with 10 raised to >> multiples of 3: 120e3, 12e-6, etc.). I know this is possible with the >> decimal.Decimal class, but repeatedly instantiating Decimals is >> inefficient for my application (matplotlib plotting library). If it is >> not currently possible, do you think the python devs would be receptive >> to including support for engineering notation in future releases? > > > Do you also consider this to be too inefficient? > > > import math > > for exponent in xrange(-10, 11): > flt = 1.23 * math.pow(10, exponent) > l = math.log10(flt) > if l < 0: > l = l - 3 > p3 = int(l / 3) * 3 > multiplier = flt / pow(10, p3) > print '%e => %fe%d' % (flt, multiplier, p3) > That's a good suggestion. It's probably fast enough. I was hoping that something like '%n'%my_number already existed. -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting using the % operator
William Gill wrote: > I am using the % operator to create queries for a db app. It works fine > when exact strings, or numbers are used, but some queries need partial > matching that use the '%' as a wildcards. So for example the resultant > string should be 'WHERE name LIKE %smith%' (would match silversmith, > smithy, and smith). Is there any way to get something like > > searchterm = 'smith' > sql += 'WHERE name LIKE %s' % searchterm > > to return 'WHERE name LIKE %smith%'I have tried using escapes, > character codes for the % sign, and lots of other gyrations with no > success. The only thing that works is if I modify searchterm first: > > searchterm = 'smith' > searchterm ='%'+'smith'+'%' > sql += 'WHERE name LIKE %s' % searchterm > > Any Ideas? try this : sql += 'WHERE name LIKE %%%s%%' % searchterm -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting using the % operator
> to return 'WHERE name LIKE %smith%'I have tried using escapes, > character codes for the % sign, and lots of other gyrations with no > success. The only thing that works is if I modify searchterm first: > >searchterm = 'smith' >searchterm ='%'+'smith'+'%' >sql += 'WHERE name LIKE %s' % searchterm > > Any Ideas? >>> "%%%s%%" % "here you go" '%here you go%' Cheers, - harold - -- If your only tool is a hammer, every problem looks like a nail. -- -- http://mail.python.org/mailman/listinfo/python-list
Re: string formatting using the % operator
On Mon, 13 Jun 2005 15:12:54 GMT,
William Gill <[EMAIL PROTECTED]> wrote:
> I am using the % operator to create queries for a db app. It works fine
> when exact strings, or numbers are used, but some queries need partial
> matching that use the '%' as a wildcards. So for example the resultant
> string should be 'WHERE name LIKE %smith%' (would match silversmith,
> smithy, and smith). Is there any way to get something like
>searchterm = 'smith'
>sql += 'WHERE name LIKE %s' % searchterm
> to return 'WHERE name LIKE %smith%'I have tried using escapes,
> character codes for the % sign, and lots of other gyrations with no
> success. The only thing that works is if I modify searchterm first:
>searchterm = 'smith'
>searchterm ='%'+'smith'+'%'
>sql += 'WHERE name LIKE %s' % searchterm
> Any Ideas?
Let the DB-API do more work for you:
cursor = connection.cursor( )
sql = """SELECT column2, columns3 FROM table WHERE name LIKE %s"""
values = ('%%%s%%' % searchterm,) # note that this is a tuple
cursor.execute( sql, values )
HTH,
Dan
--
Dan Sommers
Re: string formatting using the % operator
Dan Sommers wrote:
> On Mon, 13 Jun 2005 15:12:54 GMT,
> William Gill <[EMAIL PROTECTED]> wrote:
>
>
>>I am using the % operator to create queries for a db app. It works fine
>>when exact strings, or numbers are used, but some queries need partial
>>matching that use the '%' as a wildcards. So for example the resultant
>>string should be 'WHERE name LIKE %smith%' (would match silversmith,
>>smithy, and smith). Is there any way to get something like
>
>
>> searchterm = 'smith'
>> sql += 'WHERE name LIKE %s' % searchterm
>
>
>>to return 'WHERE name LIKE %smith%'I have tried using escapes,
>>character codes for the % sign, and lots of other gyrations with no
>>success. The only thing that works is if I modify searchterm first:
>
>
>> searchterm = 'smith'
>> searchterm ='%'+'smith'+'%'
>> sql += 'WHERE name LIKE %s' % searchterm
>
>
>>Any Ideas?
