Re: a short-cut command for globals().clear() ??
MRAB wrote: How about something like this: def clear_workspace(): keep_set = set(['__builtins__', '__doc__', '__name__', 'clear_workspace']) For 2.6/3.0, add __package__ to the list to be kept. for x in globals().keys(): if x not in keep_set: del globals()[x] -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
Terry Reedy wrote: MRAB wrote: How about something like this: def clear_workspace(): keep_set = set(['__builtins__', '__doc__', '__name__', 'clear_workspace']) For 2.6/3.0, add __package__ to the list to be kept. for x in globals().keys(): if x not in keep_set: del globals()[x] Or... you might have a script clearWorkspace.py : - initGlobals = globals().keys() def clearWorkspace() : for gVar in globals().keys() : if gVar not in initGlobals : del globals()[gVar] - Which you run before doing anything else. Then you don't mind if additions were made to the list to keep, or if you are using something like pyCrust which has its own initial globals, or if you want to keep some global vars of your own (in which case you run clearWorkspace AFTER you instantiate your global vars). -- http://mail.python.org/mailman/listinfo/python-list
a short-cut command for globals().clear() ??
hi all, forgive me , but the RTFM and Google search approaches are not yielding an answer on this question. I need to know if there's a top level python interpreter command that clears all user variables (not built-ins) from the global namespace. In other words a statement, or some_command_or_function(), that does this: x=3 y=4 z=[] dir() ['__builtins__', '__doc__', '__name__', 'x', 'y', 'z'] some_command_or_function() dir() ['__builtins__', '__doc__', '__name__'] thanks, 1 desperate snake oil programmer -- http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
On Sep 22, 2:31 pm, [EMAIL PROTECTED] wrote: hi all, forgive me , but the RTFM and Google search approaches are not yielding an answer on this question. I need to know if there's a top level python interpreter command that clears all user variables (not built-ins) from the global namespace. In other words a statement, or some_command_or_function(), that does this: x=3 y=4 z=[] dir() ['__builtins__', '__doc__', '__name__', 'x', 'y', 'z'] some_command_or_function() dir() ['__builtins__', '__doc__', '__name__'] thanks, 1 desperate snake oil programmer I don't think you will find anything. The interpreter is essentially the same whether you are in interactive mode or not. That is, there is very little use for a method that clears globals in general, so why would we add it just so that it could be used by the interpreter. There is almost* nothing available to the interactive interpreter which isn't part of the core language. * The only difference I can think of is the _ variable, which is added to __builtins__ and contains the last value returned in interactive mode. If you have ever tried to run code that uses the locale module from the interpreter you will see why having any differences between the interactive and non-interactive interpreter can be a pain. Matt -- http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
On Sep 22, 5:52 pm, Matimus [EMAIL PROTECTED] wrote: On Sep 22, 2:31 pm, [EMAIL PROTECTED] wrote: hi all, forgive me , but the RTFM and Google search approaches are not yielding an answer on this question. I need to know if there's a top level python interpreter command that clears all user variables (not built-ins) from the global namespace. In other words a statement, or some_command_or_function(), that does this: x=3 y=4 z=[] dir() ['__builtins__', '__doc__', '__name__', 'x', 'y', 'z'] some_command_or_function() dir() ['__builtins__', '__doc__', '__name__'] thanks, 1 desperate snake oil programmer I don't think you will find anything. The interpreter is essentially the same whether you are in interactive mode or not. That is, there is very little use for a method that clears globals in general, so why would we add it just so that it could be used by the interpreter. There is almost* nothing available to the interactive interpreter which isn't part of the core language. * The only difference I can think of is the _ variable, which is added to __builtins__ and contains the last value returned in interactive mode. If you have ever tried to run code that uses the locale module from the interpreter you will see why having any differences between the interactive and non-interactive interpreter can be a pain. Matt ok. thanks! guess i'll be off to define my own function ... -- http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
