Re: Stringified list back to list of ints
On Wed, 12 Dec 2007 10:38:56 -0500, Calvin Spealman wrote: > I still hold my vote that if you need to reverse the "stringification" > of a list, you shouldn't have stringified the list and lost hold of the > original list in the first place. That is the solution above all others. Naturally, but it isn't always an option. Perhaps the list was read from a human-writable config file or something. It's a non-starter to expect people to write a list of ints in Python's native binary format -- and you still have the problem of how do you get those bytes from the file into Python's virtual machine and correctly bound to a name. -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
Re: Stringified list back to list of ints
Another solution, possibly safer: >>> from cStringIO import StringIO >>> import csv >>> s = "[16, 16, 2, 16, 2, 16, 8, 16]" >>> sf = StringIO(s.strip()[1:-1]) >>> list(csv.reader(sf)) [['16', ' 16', ' 2', ' 16', ' 2', ' 16', ' 8', ' 16']] Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list
Re: Stringified list back to list of ints
I still hold my vote that if you need to reverse the
"stringification" of a list, you shouldn't have stringified the list
and lost hold of the original list in the first place. That is the
solution above all others.
On Dec 12, 2007, at 10:26 AM, Paul McGuire wrote:
> On Dec 12, 7:25 am, Lee Capps <[EMAIL PROTECTED]> wrote:
>> Regular expressions might be a good way to handle this.
>>
>> import re
>>
>> s = '[16, 16, 2, 16, 2, 16, 8, 16]'
>> get_numbers = re.compile('\d\d*').findall
>>
>> numbers = [int(x) for x in get_numbers(s)]
>>
>
> Isn't '\d\d*' the same as '\d+' ?
>
> And why would you invoke re's when str.split(',') (after stripping
> leading and trailing []'s) does the job so well?
>
> numbers = map(int, s.strip('[]').split(','))
>
> Or if map is not to your liking:
>
> numbers = [int(x) for x in s.strip('[]').split(',')]
>
> -- Paul
> --
> http://mail.python.org/mailman/listinfo/python-list
--
http://mail.python.org/mailman/listinfo/python-list
Stringified list back to list of ints
On Dec 12, 7:25 am, Lee Capps <[EMAIL PROTECTED]> wrote:
> Regular expressions might be a good way to handle this.
>
> import re
>
> s = '[16, 16, 2, 16, 2, 16, 8, 16]'
> get_numbers = re.compile('\d\d*').findall
>
> numbers = [int(x) for x in get_numbers(s)]
>
Isn't '\d\d*' the same as '\d+' ?
And why would you invoke re's when str.split(',') (after stripping
leading and trailing []'s) does the job so well?
numbers = map(int, s.strip('[]').split(','))
Or if map is not to your liking:
numbers = [int(x) for x in s.strip('[]').split(',')]
-- Paul
--
http://mail.python.org/mailman/listinfo/python-list