>
>
> Let the DB-API do more work for you:
>
> cursor = connection.cursor( )
> sql = """SELECT column2, columns3 FROM table WHERE name LIKE %s"""
> values = ('%%%s%%' % searchterm,) # note that this is a tuple
> cursor.execute( sql, values )
>
> HTH,
> Dan
>
I can't tell you how many times I looked at the table of format codes
and missed this.
Thanks everyone!
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Re: string formatting using the % operator
Dan Sommers wrote:
> Let the DB-API do more work for you:
>
> cursor = connection.cursor( )
> sql = """SELECT column2, columns3 FROM table WHERE name LIKE %s"""
> values = ('%%%s%%' % searchterm,) # note that this is a tuple
It looks like this might be a rare case where not using the % operator
might make it easier to see what's going on:
values = ('%' + searchterm + '%',)
-Peter
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Re: String formatting with fixed width
Alexander Eisenhuth wrote: > Hello alltogether, > > is it possible to format stings with fixed width of let's say 7 character. T > need a floating point with 3 chars before dot, padded with ' ' and 3 chars > after > dot, padded with '0'. > > Followingh is my approach > >>> f = 21.1 > >>> s = "%.03f" % f > >>> s > '21.100' > > But there are missing ' '. How can I get that? (For bigger numbers than 999 > they > might be cut: 1021 -> 021) > >>> def f(x): ... return "%7.3f" % (x % 1000.0) ... >>> for x in (9.9, 99.9, 999.9, .9): ... print f(x) ... 9.900 99.900 999.900 999.900 >>> regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://del.icio.us/steve.holden Blog of Note: http://holdenweb.blogspot.com See you at PyCon? http://us.pycon.org/TX2007 -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting with fixed width
On 16 Mar, 13:20, Alexander Eisenhuth <[EMAIL PROTECTED]> wrote: > Hello alltogether, > > is it possible to format stings with fixed width of let's say 7 character. T > need a floating point with 3 chars before dot, padded with ' ' and 3 chars > after > dot, padded with '0'. > > Followingh is my approach > >>> f = 21.1 > >>> s = "%.03f" % f > >>> s > '21.100' > > But there are missing ' '. How can I get that? (For bigger numbers than 999 > they > might be cut: 1021 -> 021) You can use something like this: >> print '%7.03f' % 21.1 ' 21.100' However, this will only make the string at *least* 7 long. If the length of the number exceeds this, you'll end up with it even longer; for instance: >> print '%7.03f' % 2123123121.1 '2123123121.100' >From your example about 'cutting' it, it looks like you just might be able to take the last 7 chars from it using [-7:] hth Jon. -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting with fixed width
Steve Holden wrote: > Alexander Eisenhuth wrote: >> Hello alltogether, >> >> is it possible to format stings with fixed width of let's say 7 character. T >> need a floating point with 3 chars before dot, padded with ' ' and 3 chars >> after >> dot, padded with '0'. >> >> Followingh is my approach >> >>> f = 21.1 >> >>> s = "%.03f" % f >> >>> s >> '21.100' >> >> But there are missing ' '. How can I get that? (For bigger numbers than 999 >> they >> might be cut: 1021 -> 021) >> > >>> def f(x): > ... return "%7.3f" % (x % 1000.0) > ... > >>> for x in (9.9, 99.9, 999.9, .9): > ... print f(x) > ... >9.900 > 99.900 > 999.900 > 999.900 > >>> > ... but (unfortunately?): >>> f(-.99) ' 0.010' >>> You don't say what you want to do about negative numbers, so this may or may not be significant. regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://del.icio.us/steve.holden Blog of Note: http://holdenweb.blogspot.com See you at PyCon? http://us.pycon.org/TX2007 -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting with fixed width
Thanks for your fast reply. I'm fine with your "%7.03f" solution. (negatives are not significant) Alexander Eisenhuth schrieb: > Hello alltogether, > > is it possible to format stings with fixed width of let's say 7 > character. T need a floating point with 3 chars before dot, padded with > ' ' and 3 chars after dot, padded with '0'. > > Followingh is my approach > >>> f = 21.1 > >>> s = "%.03f" % f > >>> s > '21.100' > > But there are missing ' '. How can I get that? (For bigger numbers than > 999 they might be cut: 1021 -> 021) > > Thanks, > Alexander -- http://mail.python.org/mailman/listinfo/python-list
Re: String formatting with nested dictionaries
[EMAIL PROTECTED] schrieb:
> I've got a bit of code which has a dictionary nested within another
> dictionary. I'm trying to print out specific values from the inner
> dict in a formatted string and I'm running into a roadblock. I can't
> figure out how to get a value from the inner dict into the string. To
> make this even more complicated this is being compiled into a large
> string including other parts of the outer dict.
