a question about s[i:j] when i is negative
s[i:j] slice of s from i to j (3), (4) (3) If i or j is negative, the index is relative to the end of the string: len(s) + i or len(s) + j is substituted. But note that -0 is still 0. (4) The slice of s from i to j is defined as the sequence of items with index k such that i = k j. If i or j is greater than len(s), use len(s). If i is omitted or None, use 0. If j is omitted or None, use len(s). If i is greater than or equal to j, the slice is empty. i can't follow (3) very well. for example:k = [1,2,3,4,5] k[-1:2]=[] k[-5:2]=[1,2] but k[-6:2] = [1,2] why k[-6:2] is [1,2]not [].i do follow (3),to make i positive by plusing len(k) twice.But the result is not what i expect.why,or did i misunderstand the rule of (3). -- http://mail.python.org/mailman/listinfo/python-list
Re: a question about s[i:j] when i is negative
dracula571 wrote: but k[-6:2] = [1,2] why k[-6:2] is [1,2]not [].i do follow (3),to make i positive by plusing len(k) twice. twice? /F -- http://mail.python.org/mailman/listinfo/python-list
Re: a question about s[i:j] when i is negative
dracula571 wrote: s[i:j] slice of s from i to j (3), (4) (3) If i or j is negative, the index is relative to the end of the string: len(s) + i or len(s) + j is substituted. But note that -0 is still 0. (4) The slice of s from i to j is defined as the sequence of items with index k such that i = k j. If i or j is greater than len(s), use len(s). If i is omitted or None, use 0. If j is omitted or None, use len(s). If i is greater than or equal to j, the slice is empty. i can't follow (3) very well. for example:k = [1,2,3,4,5] k[-1:2]=[] k[-5:2]=[1,2] but k[-6:2] = [1,2] why k[-6:2] is [1,2]not []. Because 6 is greater then len(k), so when you ask for i=-6, you get i=-5 instead. And relative -5 is actually absolute 0 which is less than 2, so you do not get an empty slice. i do follow (3),to make i positive by plusing len(k) twice.But the result is not what i expect.why,or did i misunderstand the rule of (3). See (4). -- http://mail.python.org/mailman/listinfo/python-list
Re: a question about s[i:j] when i is negative
Fredrik Lundh 写道： dracula571 wrote: but k[-6:2] = [1,2] why k[-6:2] is [1,2]not [].i do follow (3),to make i positive by plusing len(k) twice. twice? /F that is -6 + len(k) + len(k) =4 -- http://mail.python.org/mailman/listinfo/python-list
Re: a question about s[i:j] when i is negative
[EMAIL PROTECTED] 写道： dracula571 wrote: s[i:j] slice of s from i to j (3), (4) (3) If i or j is negative, the index is relative to the end of the string: len(s) + i or len(s) + j is substituted. But note that -0 is still 0. (4) The slice of s from i to j is defined as the sequence of items with index k such that i = k j. If i or j is greater than len(s), use len(s). If i is omitted or None, use 0. If j is omitted or None, use len(s). If i is greater than or equal to j, the slice is empty. i can't follow (3) very well. for example:k = [1,2,3,4,5] k[-1:2]=[] k[-5:2]=[1,2] but k[-6:2] = [1,2] why k[-6:2] is [1,2]not []. Because 6 is greater then len(k), so when you ask for i=-6, you get i=-5 instead. And relative -5 is actually absolute 0 which is less than 2, so you do not get an empty slice. i do follow (3),to make i positive by plusing len(k) twice.But the result is not what i expect.why,or did i misunderstand the rule of (3). See (4). when compared with len(k), the value of i is a absolute value? in this example,i used -6 to compare with len(k). I misunstood the rule (4),and used (3) wrong by plusing len(k) twice to make it positive ,that is -6 + len(k) + len(k) = 4. Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: a question about s[i:j] when i is negative
dracula571 wrote: dracula571 wrote: but k[-6:2] = [1,2] why k[-6:2] is [1,2]not [].i do follow (3),to make i positive by plusing len(k) twice. twice? that is -6 + len(k) + len(k) =4 sure, but what makes you think you should add the length twice? /F -- http://mail.python.org/mailman/listinfo/python-list
