Re: wxpython dialog - do something after ShowModal()?
On May 14, 9:37 pm, David C. Ullrich [EMAIL PROTECTED] wrote: In article [EMAIL PROTECTED], Iain King [EMAIL PROTECTED] wrote: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. dlg.ShowModal() onBrowse() obviously doesn't work, and neither does the reverse. I was hoping that the dialog would throw some kind of I have been shown event, but it doesn't (as far as I can tell). How do I make the dialog do something as soon as it's been shown? It's too bad that you found an answer. You _shouldn't_ have your dialog pop up a file-selection box as soon as it's shown! That's not the way dialogs usually work, so you're going to confuse people. Instead, first pop up the file-selection box, and then pop up the dialog (without the Browse button) to do whatever else it does after you've got the filename. That's actually what happens - the dialog throws EVT_INIT_DIALOG before it displays itself. Not that I really agree with you. I don't think that a do such-and-such dialog appearing with a Select file for such-and-such file selector on top of it, the file selector being in focus, is confusing for the user. Actually, I think it'd be friendlier - the user can see where the data from the file is going, so has an immediate reminder of what the (generic) file selector is for. -- http://mail.python.org/mailman/listinfo/python-list
Re: wxpython dialog - do something after ShowModal()?
In article [EMAIL PROTECTED], Iain King [EMAIL PROTECTED] wrote: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. dlg.ShowModal() onBrowse() obviously doesn't work, and neither does the reverse. I was hoping that the dialog would throw some kind of I have been shown event, but it doesn't (as far as I can tell). How do I make the dialog do something as soon as it's been shown? It's too bad that you found an answer. You _shouldn't_ have your dialog pop up a file-selection box as soon as it's shown! That's not the way dialogs usually work, so you're going to confuse people. Instead, first pop up the file-selection box, and then pop up the dialog (without the Browse button) to do whatever else it does after you've got the filename. Iain -- http://mail.python.org/mailman/listinfo/python-list
Re: wxpython dialog - do something after ShowModal()?
Iain King wrote: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. dlg.ShowModal() onBrowse() obviously doesn't work, and neither does the reverse. I was hoping that the dialog would throw some kind of I have been shown event, but it doesn't (as far as I can tell). How do I make the dialog do something as soon as it's been shown? Iain If the only things on your modal dialog are Browse and cancel, just call the wx.FileDialog directly and eliminate the intermediate modal dialog. If not don't bind the FileDialog to a button, just create an instance of it as the last you do in the __init__ method of the modal dialog code. If this doesn't help, you will have better luck posting to wxpython newsgroup. -Larry -- http://mail.python.org/mailman/listinfo/python-list
Re: wxpython dialog - do something after ShowModal()?
On May 13, 2:20 pm, Larry Bates [EMAIL PROTECTED] wrote: Iain King wrote: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. dlg.ShowModal() onBrowse() obviously doesn't work, and neither does the reverse. I was hoping that the dialog would throw some kind of I have been shown event, but it doesn't (as far as I can tell). How do I make the dialog do something as soon as it's been shown? Iain If the only things on your modal dialog are Browse and cancel, just call the wx.FileDialog directly and eliminate the intermediate modal dialog. If not don't bind the FileDialog to a button, just create an instance of it as the last you do in the __init__ method of the modal dialog code. If this doesn't help, you will have better luck posting to wxpython newsgroup. -Larry The dialog doesn't only let you call the file dialog, it does other stuff too. Your suggestion of __init__ sounded promising, but neither giving the dialog an __init__() method nor an OnInit() method worked. Thanks anyway. Iain -- http://mail.python.org/mailman/listinfo/python-list
Re: wxpython dialog - do something after ShowModal()?
On May 13, 2:43 pm, Iain King [EMAIL PROTECTED] wrote: On May 13, 2:20 pm, Larry Bates [EMAIL PROTECTED] wrote: Iain King wrote: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. dlg.ShowModal() onBrowse() obviously doesn't work, and neither does the reverse. I was hoping that the dialog would throw some kind of I have been shown event, but it doesn't (as far as I can tell). How do I make the dialog do something as soon as it's been shown? Iain If the only things on your modal dialog are Browse and cancel, just call the wx.FileDialog directly and eliminate the intermediate modal dialog. If not don't bind the FileDialog to a button, just create an instance of it as the last you do in the __init__ method of the modal dialog code. If this doesn't help, you will have better luck posting to wxpython newsgroup. -Larry The dialog doesn't only let you call the file dialog, it does other stuff too. Your suggestion of __init__ sounded promising, but neither giving the dialog an __init__() method nor an OnInit() method worked. Thanks anyway. Iain After having a hunt through the wxpython mailing list archives I found the answer: the event is EVT_INIT_DIALOG: dlg.Bind(wx.EVT_INIT_DIALOG, onInit, dlg) work. Thanks for the pointer. Iain -- http://mail.python.org/mailman/listinfo/python-list
Re: wxpython dialog - do something after ShowModal()?
En Tue, 13 May 2008 09:41:25 -0300, Iain King [EMAIL PROTECTED] escribió: Hi. I have a modal dialog whcih has a Browse... button which pops up a file selector. This all works fine, but the first thing the user has to do when they open the dialog is select a file, so I would like the dialog to automatically call the onBrowse function as soon as the dialog opens. However, I don't know how to do this. I've seen you already answered your question. But are you sure that doing this is a good thing? If you try to be too clever or too helpful the interfase may become annoying at some times. You can't guess the user's intention or read his mind. By example, what if I already have the desired file name copied in the clipboard? I don't want the file selector to pop up. I completely *hate* Windows programs with a Browse for folder button that don't let me paste a name, neither start opened at the currently selected folder. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