>
> mydict = {'inner_dict':{'Value1':1, 'Value2':2}, 'foo':'bar',
> 'Hammer':'nails'}
>
> print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
> and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to pound
> in %(Hammer)s" % mydict
>
> The above fails looking for a key named 'inner_dict['Value1']' which
> doesn't exist.
>
> I've looked through the docs and google and can't find anything
> relating to this.
Because it is not supported. You can only use one level of keys, and it
must be strings. So you have to do it like this:
print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to
poundin %(Hammer)s" % dict(Hammer=mydict['Hammer'],
Value1=mydict["inner_dict"]["Value1"],
Value2=mydict["inner_dict"]["Value2"])
Diez
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Re: String formatting with nested dictionaries
At Thursday 24/8/2006 13:22, [EMAIL PROTECTED] wrote:
I've got a bit of code which has a dictionary nested within another
dictionary. I'm trying to print out specific values from the inner
dict in a formatted string and I'm running into a roadblock. I can't
figure out how to get a value from the inner dict into the string. To
make this even more complicated this is being compiled into a large
string including other parts of the outer dict.
mydict = {'inner_dict':{'Value1':1, 'Value2':2}, 'foo':'bar',
'Hammer':'nails'}
print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to pound
in %(Hammer)s" % mydict
The above fails looking for a key named 'inner_dict['Value1']' which
doesn't exist.
I can think of two ways:
a) Flatten your dictionary. That is, move the contents of inner_dict
onto the outer dict:
mydict.update(mydict['inner_dict'])
Then use single names for interpolation
b) Do the interpolation in two steps.
template = "foo is set to %(foo)s - Value One is: %(Value1)s
and Value Two is: %(Value2)s -- Hammers are used to pound
in %(Hammer)s"
output = template % mydict['inner_dict']
output = output % mydict
Both methods assume that the inner dict takes precedence in case of
name clashes; reverse the order if you want the opposite.
Gabriel Genellina
Softlab SRL
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Re: String formatting with nested dictionaries
Gabriel Genellina wrote:
> At Thursday 24/8/2006 13:22, [EMAIL PROTECTED] wrote:
>
> >I've got a bit of code which has a dictionary nested within another
> >dictionary. I'm trying to print out specific values from the inner
> >dict in a formatted string and I'm running into a roadblock. I can't
> >figure out how to get a value from the inner dict into the string. To
> >make this even more complicated this is being compiled into a large
> >string including other parts of the outer dict.
> >
> >mydict = {'inner_dict':{'Value1':1, 'Value2':2}, 'foo':'bar',
> >'Hammer':'nails'}
> >
> >print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
> >and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to pound
> >in %(Hammer)s" % mydict
> >
> >The above fails looking for a key named 'inner_dict['Value1']' which
> >doesn't exist.
