Re: Slicing Arrays in this way
John Machin wrote: > On May 3, 8:55 am, Steven D'Aprano > <[EMAIL PROTECTED]> wrote: >> On Wed, 02 May 2007 15:03:24 -0700, Tobiah wrote: >> >>> >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) >>> [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] >> Wow! That's impressive. What version of Python are you using? When I try >> it, I get this: >> > elegant_solution([1,2,3,4,5,6,7,8,9,10]) >> Traceback (most recent call last): >> File "", line 1, in >> NameError: name 'elegant_solution' is not defined >> > > The OP has already confessed. Don't rub it in. > Well, my first post made perfect sense. My 'confession' involved noticing that I had replied to one respondent saying that I wanted something more concise, while praising the aptness of the same solution to the next poster. Lack of oxygen, I think. -- Posted via a free Usenet account from http://www.teranews.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
John Machin wrote: > On May 3, 10:21 am, Michael Hoffman <[EMAIL PROTECTED]> wrote: >> Tobiah wrote: >> >>> >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) >>> [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] >> That's not an array, it's a list. See the array module for arrays >> (fixed-length, unlike variable-length lists). > > You must have your very own definitions of "fixed-length" and > "unlike". Sorry, too much time spent with numarray arrays which are documented to have immutable size. -- Michael Hoffman -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On Wed, 02 May 2007 16:01:05 -0700, John Machin wrote: > The OP has already confessed. Don't rub it in. Sorry, I sent my comment before I received his confession. -- Steven D'Aprano -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
Tobiah wrote: > > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] > > Here's one I use: def elegant_solution(alist): i = iter(alist) return [[j, i.next()] for j in i] py> elegant_solution(range(14)) [[0, 1], [2, 3], [4, 5], [6, 7], [8, 9], [10, 11], [12, 13]] James -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On May 3, 10:21 am, Michael Hoffman <[EMAIL PROTECTED]> wrote:
> Tobiah wrote:
>
> > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10])
> > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]]
>
> That's not an array, it's a list. See the array module for arrays
> (fixed-length, unlike variable-length lists).
You must have your very own definitions of "fixed-length" and
"unlike".
>>> import array
>>> fixed = array.array('b')
>>> fixed.append(42)
>>> fixed.extend([0, 1, 127])
>>> fixed
array('b', [42, 0, 1, 127])
>>> fixed.append(2)
>>> fixed
array('b', [42, 0, 1, 127, 2])
>>> fixed[2:4] = array.array('b', [8])
>>> fixed
array('b', [42, 0, 8, 2])
>>>
--
http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
Tobiah wrote: > > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] That's not an array, it's a list. See the array module for arrays (fixed-length, unlike variable-length lists). -- Michael Hoffman -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
Yeah, having an elegant_solution() function would solve soo many of my problems. ;) Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On May 3, 8:55 am, Steven D'Aprano <[EMAIL PROTECTED]> wrote: > On Wed, 02 May 2007 15:03:24 -0700, Tobiah wrote: > > > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] > > Wow! That's impressive. What version of Python are you using? When I try > it, I get this: > > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > > Traceback (most recent call last): > File "", line 1, in > NameError: name 'elegant_solution' is not defined > The OP has already confessed. Don't rub it in. -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On Wed, 02 May 2007 15:03:24 -0700, Tobiah wrote: > > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] Wow! That's impressive. What version of Python are you using? When I try it, I get this: >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) Traceback (most recent call last): File "", line 1, in NameError: name 'elegant_solution' is not defined -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
I'm a retard. Disregard. -- Posted via a free Usenet account from http://www.teranews.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
John Machin wrote: > On May 3, 8:03 am, Tobiah <[EMAIL PROTECTED]> wrote: >> >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) >> [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] >> > > What is your definition of "elegant"? What about other dimensions of > code quality like "robust" and "fast"? > > What have you tried? > > Here's one possibility: > zip(source[::2], source[1::2]) > [I'm presuming you won't be upset by getting tuples instead of lists] I like it, and it fits my definition of elegant. -- Posted via a free Usenet account from http://www.teranews.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
Matimus wrote: > On May 2, 3:03 pm, Tobiah <[EMAIL PROTECTED]> wrote: >> >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) >> [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] >> >> -- >> Posted via a free Usenet account fromhttp://www.teranews.com > seq = range(1,11) seq > [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] zip( seq[0::2],seq[1::2] ) > [(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)] > > if you _really_ need lists then... map(list, zip( seq[0::2],seq[1::2] )) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] > I had come up with: [[a[x], a[x + 1]] for x in range(0, 10, 2)] I was hoping for something a little more concise. Something like list[::2:2] if that existed. -- Posted via a free Usenet account from http://www.teranews.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On May 3, 8:03 am, Tobiah <[EMAIL PROTECTED]> wrote: > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] > What is your definition of "elegant"? What about other dimensions of code quality like "robust" and "fast"? What have you tried? Here's one possibility: zip(source[::2], source[1::2]) [I'm presuming you won't be upset by getting tuples instead of lists] -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
On May 2, 3:03 pm, Tobiah <[EMAIL PROTECTED]> wrote: > >>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) > [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] > > -- > Posted via a free Usenet account fromhttp://www.teranews.com >>> seq = range(1,11) >>> seq [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] >>> zip( seq[0::2],seq[1::2] ) [(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)] if you _really_ need lists then... >>> map(list, zip( seq[0::2],seq[1::2] )) [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] -- http://mail.python.org/mailman/listinfo/python-list
Slicing Arrays in this way
>>> elegant_solution([1,2,3,4,5,6,7,8,9,10]) [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] -- Posted via a free Usenet account from http://www.teranews.com -- http://mail.python.org/mailman/listinfo/python-list
