Why this code works in python3, but not python 2:
Out of curiosity: Does anyone know why the code below is valid in python3, but not python2: def foo(*args, bar=1, **kwargs): pass -- Maciej Dziardziel -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On 4/07/2013 1:52 PM, Maciej Dziardziel wrote: Out of curiosity: Does anyone know why the code below is valid in python3, but not python2: def foo(*args, bar=1, **kwargs): pass It was an explicit syntax change for Python3. You can read about the reasoning behind it here: http://www.python.org/dev/peps/pep-3102/ -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On Thu, Jul 4, 2013 at 1:52 PM, Maciej Dziardziel fied...@gmail.com wrote: Out of curiosity: Does anyone know why the code below is valid in python3, but not python2: def foo(*args, bar=1, **kwargs): pass Keyword-only arguments are (IIRC) a Py3-only feature. There are lots of features that don't work in Python 2 - that's simply the way things happen with old versions of software. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On 4 July 2013 04:52, Maciej Dziardziel fied...@gmail.com wrote: Out of curiosity: Does anyone know why the code below is valid in python3, but not python2: def foo(*args, bar=1, **kwargs): pass Python 3 gained syntax for keyword-only arguments. Try foo(1) and it will fail -- bar needs to be given as a keyword. This is because it comes after a *-expression. You can also do def foo(*, bar=1) if you want bar to be keyword-only without accepting any number of positional arguments. Python 2 does not have these, and doesn't understand the syntax for them. -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On Thursday, July 4, 2013 5:05:23 AM UTC+1, alex23 wrote: It was an explicit syntax change for Python3. You can read about the reasoning behind it here: http://www.python.org/dev/peps/pep-3102/ Thanks, that was helpful. Maciej Dziardziel -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On 4/07/2013 2:12 PM, Joshua Landau wrote: On 4 July 2013 04:52, Maciej Dziardziel fied...@gmail.com wrote: def foo(*args, bar=1, **kwargs): pass Try foo(1) and it will fail -- bar needs to be given as a keyword. No it won't, because it is supplied with a default. You may be confusing it with the requirement that `bar` must be given as a keyword in order for it to override the default, compared to the way this would need to be written in Py2: def foo(bar=1, *args, **kwargs): ... ...in which case `bar` could be assigned to by the first positional argument. -- http://mail.python.org/mailman/listinfo/python-list
Re: Why this code works in python3, but not python 2:
On 4 July 2013 05:47, alex23 wuwe...@gmail.com wrote: On 4/07/2013 2:12 PM, Joshua Landau wrote: On 4 July 2013 04:52, Maciej Dziardziel fied...@gmail.com wrote: def foo(*args, bar=1, **kwargs): pass Try foo(1) and it will fail -- bar needs to be given as a keyword. No it won't, because it is supplied with a default. Pah! I'm not even thinking. -- http://mail.python.org/mailman/listinfo/python-list