>
> I can think of two ways:
>
> a) Flatten your dictionary. That is, move the contents of inner_dict
> onto the outer dict:
> mydict.update(mydict['inner_dict'])
> Then use single names for interpolation
>
> b) Do the interpolation in two steps.
>
> template = "foo is set to %(foo)s - Value One is: %(Value1)s
> and Value Two is: %(Value2)s -- Hammers are used to pound
> in %(Hammer)s"
> output = template % mydict['inner_dict']
> output = output % mydict
>
> Both methods assume that the inner dict takes precedence in case of
> name clashes; reverse the order if you want the opposite.
>
>
> Gabriel Genellina
> Softlab SRL
>
Thanks, I started going with a) only doing it the long way.
(mydict['Value1'] = mydict['inner_dict']['Value1']) mydict.update() is
*much* simpler and less prone to errors too.
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Re: String formatting with nested dictionaries
[EMAIL PROTECTED] wrote:
> I've got a bit of code which has a dictionary nested within another
> dictionary. I'm trying to print out specific values from the inner
> dict in a formatted string and I'm running into a roadblock. I can't
> figure out how to get a value from the inner dict into the string. To
> make this even more complicated this is being compiled into a large
> string including other parts of the outer dict.
>
> mydict = {'inner_dict':{'Value1':1, 'Value2':2}, 'foo':'bar',
> 'Hammer':'nails'}
>
> print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
> and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to pound
> in %(Hammer)s" % mydict
>
> The above fails looking for a key named 'inner_dict['Value1']' which
> doesn't exist.
the % operator treats the keys as plain keys, not expressions. if you
trust the template provider, you can use a custom wrapper to evaluate
the key expressions:
mydict = {'inner_dict':{'Value1':1, 'Value2':2}, 'foo':'bar',
'Hammer':'nails'}
class wrapper:
def __init__(self, dict):
self.dict = dict
def __getitem__(self, key):
try:
return self.dict[key]
except KeyError:
return eval(key, self.dict)
print "foo is set to %(foo)s - Value One is: %(inner_dict['Value1'])s
and Value Two is: %(inner_dict['Value2'])s -- Hammers are used to pound
in %(Hammer)s" % wrapper(mydict)
foo is set to bar - Value One is: 1 and Value Two is: 2 -- Hammers are
used to pound in nails
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Re: String formatting with nested dictionaries
Le jeudi 24 août 2006 21:02, Fredrik Lundh a écrit :
> class wrapper:
> def __init__(self, dict):
> self.dict = dict
> def __getitem__(self, key):
> try:
> return self.dict[key]
> except KeyError:
>
Quite the same idea, but without eval and the need to know the internal dict
arborescence :
In [242]: class nested_dict_wrapper :
.: def __init__(self, dic) :
.: self._all = [dic] + [nested_dict_wrapper(v) for v in
dic.values() if isinstance(v, dict)]
.: def __getitem__(self, v) :
.: for i in self._all :
.: try : return i[v]
.: except KeyError: pass
.: raise KeyError(v + ' not found in dict and subdicts')
.:
.:
In [248]: complex_dict = { '0': 'zero', '1':'one', 'in1' : {'2':'two'}, 'in2':
{'3': 'three', '4' :'four', 'deeper':{'5':'five', '6':'six'}}, '7':'seven' }
In [250]: "%%(%s)s "*7 % tuple(range(7)) % nested_dict_wrapper(complex_dict)
Out[250]: 'zero one two three four five six '
In [251]: "%%(%s)s "*8 % tuple(range(8)) % nested_dict_wrapper(complex_dict)
Out[251]: 'zero one two three four five six seven '
In [252]: "%%(%s)s "*9 % tuple(range(9)) % nested_dict_wrapper(complex_dict)
---
exceptions.KeyError Traceback (most recent
call last)
/home/maric/
/home/maric/ in __getitem__(self, v)
KeyError: '8 not found in dict and subdicts'
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Maric Michaud
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Aristote - www.aristote.info
3 place des tapis
69004 Lyon
Tel: +33 426 880 097
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