Re: Regexp Neg. set of chars HowTo?
Hi! Thanks for this! I'll use that! I found a solution my question in regexp way too: import re testtext = minion battalion nation dion sion wion alion m = re.compile([^t^l]ion) print m.findall(testtext) I search for all text that not lion and tion. dd Paul McGuire wrote: It looks like you are trying to de-hyphenate words that have been broken across line breaks. Well, this isn't a regexp solution, it uses pyparsing instead. But I've added a number of other test cases which may be problematic for an re. -- Paul -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp Neg. set of chars HowTo?
In [EMAIL PROTECTED], durumdara wrote: I found a solution my question in regexp way too: import re testtext = minion battalion nation dion sion wion alion m = re.compile([^t^l]ion) print m.findall(testtext) I search for all text that not lion and tion. And ^ion. The first ^ in that character group negates that group, the second is a literal ^, so I guess you meant [^tl]ion. Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp Neg. set of chars HowTo?
On Dec 20, 7:40 am, durumdara [EMAIL PROTECTED] wrote:
Hi!
I want to replace some seqs. in a html.
Let:
a-
b
= ab
but:
xxx -
b
must be unchanged, because it is not word split.
I want to search and replace with re, but I don't know how to neg. this
set ['\ \n\t'].
This time I use full set without these chars, but neg. is better and
shorter.
Ok, I can use [^\s], but I want to know, how to neg. set of chars.
sNorm1= '([^[\ \t\n]]{1})\-\br\ \/\\n' - this is not working.
Thanks for the help:
dd
sNorm1= '([%s]{1})\-\br\ \/\\n'
c = range(0, 256)
c.remove(32)
c.remove(13)
c.remove(10)
c.remove(9)
s = [\\%s % (hex(v).replace('00x', '')) for v in c]
sNorm1 = sNorm1 % (.join(s))
print sNorm1
def Normalize(Text):
rx = re.compile(sNorm1)
def replacer(match):
return match.group(1)
return rx.sub(replacer, Text)
print Normalize('a -br /\nb')
print Normalize('a-br /\nb')
sys.exit()
It looks like you are trying to de-hyphenate words that have been
broken across line breaks.
Well, this isn't a regexp solution, it uses pyparsing instead. But
I've added a number of other test cases which may be problematic for an
re.
-- Paul
from pyparsing import makeHTMLTags,Literal,Word,alphas,Suppress
brTag,brEndTag = makeHTMLTags(br)
hyphen = Literal(-)
hyphen.leaveWhitespace() # don't skip whitespace before matching this
collapse = Word(alphas) + Suppress(hyphen) + Suppress(brTag) \
+ Word(alphas)
# define action to replace expression with the word before hyphen
# concatenated with the word after the BR tag
collapse.setParseAction(lambda toks: toks[0]+toks[1])
print collapse.transformString('a -br /\nb')
print collapse.transformString('a-br /\nb')
print collapse.transformString('a-br/\nb')
print collapse.transformString('a-br\nb')
print collapse.transformString('a- BR clear=all\nb')
--
http://mail.python.org/mailman/listinfo/python-list
Regexp Neg. set of chars HowTo?
Hi!
I want to replace some seqs. in a html.
Let:
a-
b
= ab
but:
xxx -
b
must be unchanged, because it is not word split.
I want to search and replace with re, but I don't know how to neg. this
set ['\ \n\t'].
This time I use full set without these chars, but neg. is better and
shorter.
Ok, I can use [^\s], but I want to know, how to neg. set of chars.
sNorm1= '([^[\ \t\n]]{1})\-\br\ \/\\n' - this is not working.
Thanks for the help:
dd
sNorm1= '([%s]{1})\-\br\ \/\\n'
c = range(0, 256)
c.remove(32)
c.remove(13)
c.remove(10)
c.remove(9)
s = [\\%s % (hex(v).replace('00x', '')) for v in c]
sNorm1 = sNorm1 % (.join(s))
print sNorm1
def Normalize(Text):
rx = re.compile(sNorm1)
def replacer(match):
return match.group(1)
return rx.sub(replacer, Text)
print Normalize('a -br /\nb')
print Normalize('a-br /\nb')
sys.exit()
--
http://mail.python.org/mailman/listinfo/python-list
