Re: Regexp Neg. set of chars HowTo?
In <[EMAIL PROTECTED]>, durumdara
wrote:
> I found a solution my question in regexp way too:
> import re
> testtext = " minion battalion nation dion sion wion alion"
> m = re.compile("[^t^l]ion")
> print m.findall(testtext)
>
> I search for all text that not lion and tion.
And ^ion. The first ^ in that character group "negates" that group, the
second is a literal ^, so I guess you meant "[^tl]ion".
Ciao,
Marc 'BlackJack' Rintsch
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Re: Regexp Neg. set of chars HowTo?
Hi!
Thanks for this! I'll use that!
I found a solution my question in regexp way too:
import re
testtext = " minion battalion nation dion sion wion alion"
m = re.compile("[^t^l]ion")
print m.findall(testtext)
I search for all text that not lion and tion.
dd
Paul McGuire wrote:
> It looks like you are trying to de-hyphenate words that have been
> broken across line breaks.
>
> Well, this isn't a regexp solution, it uses pyparsing instead. But
> I've added a number of other test cases which may be problematic for an
> re.
>
> -- Paul
>
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Re: Regexp Neg. set of chars HowTo?
On Dec 20, 7:40 am, durumdara <[EMAIL PROTECTED]> wrote:
> Hi!
>
> I want to replace some seqs. in a html.
> Let:
> a-
> b
> = ab
>
> but:
> xxx -
> b
> must be unchanged, because it is not word split.
>
> I want to search and replace with re, but I don't know how to neg. this
> set ['\ \n\t'].
>
> This time I use full set without these chars, but neg. is better and
> shorter.
>
> Ok, I can use [^\s], but I want to know, how to neg. set of chars.
> sNorm1= '([^[\ \t\n]]{1})\-\\n' - this is not working.
>
> Thanks for the help:
> dd
>
> sNorm1= '([%s]{1})\-\\n'
> c = range(0, 256)
> c.remove(32)
> c.remove(13)
> c.remove(10)
> c.remove(9)
> s = ["\\%s" % (hex(v).replace('00x', '')) for v in c]
> sNorm1 = sNorm1 % ("".join(s))
> print sNorm1
>
> def Normalize(Text):
>
> rx = re.compile(sNorm1)
> def replacer(match):
> return match.group(1)
> return rx.sub(replacer, Text)
>
> print Normalize('a -\nb')
> print Normalize('a-\nb')
> sys.exit()
It looks like you are trying to de-hyphenate words that have been
broken across line breaks.
Well, this isn't a regexp solution, it uses pyparsing instead. But
I've added a number of other test cases which may be problematic for an
re.
-- Paul
from pyparsing import makeHTMLTags,Literal,Word,alphas,Suppress
brTag,brEndTag = makeHTMLTags("br")
hyphen = Literal("-")
hyphen.leaveWhitespace() # don't skip whitespace before matching this
collapse = Word(alphas) + Suppress(hyphen) + Suppress(brTag) \
+ Word(alphas)
# define action to replace expression with the word before hyphen
# concatenated with the word after the tag
collapse.setParseAction(lambda toks: toks[0]+toks[1])
print collapse.transformString('a -\nb')
print collapse.transformString('a-\nb')
print collapse.transformString('a-\nb')
print collapse.transformString('a-\nb')
print collapse.transformString('a- \nb')
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Regexp Neg. set of chars HowTo?
Hi!
I want to replace some seqs. in a html.
Let:
a-
b
= ab
but:
xxx -
b
must be unchanged, because it is not word split.
I want to search and replace with re, but I don't know how to neg. this
set ['\ \n\t'].
This time I use full set without these chars, but neg. is better and
shorter.
Ok, I can use [^\s], but I want to know, how to neg. set of chars.
sNorm1= '([^[\ \t\n]]{1})\-\\n' - this is not working.
Thanks for the help:
dd
sNorm1= '([%s]{1})\-\\n'
c = range(0, 256)
c.remove(32)
c.remove(13)
c.remove(10)
c.remove(9)
s = ["\\%s" % (hex(v).replace('00x', '')) for v in c]
sNorm1 = sNorm1 % ("".join(s))
print sNorm1
def Normalize(Text):
rx = re.compile(sNorm1)
def replacer(match):
return match.group(1)
return rx.sub(replacer, Text)
print Normalize('a -\nb')
print Normalize('a-\nb')
sys.exit()
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