[EMAIL PROTECTED] wrote: forgive me , but the RTFM and Google search approaches are not yielding an answer on this question. I need to know if there's a top level python interpreter command that clears all user variables (not built-ins) from the global namespace. In other words a statement, or some_command_or_function(), that does this: x=3 y=4 z=[] dir() ['__builtins__', '__doc__', '__name__', 'x', 'y', 'z'] some_command_or_function() dir() ['__builtins__', '__doc__', '__name__'] First, a WARNING to other readers deceived by the subject line. Globals().clear() clears everything and leaves nothing, so Capn... is looking for something that works that is a shortcut for deleting bindings one-by-one. To your question. The short answer is no. In batch mode, only create what you need and delete (unbind) large objects that are not automatically deleted (unbound) when you are done with them. Remember that only reference-counted implementations will guarantee immediate destruction and space-freeing when the last reference goes away. Check the gc module (and some posts in the archives) for more specialized control. In interactive mode, restart the interpreter if you really need a clean slate and have too many bindings that you must delete to do something quick like 'del x,y,z' as in your example above. In IDLE, cntl-F6 restarts the shell with a clean slate. I presume IPython has something similar. tjr -- http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
On Sep 22, 5:44 pm, Terry Reedy [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] wrote:
forgive me , but the RTFM and Google search approaches are not
yielding an answer on this question. I need to know if there's a top
level python interpreter command that clears all user variables (not
built-ins) from the global namespace. In other words a statement, or
some_command_or_function(), that does this:
x=3
y=4
z=[]
dir()
['__builtins__', '__doc__', '__name__', 'x', 'y', 'z']
some_command_or_function()
dir()
['__builtins__', '__doc__', '__name__']
First, a WARNING to other readers deceived by the subject line.
Globals().clear() clears everything and leaves nothing, so Capn... is
looking for something that works that is a shortcut for deleting
bindings one-by-one.
To your question. The short answer is no.
In batch mode, only create what you need and delete (unbind) large
objects that are not automatically deleted (unbound) when you are done
with them. Remember that only reference-counted implementations will
guarantee immediate destruction and space-freeing when the last
reference goes away. Check the gc module (and some posts in the
archives) for more specialized control.
In interactive mode, restart the interpreter if you really need a clean
slate and have too many bindings that you must delete to do something
quick like 'del x,y,z' as in your example above. In IDLE, cntl-F6
restarts the shell with a clean slate. I presume IPython has something
similar.
tjr
I guess you have a few hackish options.
1) Define a wrapper that calls its argument immediately, and use it as
you would use anonymous blocks.
@call_imm
def block( ):
code
code
code
@call_imm
def block( ):
code
code
code
You have no globals when you are done.
2) If you need them to be global, use some introspection, and delete
the variables upon exiting the scope.
3) Declare all your variables in a namespace, and just delete the
namespace.
a= type('blank',(),{})()
a.varA= 0
a.varB= 'abc'
del a
--
http://mail.python.org/mailman/listinfo/python-list
Re: a short-cut command for globals().clear() ??
On Sep 22, 11:07 pm, [EMAIL PROTECTED] wrote: On Sep 22, 5:52 pm, Matimus [EMAIL PROTECTED] wrote: On Sep 22, 2:31 pm, [EMAIL PROTECTED] wrote: hi all, forgive me , but the RTFM and Google search approaches are not yielding an answer on this question. I need to know if there's a top level python interpreter command that clears all user variables (not built-ins) from the global namespace. In other words a statement, or some_command_or_function(), that does this: x=3 y=4 z=[] dir() ['__builtins__', '__doc__', '__name__', 'x', 'y', 'z'] some_command_or_function() dir() ['__builtins__', '__doc__', '__name__'] thanks, 1 desperate snake oil programmer I don't think you will find anything. The interpreter is essentially the same whether you are in interactive mode or not. That is, there is very little use for a method that clears globals in general, so why would we add it just so that it could be used by the interpreter. There is almost* nothing available to the interactive interpreter which isn't part of the core language. * The only difference I can think of is the _ variable, which is added to __builtins__ and contains the last value returned in interactive mode. If you have ever tried to run code that uses the locale module from the interpreter you will see why having any differences between the interactive and non-interactive interpreter can be a pain. Matt ok. thanks! guess i'll be off to define my own function ... How about something like this: def clear_workspace(): keep_set = set(['__builtins__', '__doc__', '__name__', 'clear_workspace']) for x in globals().keys(): if x not in keep_set: del globals()[x] -- http://mail.python.org/mailman/listinfo/python-list
